Behind the scenes in the computer's memory, color is always talked about as a series of 24 bits of information for each pixel. In an image, the color with the largest proportional area is called the dominant color. A strictly dominant color takes more than half of the total area. Now given an image of resolution M by N (for example, 8), you are supposed to point out the strictly dominant color.

Input Specification:

Each input file contains one test case. For each case, the first line contains 2 positive numbers: M (≤) and N (≤) which are the resolutions of the image. Then N lines follow, each contains M digital colors in the range [0). It is guaranteed that the strictly dominant color exists for each input image. All the numbers in a line are separated by a space.

Output Specification:

For each test case, simply print the dominant color in a line.

Sample Input:

5 3
0 0 255 16777215 24
24 24 0 0 24
24 0 24 24 24

Sample Output:

24

思路:初始化tmp为0,cnt为0,每次输入一个数与tmp比较如果相同cnt++,否则更新tmp值,因为题意是所求的值总会超过一半数据,所以最后留下来的tmp一定就是目标值。
 #include <stdio.h>
int n,m;
int a[][];
int main()
{
scanf("%d %d",&m,&n);
int tmp=,cnt=;
for(int i=;i<n;i++){
for(int j=;j<m;j++){
scanf("%d",&a[i][j]);
if(a[i][j]==tmp){
cnt++;
}else{
tmp=a[i][j];
cnt=;
}
}
}
printf("%d\n",tmp);
return ;
}

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