求一个生成树,使得最大边权和最小边权之差最小。由于数据太小,暴力枚举下界,求出相应的上界。最后取min即可。

 #include<cstdio>
#include<algorithm>
#include<cstring>
using namespace std;
int n,m,fa[],rank[];
void clear(){for(int i=;i<=n;i++) fa[i]=i; memset(rank,,sizeof(rank));}
int findroot(int x)
{
if(fa[x]==x) return x;
int rt=findroot(fa[x]);
fa[x]=rt;
return rt;
}
void Union(int U,int V)
{
if(rank[U]<rank[V]) fa[U]=V;
else
{
fa[V]=U;
if(rank[U]==rank[V]) rank[U]++;
}
}
struct Edge{int u,v,w;};
bool cmp(const Edge &a,const Edge &b){return a.w<b.w;}
Edge edges[];
int tot,ans,maxv;
int main()
{
while()
{
scanf("%d%d",&n,&m);
if(!n) break;
for(int i=;i<=m;i++) scanf("%d%d%d",&edges[i].u,&edges[i].v,&edges[i].w);
sort(edges+,edges+m+,cmp); ans=;
for(int j=;j<=m;j++)
{
tot=; clear();
for(int i=j;i<=m;i++)
{
int f1=findroot(edges[i].u),f2=findroot(edges[i].v);
if(f1!=f2) {Union(f1,f2); tot++; if(tot==n-) {maxv=edges[i].w; goto WIN;}}
}
continue;
WIN:ans=min(ans,maxv-edges[j].w);
}
printf("%d\n",ans!= ? ans : -);
}
return ;
}

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