2013 US Open Award Ceremoney
http://v.youku.com/v_show/id_XNjA3MjU3MzY4.html?firsttime=0
Singapore how about another hand trophy Ceremoney it's y pleaure to introduce the Chairman this match and two weeks
spectacular here at US Open around the world, thanks to all you two do , most importantly , I'd like to thank the fans, for the six year ad attendants Thank you
we couldn't do wihout you. Thank you very much . Novak Djokovic. Novak, you two played so many remarkable match this year
on a couple of , tell us what is Spainard
Thanks good questions
obviously I want congradulate definetely deserved to win this match today and this trophy. Now obviously dispointed this way one of the most valuable next year and thanks you all the guys for all your supporting.
Now on behalf of runer-up trophy, now champion Rafael Nadal. Rafael a lot of notice you are leaving here last year, how was your feeling tonight? very very emotional , probably all my team knows how much means to me against Novak is always is very special eeling like congradulation Novak,you are amazn player you are having an amazing career and I'm sure one f the best of the history
you are already are. Rafael Nadal
first two point six million dollar president and CEO USA. And Rafa in addtion to wining US Open today , you also finish summer that means to your winning today as did Serena last night in additional three pint six million dollars , congradulation we will hand you the throphy.
Ladies and gentlemen , for the second time , the US Open Champion Rafael Nadal. Well, we will see more terific match coming the third meeting
2013 US Open Award Ceremoney的更多相关文章
- 美国政府关于Google公司2013年度的财务报表红头文件
请管理员移至新闻版块,谢谢! 来源:http://www.sec.gov/ 财务报表下载↓ 此文仅作参考分析. 10-K 1 goog2013123110-k.htm FORM 10-K UNIT ...
- 历届图灵奖 (Turing award)得奖名单
历届图灵奖 (Turing award)得奖名单 一.总结 一句话总结:各个方面都有. 二.历届图灵奖 (Turing award)得奖名单 Turing奖最早设立于1966年,是美国计算机协会在计算 ...
- 信息检索盛会 微软“领衔主演”——记ACM SIGIR 2013信息检索国际会议
微软"领衔主演"--记ACM SIGIR 2013信息检索国际会议" title="信息检索盛会 微软"领衔主演"--记ACM SIGIR ...
- 微软科学家Leslie Lamport荣获2013年图灵奖
Lamport荣获2013年图灵奖" title="微软科学家Leslie Lamport荣获2013年图灵奖"> 编者按:Leslie Lamport,新晋图灵奖 ...
- 2013 Asia Changsha Regional Contest---Josephina and RPG(DP)
题目链接 http://acm.hdu.edu.cn/showproblem.php?pid=4800 Problem Description A role-playing game (RPG and ...
- SharePoint 2013: A feature with ID has already been installed in this farm
使用Visual Studio 2013创建一个可视web 部件,当右击项目选择"部署"时报错: "Error occurred in deployment step ' ...
- Visual Studio 2013 添加一般应用程序(.ashx)文件到SharePoint项目
默认,在用vs2013开发SharePoint项目时,vs没有提供一般应用程序(.ashx)的项目模板,本文解决此问题. 以管理员身份启动vs2013,创建一个"SharePoint 201 ...
- SharePoint 2013 create workflow by SharePoint Designer 2013
这篇文章主要基于上一篇http://www.cnblogs.com/qindy/p/6242714.html的基础上,create a sample workflow by SharePoint De ...
- Install and Configure SharePoint 2013 Workflow
这篇文章主要briefly introduce the Install and configure SharePoint 2013 Workflow. Microsoft 推出了新的Workflow ...
随机推荐
- 修复duilib CEditUI控件和CWebBrowserUI控件中按Tab键无法切换焦点的bug
转载请说明原出处,谢谢~~:http://blog.csdn.net/zhuhongshu/article/details/41556615 在duilib中,按tab键会让焦点在Button一类的控 ...
- 【转】Bellman_ford算法
原文链接:http://www.cnblogs.com/Jason-Damon/archive/2012/04/21/2460850.html 摘自百度百科 Bellman-ford算法是求含负权图的 ...
- C语言练习:第二大整数
问题描述 编写一个程序,读入一组整数(不超过20个),当用户输入0时,表示输入结束.然后程序将从这组整数中,把第二大的那个整数找出来,并把它打印出来.说明:(1)0表示输入结束,它本身并不计入这组整数 ...
- BITED数学建模七日谈之三:怎样进行论文阅读
前两天,我和大家谈了如何阅读教材和备战数模比赛应该积累的内容,本文进入到数学建模七日谈第三天:怎样进行论文阅读. 大家也许看过大量的数学模型的书籍,学过很多相关的课程,但是若没有真刀真枪地看过论文,进 ...
- Protocol Buffer详解
1.Protocol Buffer 概念 Google Protocol Buffer( 简称 Protobuf) 是 Google 公司内部的混合语言数据标准,目前已经正在使用的有超过 48,162 ...
- 32+激发灵感的HTML5/CSS3网页设计教程
HTML5是寄托在HTML4基础上取得了的广泛成就.这不仅意味着你不必完全放弃现有的一些标记,而是可以借鉴,以加强 它. CSS3也以同样的方式在互联网内容的安排下,提供了它的柔韧性.CSS3是开 ...
- SQL SERVER安装提示“安装了 Microsoft Visual Studio 2008 的早期版本
工作共遇到的问题记录: 安装Sql Server 2008 R2时提示错误:“此计算机上安装了 Microsoft Visual Studio 2008 的早期版本.请在安装 SQL Server 2 ...
- 最精简的IOCP封装
最精简的IOCP封装,DELPHI XE8直接编译通过.Winsock2.pas即使用DELPHI自带的,相信XE7也能编译,或者XE6,XE5也能. 单说Winsock2.pas,我见过无数种版本的 ...
- True or False
任何对象都可以被测试真值.用于if或while条件中或作为下面的布尔操作的操作数.以下值被视为假: None False 任何数值类型的零,例如,0.0.0.0j . 任何空序列,例如,". ...
- Intellij IDEA 14.x 中的Facets和Artifacts的区别
Facets和Artifacts的区别: Facets 表示这个module有什么特征,比如 Web,Spring和Hibernate等: Artifact 是maven中的一个概念,表示某个modu ...