Happy Three Friends
Happy Three Friends
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 0 Accepted Submission(s): 0
There are 6 numbers on the table.
Firstly , Dong-hao can change the order of 6 numbers.
Secondly , Grandpa Shawn take the first one and the last one , sum them up as his scores.
Thirdly , Beautiful-leg Mzry take any of 3 numbers from the last 4 numbers , and sum them up as his scores.
Finally , if Grandpa Shawn's score is larger than Beautiful-leg Mzry's , Granpa Shawn wins!
If Grandpa Shawn's score is smaller than Beautiful-leg Mzry's , Granpa Shawn loses.
If the scores are equal , there is a tie.
Nowadays , it's really sad that Grandpa Shawn loses his love. So Dong-hao wants him to win(not even tie). You have to tell Dong-hao whether he can achieve his goal.
For each test case , there are 6 numbers Ai ( 1 <= Ai <= 100 ).
If he can not , output "What a sad story!"
For the first test case , {3 , 1 , 2 , 2 , 2 , 3} Grandpa Shawn can take 6 at most . But Beautiful-leg Mzry can take 6 too. So there is a tie.
For the second test cases , Grandpa Shawn loses.
For the last one , Dong-hao can arrange the numbers as {3 , 2 , 2 , 2 , 1 , 4} , Grandpa Shawn can take 7 , but Beautiful-leg Mzry can take 6 at most. So Grandpa Shawn Wins!
#include <iostream>
#include <cstdio>
#include <cstring>
#include <cmath>
#include <algorithm>
#include <climits>
#include <vector>
#include <queue>
#include <cstdlib>
#include <string>
#include <set>
#include <stack>
#define LL long long
#define INF 0x3f3f3f3f
using namespace std;
int d[],n;
int main() {
int t,i,j,grapa,mzry;
scanf("%d",&t);
while(t--){
for(i = ;i < ; i++)
scanf("%d",d+i);
sort(d,d+);
grapa = d[]+d[];
mzry = d[]+d[]+d[];
if(grapa > mzry){
puts("Grandpa Shawn is the Winner!");
}else puts("What a sad story!");
}
return ;
}
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