Select all employee's name and bonus whose bonus is < 1000.

Table:Employee

+-------+--------+-----------+--------+
| empId | name | supervisor| salary |
+-------+--------+-----------+--------+
| 1 | John | 3 | 1000 |
| 2 | Dan | 3 | 2000 |
| 3 | Brad | null | 4000 |
| 4 | Thomas | 3 | 4000 |
+-------+--------+-----------+--------+
empId is the primary key column for this table.

Table: Bonus

+-------+-------+
| empId | bonus |
+-------+-------+
| 2 | 500 |
| 4 | 2000 |
+-------+-------+
empId is the primary key column for this table.

Example ouput:

+-------+-------+
| name | bonus |
+-------+-------+
| John | null |
| Dan | 500 |
| Brad | null |
+-------+-------+

选出所有奖金<1000元的雇员姓名及奖金数额

解法1:

# Write your MySQL query statement below
SELECT name, bonus
FROM Employee LEFT JOIN Bonus USING (empId)
WHERE IFNULL(bonus, 0) < 1000  

解法2:

select name, bonus
from
Employee e left join Bonus b
on e.empId = b.empId
where bonus < 1000 or bonus is null

  

All LeetCode Questions List 题目汇总

[LeetCode]577. Employee Bonus 员工奖金的更多相关文章

  1. 【leetcode_easy_$】577. Employee Bonus

    problem 577. Employee Bonus 参考 1. Leetcode_easy_$_577. Employee Bonus; 2. https://www.cnblogs.com/li ...

  2. [LeetCode] 577. Employee Bonus_Easy tag: SQL

    Select all employee's name and bonus whose bonus is < 1000. Table:Employee +-------+--------+---- ...

  3. 解题报告 - 577. Employee Bonus

    Select all employee's name and bonus whose bonus is < 1000. Table:Employee +-------+--------+---- ...

  4. [LeetCode]690. Employee Importance员工重要信息

    哈希表存id和员工数据结构 递归获取信息 public int getImportance(List<Employee> employees, int id) { Map<Integ ...

  5. [SQL]LeetCode577.员工奖金 | Employee Bonus

    Select all employee's name and bonus whose bonus is < 1000. Table:Employee +-------+--------+---- ...

  6. [LeetCode] Employee Importance 员工重要度

    You are given a data structure of employee information, which includes the employee's unique id, his ...

  7. LeetCode 690. Employee Importance (职员的重要值)

    You are given a data structure of employee information, which includes the employee's unique id, his ...

  8. Leetcode690.Employee Importance员工的重要性

    给定一个保存员工信息的数据结构,它包含了员工唯一的id,重要度 和 直系下属的id. 比如,员工1是员工2的领导,员工2是员工3的领导.他们相应的重要度为15, 10, 5.那么员工1的数据结构是[1 ...

  9. LeetCode - 690. Employee Importance

    You are given a data structure of employee information, which includes the employee's unique id, his ...

随机推荐

  1. selenium常用的API(四)设置get方法最大加载时间

    我们在进行自动化测试的时候,使用get方法打开页面时会等到页面完全加载完才会执行后续操作, 有时我们需要的元素已加载完成,而部分JS未加载完导致加载时间很长,这无疑增加了自动化测试的时间, 针对此情况 ...

  2. C# 模拟鼠标移动和点击

    我们需要用到的mouse_event函数,位于user32.dll这个库文件里面,所以我们要先声明引用. [System.Runtime.InteropServices.DllImport(" ...

  3. 项目Alpha冲刺(10/10)

    1.项目燃尽图 2.今日进度描述 项目进展 完成测试 问题困难 测试用例的设计 心得体会 目标快要完成,队员士气较高 3.会议照片 4.各成员情况 221600106 今日进展 根据测试结果修改代码 ...

  4. 2019-2020-1 20199301《Linux内核原理与分析》第九周作业

    第八章 进程的切换和系统的一般执行过程 进程的调度实际与进程的切换 ntel定义的中断类型 硬中断:就是CPU的两根引脚(可屏蔽中断和不可屏蔽中断) 软中断/异常:包括除零错误.系统调用.调试断点等在 ...

  5. 事件类型(onfocus和onblur)

    <!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8&quo ...

  6. codeforcesC - Berry Jam(折半枚举+1-1序列前后缀和)

    Educational Codeforces Round 78 (Rated for Div. 2) C - Berry Jam C. Berry Jam time limit per test 2 ...

  7. 9-ESP8266 SDK开发基础入门篇--编写串口上位机软件

    https://www.cnblogs.com/yangfengwu/p/11087613.html 页面修改成这样子             现在看串口发送数据 点击点亮 发送0xaa 0x55 0 ...

  8. 洛谷 P2085 最小函数值

    目录 题目 思路 \(Code\) 题目 戳 思路 首先这些函数全部单带递增,因为\(a\),\(b\),\(c\)都是正整数. 我们将全部的函数的\(x\)为\(1\)时的函数值放入优先度列(小根堆 ...

  9. javascript 百度地图无秘钥(appkey)创建marker标记地图

    创建简单的marker地图不一定需要去百度地图申请key,简单代码实现marker地图,效果如图: html代码如下,代码中的baidu.api.js参考后面的隐藏代码: <!DOCTYPE h ...

  10. 【洛谷P3391】文艺平衡树——Splay学习笔记(二)

    题目链接 Splay基础操作 \(Splay\)上的区间翻转 首先,这里的\(Splay\)维护的是一个序列的顺序,每个结点即为序列中的一个数,序列的顺序即为\(Splay\)的中序遍历 那么如何实现 ...