Select all employee's name and bonus whose bonus is < 1000.

Table:Employee

+-------+--------+-----------+--------+
| empId | name | supervisor| salary |
+-------+--------+-----------+--------+
| 1 | John | 3 | 1000 |
| 2 | Dan | 3 | 2000 |
| 3 | Brad | null | 4000 |
| 4 | Thomas | 3 | 4000 |
+-------+--------+-----------+--------+
empId is the primary key column for this table.

Table: Bonus

+-------+-------+
| empId | bonus |
+-------+-------+
| 2 | 500 |
| 4 | 2000 |
+-------+-------+
empId is the primary key column for this table.

Example ouput:

+-------+-------+
| name | bonus |
+-------+-------+
| John | null |
| Dan | 500 |
| Brad | null |
+-------+-------+

选出所有奖金<1000元的雇员姓名及奖金数额

解法1:

# Write your MySQL query statement below
SELECT name, bonus
FROM Employee LEFT JOIN Bonus USING (empId)
WHERE IFNULL(bonus, 0) < 1000  

解法2:

select name, bonus
from
Employee e left join Bonus b
on e.empId = b.empId
where bonus < 1000 or bonus is null

  

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