[Interview] Bubble sort using singly-linked list

• Question :
  • Bubble sort using singly-linked list
  • 群暉面試題
• Idea : 
  • 在linked list 交換node與node時, 我們會想用換*next的方式。但是這裡是singly-linked list.
    還會需要previously node。其實這裡單純直接換int val還比較簡單。不過算蠻偷吃步的
• Code : [根本就是array版]

• typedef struct Node{
      int val;
      struct Node *next;
  }Node, *NodePtr;
  void bubbleSort(NodePtr head) {
      int i,j,tmp;
      bool flag;
      for(i = 0; i < len-1 ;i++) {
          NodePtr curr = head;
          NodePtr next = head->next;
          flag = false;
          for(j=0; j < len-i-1 ;j++) {
              if(curr->val > next->val ) {
                  tmp = curr->val;
                  curr->val = next->val;
                  next->val = tmp;
                  flag = true;
              }
          }
          if(flag == false) break; // 沒有結點需要swap
      }
  }
  

• 　　[修改*next 版]

void bubbleSort(NodePtr head) {
	bool flag = true;
	while(flag) {
		flag = false;
		NodePtr curr = head;
		NodePtr prev = NULL;
		while(curr->next){
			if(curr->val > curr->next->val) {
				flag = true;
				curr = swap(curr,curr->next);
				if(prev == NULL) //while swaping the head node
					head = curr;
				else
					prev->next = curr;
			}
			prev = curr;
			curr = curr->next;
		}
	}
}

　　　　[使用dummyHead版] - 可以減少一個if, 來判斷swap頭結點的情況。

void bubbleSort(NodePtr head) {
	bool flag = true;
	NodePtr dummyHead = (NodePtr)malloc(sizeof(Node));
	dummyHead->next = head;
	while(flag) {
		flag = false;
		NodePtr curr = dummyHead->next;
		NodePtr prev = dummyHead;
		while(curr->next){
			if(curr->val > curr->next->val) {
				flag = true;
				prev->next = curr = swap(curr,curr->next);
			}
			prev = curr;
			curr = curr->next;
		}
		printf("flag:%d ",flag);
		print_all(dummyHead->next);
	}
}

　　

• 完整測資 : https://github.com/bittorrent3389/leetCode/blob/master/BubbleSort.c