2016huasacm暑假集训训练五 H - Coins

题目链接：https://vjudge.net/contest/126708#problem/H

题意：A有一大堆的硬币，他觉得太重了，想花掉硬币去坐的士；的士司机可以不找零，但是的士司机也不会多收零钱。怎么样才能使 A 花的零钱最多。

多重背包模板题

AC代码：

 import java.io.BufferedReader;
 import java.io.IOException;
 import java.io.InputStream;
 import java.io.InputStreamReader;
 import java.util.Arrays;
 import java.util.StringTokenizer;
 public class Main{
   public static void main(String args[])
 {
    int N, M;
    Scanner sc=new Scanner(System.in);
    while(sc.hasNext())
    {
       N=sc.nextInt();
       M=sc.nextInt();
       if(N==&&M==) break;
       int a[]=new int[];
       int c[]=new int [];
       int u[]=new int[];
       for (int i=; i< N; i++) a[i]=sc.nextInt();
       for (int i=; i< N; i++) c[i]=sc.nextInt();
       int sun=;
       boolean s[]=new boolean[];
       s[]=true;

       for (int i=; i< N; i++)
       {
          Arrays.fill(u, );
           for (int j=a[i]; j<=M; j++)
           {
              if (!s[j] && s[j-a[i]] && u[j-a[i]]< c[i])
               {
                    s[j]=true;
                    u[j]=u[j-a[i]]+;
                    sun++;
               }
           }
       }
       System.out.println(sun);
    }

   }
 }
 class Scanner {
     BufferedReader br;
     StringTokenizer st;

     Scanner(InputStream in) {
         br = new BufferedReader(new InputStreamReader(in));
         eat("");
     }

     private void eat(String string) {
         st = new StringTokenizer(string);
     }

     String nextLine() {
         try {
             return br.readLine();
         } catch (IOException e) {
             return null;
         }
     }

     boolean hasNext() {
         while (!st.hasMoreTokens()) {
             String s = nextLine();
             if (s == null)
                 return false;
             eat(s);
         }
         return true;
     }

     String next() {
         hasNext();
         return st.nextToken();
     }

     int nextInt() {
         return Integer.parseInt(next());
     }

     long nextLong() {
         return Long.parseLong(next());
     }

     double nextDouble() {
         return Double.parseDouble(next());
     }
 }