Given a non-negative integer N, find the largest number that is less than or equal to N with monotone increasing digits.

(Recall that an integer has monotone increasing digits if and only if each pair of adjacent digits x and ysatisfy x <= y.)

Example 1:

Input: N = 10
Output: 9

Example 2:

Input: N = 1234
Output: 1234

Example 3:

Input: N = 332
Output: 299

Note: N is an integer in the range [0, 10^9].

Runtime: 16 ms, faster than 87.76% of Java online submissions for Monotone Increasing Digits.

class Solution {
public static int monotoneIncreasingDigits(int N) {
char[] Nstr = String.valueOf(N).toCharArray();
int cnt = 0;
boolean firstmeet = true;
while(cnt < Nstr.length-1){
if(Nstr[cnt] > Nstr[cnt+1]){
if(firstmeet) {
for(int i=cnt+1; i<Nstr.length; i++) Nstr[i] = '9';
Nstr[cnt] = (char)((int)Nstr[cnt] - 1);
firstmeet = false;
}else{
Nstr[cnt+1] = '9';
}
if(cnt > 0) {
cnt-=2;
firstmeet = true;
}
}
cnt++;
}
return Integer.parseInt(String.valueOf(Nstr));
}
}

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