Catch That Cow (bfs)
Catch That Cow
bfs代码
#include<cstdio>
#include<cstring>
#include<algorithm>
#include<iostream>
#include<string>
#include<vector>
#include<stack>
#include<bitset>
#include<cstdlib>
#include<cmath>
#include<set>
#include<list>
#include<deque>
#include<map>
#include<queue>
using namespace std;
typedef long long lint;
const double PI = acos(-1.0);
const int INF = ;
const int maxn = ; struct node{
int n, t;
}; node n;
int s, e;
int vis[maxn]; int bfs()
{
queue<node>q;
q.push(n);
while(!q.empty())
{
int b[];
node tmp;
tmp = q.front();
q.pop();
// cout << tmp.n << "&&" << tmp.t << " ";
if(tmp.n == e)
{
return tmp.t;
}
for(int i = ; i < ;i++)
{
if(i == ) b[i] = tmp.n - ;
else if(i == ) b[i] = tmp.n + ;
else if(i == ) b[i] = tmp.n * ;
if(b[i] < maxn && !vis[b[i]] && b[i] >= )
{
node g;
g.n = b[i];
g.t = tmp.t + ;
vis[g.n] = ;
q.push(g);
}
}
}
return -;
} int main()
{
while(cin >> s >> e)
{
n.n = s, n.t = ;
memset(vis, , sizeof(vis));
int ans = bfs();
cout << ans << endl;
} }
Catch That Cow (bfs)的更多相关文章
- HDU 2717 Catch That Cow (bfs)
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2717 Catch That Cow Time Limit: 5000/2000 MS (Java/Ot ...
- POJ 3278 Catch That Cow(bfs)
传送门 Catch That Cow Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 80273 Accepted: 25 ...
- HDU 2717 Catch That Cow(BFS)
Catch That Cow Farmer John has been informed of the location of a fugitive cow and wants to catch he ...
- Catch That Cow(BFS)
Catch That Cow Time Limit: 5000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)To ...
- POJ3279 Catch That Cow(BFS)
本文来源于:http://blog.csdn.net/svitter 意甲冠军:给你一个数字n, 一个数字k.分别代表主人的位置和奶牛的位置,主任能够移动的方案有x+1, x-1, 2*x.求主人找到 ...
- ***参考Catch That Cow(BFS)
Catch That Cow Time Limit : 4000/2000ms (Java/Other) Memory Limit : 131072/65536K (Java/Other) Tot ...
- poj 3278(hdu 2717) Catch That Cow(bfs)
Catch That Cow Time Limit: 5000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)To ...
- 题解报告:hdu 2717 Catch That Cow(bfs)
Problem Description Farmer John has been informed of the location of a fugitive cow and wants to cat ...
- poj 3278 Catch That Cow (bfs)
题目:http://poj.org/problem?id=3278 题意: 给定两个整数n和k 通过 n+1或n-1 或n*2 这3种操作,使得n==k 输出最少的操作次数 #include<s ...
随机推荐
- Java与openssl的RSA算法
1.java生成的公私钥格式为 pkcs8(PKCS8EncodedKeySpec), 而openssl默认生成的公私钥格式为 pkcs1 2.java采用的rsa默认补齐方式是pkcs1 (RSA/ ...
- Ubuntu中Redis的安装与使用
安装 安装Redis服务器端 apt-get install redis-server 安装完成后,Redis服务器会自动启动,我们检查Redis服务器程序. 检查Redis服务器系统进程 ps -a ...
- Oracle(1)之虚拟机下安装与简单使用
Oracle介绍与安装 简介 Oracle 数据库系统是美国 ORACLE 公司(甲骨文)提供的以分布式数据库为核心的一组软件产品,是目前最流行的客户/服务器 (CLIENT/SERVER) 或 B/ ...
- jquery-ui 之dialog
1,引入css和js <script type="text/javascript" src="${ctx}/js/ytd/platform/zdjsDlbyqbh/ ...
- vuex中的dispatch和commit
dispatch:含有异步操作,eg:向后台提交数据,写法: this.$store.dispatch('mutations方法名',值) commit:同步操作,写法:this.$store.com ...
- [LeetCode] 586. Customer Placing the Largest Number of Orders_Easy tag;SQL
Query the customer_number from the orders table for the customer who has placed the largest number o ...
- vue使用md5加密
import crypto from 'crypto' export default { name: 'HelloWorld', data () { return { msg: 'Welcome to ...
- JAVA代码(GET方式)请求URL(HTTP,HTTPS)
/** * * @param url 这个只支持http地址,不支持https * @param request * @return */ public static String sendMessa ...
- 利用TensorFlow实现多元逻辑回归
利用TensorFlow实现多元逻辑回归,代码如下: import tensorflow as tf import numpy as np from sklearn.linear_model impo ...
- 第三章Div水平居中
1.div居中 text-align:center可以让元素里面的文字内容居中,但并不能让div居中.要让div水平居中必须设置div宽度,外边距设置为margin:0 auto <%@ Pag ...