Help Me with the Game
Time Limit: 1000MS   Memory Limit: 65536K
Total Submissions: 3706   Accepted: 2371

Description

Your task is to read a picture of a chessboard position and print it in the chess notation.

Input

The input consists of an ASCII-art picture of a chessboard with chess pieces on positions described by the input. The pieces of the white player are shown in upper-case letters, while the black player's pieces are lower-case letters.
The letters are one of "K" (King), "Q" (Queen), "R" (Rook), "B" (Bishop), "N" (Knight), or "P" (Pawn). The chessboard outline is made of plus ("+"), minus ("-"), and pipe ("|") characters. The black fields are filled with colons (":"), white fields with dots
(".").

Output

The output consists of two lines. The first line consists of the string "White: ", followed by the description of positions of the pieces of the white player. The second line consists of the string "Black: ", followed by the description
of positions of the pieces of the black player.



The description of the position of the pieces is a comma-separated list of terms describing the pieces of the appropriate player. The description of a piece consists of a single upper-case letter that denotes the type of the piece (except for pawns, for that
this identifier is omitted). This letter is immediatelly followed by the position of the piece in the standard chess notation -- a lower-case letter between "a" and "h" that determines the column ("a" is the leftmost column in the input) and a single digit
between 1 and 8 that determines the row (8 is the first row in the input).



The pieces in the description must appear in the following order: King("K"), Queens ("Q"), Rooks ("R"), Bishops ("B"), Knights ("N"), and pawns. Note that the numbers of pieces may differ from the initial position because of capturing the pieces and the promotions
of pawns. In case two pieces of the same type appear in the input, the piece with the smaller row number must be described before the other one if the pieces are white, and the one with the larger row number must be described first if the pieces are black.
If two pieces of the same type appear in the same row, the one with the smaller column letter must appear first.

Sample Input

+---+---+---+---+---+---+---+---+
|.r.|:::|.b.|:q:|.k.|:::|.n.|:r:|
+---+---+---+---+---+---+---+---+
|:p:|.p.|:p:|.p.|:p:|.p.|:::|.p.|
+---+---+---+---+---+---+---+---+
|...|:::|.n.|:::|...|:::|...|:p:|
+---+---+---+---+---+---+---+---+
|:::|...|:::|...|:::|...|:::|...|
+---+---+---+---+---+---+---+---+
|...|:::|...|:::|.P.|:::|...|:::|
+---+---+---+---+---+---+---+---+
|:P:|...|:::|...|:::|...|:::|...|
+---+---+---+---+---+---+---+---+
|.P.|:::|.P.|:P:|...|:P:|.P.|:P:|
+---+---+---+---+---+---+---+---+
|:R:|.N.|:B:|.Q.|:K:|.B.|:::|.R.|
+---+---+---+---+---+---+---+---+

Sample Output

White: Ke1,Qd1,Ra1,Rh1,Bc1,Bf1,Nb1,a2,c2,d2,f2,g2,h2,a3,e4
Black: Ke8,Qd8,Ra8,Rh8,Bc8,Ng8,Nc6,a7,b7,c7,d7,e7,f7,h7,h6
大模拟
#include <iostream>
#include <cstring>
#include <cstdio>
#include <cmath>
#include <string>
#include <stack>
#include <queue>
#include <vector>
#include <algorithm>
using namespace std; const int Max=1100000; char s[110][110]; char str[110]; char c[]={'K','Q','R','B','N','P'}; int main()
{
for(int i=8;i>=1;i--)
{
scanf("%s",str);
scanf("%s",s[i]);
}
scanf("%s",str);
cout<<"White: ";
bool flag=false;
for(int i=0;i<6;i++)
{
for(int j=1;j<=8;j++)
{
int sum=0;
for(int k=2;k<33;k+=4,sum++)
{
if(c[i]==s[j][k]&&c[i]!='P')
{
if(!flag)
{
printf("%c%c%d",c[i],'a'+sum,j);
flag=true;
}
else
{
printf(",%c%c%d",c[i],'a'+sum,j);
}
}
else if(c[i]==s[j][k]&&c[i]=='P')
{
if(!flag)
{
printf("%c%d",'a'+sum,j);
flag=true;
}
else
{
printf(",%c%d",'a'+sum,j);
}
}
}
}
}
cout<<endl;
cout<<"Black: ";
flag=false;
for(int i=0;i<6;i++)
{
for(int j=8;j>=1;j--)
{
int sum=0;
for(int k=2;k<33;k+=4,sum++)
{
if(c[i]+32==s[j][k]&&c[i]!='P')
{
if(!flag)
{
printf("%c%c%d",c[i],'a'+sum,j);
flag=true;
}
else
{
printf(",%c%c%d",c[i],'a'+sum,j);
}
}
else if(c[i]+32==s[j][k]&&c[i]=='P')
{
if(!flag)
{
printf("%c%d",'a'+sum,j);
flag=true;
}
else
{
printf(",%c%d",'a'+sum,j);
}
}
}
}
}
cout<<endl;
return 0;
}

版权声明:本文为博主原创文章,未经博主允许不得转载。

Help Me with the Game 分类: POJ 2015-06-29 16:34 17人阅读 评论(0) 收藏的更多相关文章

  1. iOS自定义字体及类目 分类: ios技术 2015-05-15 16:34 195人阅读 评论(0) 收藏

    1:获取字体文件 从各种渠道下载字体文件ttf, 网站或者从别的ipa里扣出来.(以fzltxh.ttf为例) 2:将fzltxh.ttf文件拷贝到工程中 3:在Info.plist中添加项: Fon ...

  2. Binary Tree 分类: POJ 2015-06-12 20:34 17人阅读 评论(0) 收藏

    Binary Tree Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 6355   Accepted: 2922 Descr ...

  3. ASP.NET 自定义URL重写 分类: ASP.NET 2014-10-31 16:05 175人阅读 评论(0) 收藏

    一.功能说明: 可以解决类似 http://****/news 情形,Url路径支持正则匹配. 二.操作步骤: 1.增加URL重写模块: using System; using System.IO; ...

  4. ASP.NET 自定义URL重写 分类: ASP.NET 2014-10-31 16:05 174人阅读 评论(0) 收藏

    一.功能说明: 可以解决类似 http://****/news 情形,Url路径支持正则匹配. 二.操作步骤: 1.增加URL重写模块: using System; using System.IO; ...

  5. Removing Columns 分类: 贪心 CF 2015-08-08 16:10 10人阅读 评论(0) 收藏

    Removing Columns time limit per test 2 seconds memory limit per test 256 megabytes input standard in ...

  6. JAVA 对象数组,加载图片实例 分类: Java Game 2014-08-14 16:57 80人阅读 评论(0) 收藏

    主函数: package com.mywork; import java.awt.Color; import java.awt.Image; import javax.swing.ImageIcon; ...

  7. Hdu 1010 Tempter of the Bone 分类: Translation Mode 2014-08-04 16:11 82人阅读 评论(0) 收藏

    Tempter of the Bone Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Othe ...

  8. winform 解决界面闪动、提升加载速度 分类: WinForm 2015-02-03 16:34 161人阅读 评论(0) 收藏

    说明: 从一个技术交流群里获得,经验证效果不错. //作用 加快界面加载 protected override CreateParams CreateParams          {         ...

  9. SQL string类型的数据按int类型排序 分类: SQL Server 2014-12-08 16:56 393人阅读 评论(0) 收藏

    说明: 我在做wms进销存软件时,发现一个问题:一张入库单(T_OutIn_BoxTop),入库扫描时要分成多箱,箱号(BoxTop_No)可以是数字也可以是字符串,所以箱号只能是字符串类型的,问题来 ...

随机推荐

  1. SQL 2012 连接失败

  2. UVa 10007 - Count the Trees(卡特兰数+阶乘+大数)

    题目链接:UVa 10007 题意:统计n个节点的二叉树的个数 1个节点形成的二叉树的形状个数为:1 2个节点形成的二叉树的形状个数为:2 3个节点形成的二叉树的形状个数为:5 4个节点形成的二叉树的 ...

  3. How to wipe silicon to CPU 如何给CPU正确涂抹硅脂

    随 着计算机性能的提升,CPU的功耗也在不断的增大,虽然现在由于改进了工艺使得在功耗方面得到了一定的缓解,但由于近年来显卡性能的不断增强,也开始走上 了CPU功耗性能成正比的老路,功耗依然还是一个值得 ...

  4. zjuoj The 12th Zhejiang Provincial Collegiate Programming Contest Ace of Aces

    http://acm.zju.edu.cn/onlinejudge/showContestProblem.do?problemId=5493 The 12th Zhejiang Provincial ...

  5. vi/vim 键盘图 & 替换

    在VIM中进行文本替换:    1.  替换当前行中的内容:    :s/from/to/    (s即substitude)        :s/from/to/     :  将当前行中的第一个f ...

  6. URAL 1139 City Blocks(数论)

    The blocks in the city of Fishburg are of square form. N avenues running south to north and Mstreets ...

  7. ef 5 在 DropCreateDatabaseAlways 报错,the connection is currently used

    go sp_who2 -- db_id 数据库名称,查询出来的结果执行一遍就能关闭所有连接 SELECT N'kill '+ CAST(spid AS varchar) FROM master..sy ...

  8. Mysql索引总结(二)

    在数据库表中,对字段建立索引可以大大提高查询速度.假如我们创建了一个 mytable表: ) NOT NULL ); 在查找username="admin"的记录 SELECT * ...

  9. webpack我遇到的一些坑

    我的第一个用于实验webpack的项目是一个拥有多个版本的项目.什么叫多个版本?这个项目对3个语言版本+3个不同城市版本+(移动端  + PC端),也就是3*3*2,18个版本. 我的第一次想法肯定是 ...

  10. JSP-08-第三方控件的使用

    添加图片 下载 commons-fileupload-1.2.2.jar和commons-io-2.4.jar 导入项目 在添加涂抹的页面设置表单属性  enctype=”multipart/form ...