A variation to a classical DP: LCS.

class Solution {
public:
/**
* @param A an integer array
* @return A list of integers includes the index of
* the first number and the index of the last number
*/
vector<int> continuousSubarraySum(vector<int>& A) {
vector<int> ret; size_t len = A.size(); int curr = A[];
int sum = A[], csum = A[];
int s = , e = , ss = , ee = ;
for (int i = ; i < len; i++)
{
int nsum = csum + A[i];
if (A[i] > nsum)
{
ss = ee = i;
csum = A[i];
}
else
{
ee = i;
csum = nsum;
} if(csum > sum) // update global record
{
sum = nsum;
s = ss;
e = ee;
}
} ret.push_back(s);
ret.push_back(e);
return ret;
}
};

LintCode "Continuous Subarray Sum"的更多相关文章

  1. [LintCode] Continuous Subarray Sum II

    Given an integer array, find a continuous rotate subarray where the sum of numbers is the biggest. Y ...

  2. [LintCode] Continuous Subarray Sum 连续子数组之和

    Given an integer array, find a continuous subarray where the sum of numbers is the biggest. Your cod ...

  3. LintCode 402: Continuous Subarray Sum

    LintCode 402: Continuous Subarray Sum 题目描述 给定一个整数数组,请找出一个连续子数组,使得该子数组的和最大.输出答案时,请分别返回第一个数字和最后一个数字的下标 ...

  4. Continuous Subarray Sum II(LintCode)

    Continuous Subarray Sum II   Given an circular integer array (the next element of the last element i ...

  5. leetcode 560. Subarray Sum Equals K 、523. Continuous Subarray Sum、 325.Maximum Size Subarray Sum Equals k(lintcode 911)

    整体上3个题都是求subarray,都是同一个思想,通过累加,然后判断和目标k值之间的关系,然后查看之前子数组的累加和. map的存储:560题是存储的当前的累加和与个数 561题是存储的当前累加和的 ...

  6. Continuous Subarray Sum

    Given an integer array, find a continuous subarray where the sum of numbers is the biggest. Your cod ...

  7. [LeetCode] Continuous Subarray Sum 连续的子数组之和

    Given a list of non-negative numbers and a target integer k, write a function to check if the array ...

  8. [Swift]LeetCode523. 连续的子数组和 | Continuous Subarray Sum

    Given a list of non-negative numbers and a target integer k, write a function to check if the array ...

  9. Continuous Subarray Sum LT523

    Given a list of non-negative numbers and a target integer k, write a function to check if the array ...

随机推荐

  1. Python的类实例属性访问规则

    一般来说,在Python中,类实例属性的访问规则算是比较直观的. 但是,仍然存在一些不是很直观的地方,特别是对C++和Java程序员来说,更是如此. 在这里,我们需要明白以下几个地方: 1.Pytho ...

  2. meta标签兼容性

    基本标签SEO 优化为移动设备添加 viewportWindows 8其他 禁止数字识自动别为电话号码不让android识别邮箱每 8 秒刷新一次页面移动端的头部标签和meta 基本标签 声明文档使用 ...

  3. Vimium 快捷键记录

    , <c-e> : Scroll down k, <c-y> : Scroll up h : Scroll left l : Scroll right gg : Scroll ...

  4. Java--常用类

    1.方法中参数传递:值传递 基本数类型:具体的实际值 引用数据类型:对象的地址值 2.继承:关键字:extends单继承继承父类的非私有成员多重继承 2.权限的修饰符:private 只能在当前类的内 ...

  5. 比较字符串,equals防空指针问题

    1,比较两个字符串内容的话,用a.equals(b)比较,其中a,b是两个字符串,用a==b的话比较的是a和b的内存地址.2,如果一个字符串是变量,另一个字符串是常量的话,一定要把常量写在前面,变量写 ...

  6. eclipse项目导入到android studio

    只需要添加gradle文件,在里面添加如下代码片段------------------------------------------- main { manifest.srcFile 'Androi ...

  7. 基于时间延迟的Python验证脚本

    自己写的一段Python脚本,经常拿来验证一些sqlmap等工具跑不出数据的网站. GET类型: import urllib import urllib2 import time payloads = ...

  8. sqlserver函数

    SQLServer时间日期函数详解,SQLServer,时间日期, 1.      当前系统日期.时间 select getdate() 2. dateadd      在向指定日期加上一段时间的基础 ...

  9. HDU-1542 Atlantis(离散化+扫描线)

    题目大意:给n个矩形,可能重叠,求面积. 题目分析:线段树维护扫描线. 代码如下: # include<bits/stdc++.h> using namespace std; # defi ...

  10. 关于duplicate symbol _main in的解决办法

    报错:duplicate symbol _main in: duplicate symbol _main in:    /Users/gavin/Library/Developer/Xcode/Der ...