POJ1426——Find The Multiple

Description

Given a positive integer n, write a program to find out a nonzero multiple m of n whose decimal representation contains only the digits 0 and 1. You may assume that n is not greater than 200 and there is a corresponding m containing no more than 100 decimal digits.

Input

The input file may contain multiple test cases. Each line contains a value of n (1 <= n <= 200). A line containing a zero terminates the input.

Output

For each value of n in the input print a line containing the corresponding value of m. The decimal representation of m must not contain more than 100 digits. If there are multiple solutions for a given value of n, any one of them is acceptable.

Sample Input

2
6
19
0

Sample Output

10
100100100100100100
111111111111111111

代码:

#include<iostream>
#include<bits/stdc++.h>
#include<queue>
using namespace std; void BFS(int x){
queue<int> q ;
q.push(1);
int y;
while (!q.empty())
{
y=q.front();
q.pop();
for (int i = 0; i < 2; i++)
{
if (i==0) q.push(y*10);
else
q.push(y*10+1);
if (y%x==0)
{
cout<<y<<endl;
return ;
} }
}
} int main(){
int x;
while ((cin>>x)&&x)
{
BFS(x);
}
}

POJ1426——Find The Multiple的更多相关文章

  1. POJ1426 Find The Multiple (宽搜思想)

    Find The Multiple Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 24768   Accepted: 102 ...

  2. poj1426 Find The Multiple

    Find The Multiple Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 14622   Accepted: 593 ...

  3. poj1426 Find The Multiple(c语言巧解)

    Find The Multiple Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 36335   Accepted: 151 ...

  4. POJ1426:Find The Multiple(算是bfs水题吧,投机取巧过的)

    http://poj.org/problem?id=1426 Description Given a positive integer n, write a program to find out a ...

  5. POJ1426 Find The Multiple —— BFS

    题目链接:http://poj.org/problem?id=1426 Find The Multiple Time Limit: 1000MS   Memory Limit: 10000K Tota ...

  6. poj1426 Find The Multiple (DFS)

    题目: Find The Multiple Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 41845   Accepted: ...

  7. POJ1426 Find The Multiple 解题报告

    参考:http://www.cnblogs.com/ACShiryu/archive/2011/07/24/2115356.html #include <iostream> #includ ...

  8. poj1426 - Find The Multiple [bfs 记录路径]

    传送门 转:http://blog.csdn.net/wangjian8006/article/details/7460523 (比较好的记录路径方案) #include<iostream> ...

  9. POJ1426——Find The Multiple (简单搜索+取余)

    题意: 给一个数n,让你找出一个只有1,0,组成的十进制数,要求是找到的数可以被n整除. 用DFS是搜索 当前位数字 (除最高位固定为1),因为每一位都只有0或1两种选择,换而言之是一个双入口BFS. ...

随机推荐

  1. 新手安装eclipse或idea后进行配置、快捷键、插件总结

    .personSunflowerP { background: rgba(51, 153, 0, 0.66); border-bottom: 1px solid rgba(0, 102, 0, 1); ...

  2. 记面试的一道JS题

    给一个数组arr=[1,2,3,4,5],索引第二位插入'z',设计一个函数change,调用change(arr, 2, 'z')返回一个新数组[1,2,'z',3,4,5] 我想了两种办法: 第一 ...

  3. 模拟7 T3 寿司题解

    题目要求可以转化成一个01串,让通过最少次数把序列变成中间是0,两端是1: 首先我们可以考虑一些性质: 最优解一定是每次操作都把0和1交换 这个很好理解,如果你交换同一种东西,跟没换一样 这个题卡就卡 ...

  4. HTTP协议之:HTTP/1.1和HTTP/2

    目录 简介 HTTP/1.1 HTTP/2 传输模式对比 流优先级 缓冲区溢出处理 预测资源请求 压缩 总结 简介 HTTP的全称是Hypertext Transfer Protocol,是在1989 ...

  5. 【springboot】知识点总结

    [springboot 基础编] 01.SpringBoot>01 - 第一个应用–HelloWorld 02.SpringBoot>02 - 整合 MyBatis 03.SpringBo ...

  6. JAVA集合类(代码手写实现,全面梳理)

    参考网址:https://blog.csdn.net/weixin_41231928/article/details/103413167 目录 一.集合类关系图 二.Iterator 三.ListIt ...

  7. Windows10 Dev - Background Execution

    The Universal Windows Platform (UWP) introduces new mechanisms, which allow the applications to perf ...

  8. 【转】TCP和UDP的区别

    转自:https://www.cnblogs.com/steven520213/p/8005258.html TCP和UDP是OSI模型中的运输层中的协议.TCP提供可靠的通信传输,而UDP则常被用于 ...

  9. const 修饰

    int * const grape_jelly; 指针是只读的. const int * grape; int const * grape; 指针所指向的对象是只读的. 对象和指针有可能都是只读的: ...

  10. mzy对于反射的复习

    反射其实就是指在超脱规则的束缚,从强引用到弱相关,在上帝视角做事情,对于写配置文件,和一些框架的源码,得到调用上至关重要,java带有解释器的语法特性,使得泛型一类的语法糖和反射配合之后更如鱼得水! ...