function findInCircularlySortedAry (ary = [], target) {
if (ary && ary.length === ) {
return -;
} if (ary.length === ) {
return ary[] === target ? : -;
} let low = ,
high = ary.length - ; while(low <= high) {
let mid = Math.floor((low + high) / );
// case 1: target === middle item, return found
if (ary[mid] === target) {
return mid;
}
// To find which parts (left or right) is sorted
// case 2: if middle < high, mean from middle to high is sorted
if (ary[mid] < ary[high]) {
if (target > ary[mid] && target <= ary[high]) {
low = mid + ;
} else {
high = mid - ;
}
}
// case 3: if low < middle, mean from low to middle is sorted
else {
if (target >= ary[low] && target < ary[mid]) {
high = mid -;
} else {
low = mid + ;
}
}
} return -;
} const data = [,,,,,,,];
const res = findInCircularlySortedAry(data,); // 2
console.log(res);

We don't need to

[Algorithm] Search element in a circular sorted array的更多相关文章

  1. [Algorithm] How many times is a sorted array rotated?

    Given a sorted array, for example: // [2,5,6,8,11,12,15,18] Then we rotated it 1 time, it becomes: / ...

  2. Remove Element,Remove Duplicates from Sorted Array,Remove Duplicates from Sorted Array II

    以下三个问题的典型的两个指针处理数组的问题,一个指针用于遍历,一个指针用于指向当前处理到位置 一:Remove Element Given an array and a value, remove a ...

  3. 【题解】【数组】【查找】【Leetcode】Search in Rotated Sorted Array

    Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 migh ...

  4. [LeetCode] 34. Search for a Range 搜索一个范围(Find First and Last Position of Element in Sorted Array)

    原题目:Search for a Range, 现在题目改为: 34. Find First and Last Position of Element in Sorted Array Given an ...

  5. [LeetCode] 34. Find First and Last Position of Element in Sorted Array == [LintCode] 61. Search for a Range_Easy tag: Binary Search

    Description Given a sorted array of n integers, find the starting and ending position of a given tar ...

  6. [Algorithm] Count occurrences of a number in a sorted array with duplicates using Binary Search

    Let's say we are going to find out number of occurrences of a number in a sorted array using binary ...

  7. [array] leetcode - 33. Search in Rotated Sorted Array - Medium

    leetcode - 33. Search in Rotated Sorted Array - Medium descrition Suppose an array sorted in ascendi ...

  8. 33. Search in Rotated Sorted Array & 81. Search in Rotated Sorted Array II

    33. Search in Rotated Sorted Array Suppose an array sorted in ascending order is rotated at some piv ...

  9. 33.[LeetCode] Search in Rotated Sorted Array

    Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e. ...

随机推荐

  1. 找不到包含 OwinStartupAttribute 的程序集

    配置一个 MVC 项目时 遇到的  vs 2013 解决办法:在 webconfig 中 <appSettings> <add key="owin:AutomaticApp ...

  2. 【Oracle】-【LRU和DBWR】-LRU算法与DBWR中的应用

    Oracle体系结构中经常看到LRU算法,Least Recently Used,也有叫“最近最少使用页面置换算法”,简单讲,Oracle会将内存中最近不用的数据库移出内存以腾出空间来加载另外的数据. ...

  3. ProFTPd Local pr_ctrls_connect Vulnerability - ftpdctl 漏洞及攻击代码分析

    攻击代码网址:http://www.exploit-db.com/exploits/394/ 1.执行环境: 1.ProFTPD 1.3.0/1.3.0a 2.编译ProFTPD时.--enable- ...

  4. Revit API找到风管穿过的墙(当前文档和链接文档)

    start [Transaction(TransactionMode.Manual)] [Regeneration(RegenerationOption.Manual)] public class c ...

  5. .NET 开源Protobuf-net从入门到精通

    <.NET 开源Protobuf-net从入门到精通>课程包含以下两个部分: 一..NET 开源Protobuf-net组件[数据存储篇] 本次分享课程包含以下干货知识点: 1.什么是Pr ...

  6. [Asp.net]web.config customErrors 如何设置?

    摘要 customErrors也经常在开发部署中看到<customErrors mode="Off" />,设置这样可以在页面上看到详细的错误信息.但也为黑客提供了攻击 ...

  7. 内存映射函数remap_pfn_range学习——代码分析(3)

    li {list-style-type:decimal;}ol.wiz-list-level2 > li {list-style-type:lower-latin;}ol.wiz-list-le ...

  8. ASP.NET Web API中实现版本的几种方式

    在ASP.NET Web API中,当我们的API发生改变,就涉及到版本问题了.如何实现API的版本呢? 1.通过路由设置版本 最简单的一种方式是通过路由设置,不同的路由,不同的版本,不同的contr ...

  9. Consul替代Eureka

    原文:https://www.cnblogs.com/ityouknow/p/9340591.html 在上个月我们知道 Eureka 2.X 遇到困难停止开发了,但其实对国内的用户影响甚小,一方面国 ...

  10. android&php 加密解密

    from://http://blog.csdn.net/hecker385/article/details/6717647 android&php 加密解密 分类: Php Android20 ...