导出现有数据库数据:

  • mysqldump -u用户名 -p密码 数据库名称 >导出文件路径           # 结构+数据
  • mysqldump -u用户名 -p密码 -d 数据库名称 >导出文件路径       # 结构

导入现有数据库数据:

  • mysqldump -uroot -p密码  数据库名称 < 文件路径

一、表关系

请创建如下表,并创建相关约束

二、操作表

1、自行创建测试数据

  1. /*
  2. Navicat MySQL Data Transfer
  3.  
  4. Source Server : abc
  5. Source Server Version : 50713
  6. Source Host : localhost:3306
  7. Source Database : lx
  8.  
  9. Target Server Type : MYSQL
  10. Target Server Version : 50713
  11. File Encoding : 65001
  12.  
  13. Date: 2016-10-24 18:07:25
  14. */
  15.  
  16. SET FOREIGN_KEY_CHECKS=0;
  17.  
  18. -- ----------------------------
  19. -- Table structure for `class`
  20. -- ----------------------------
  21. DROP TABLE IF EXISTS `class`;
  22. CREATE TABLE `class` (
  23. `cid` int(11) NOT NULL AUTO_INCREMENT,
  24. `caption` varchar(20) DEFAULT NULL,
  25. PRIMARY KEY (`cid`)
  26. ) ENGINE=InnoDB AUTO_INCREMENT=5 DEFAULT CHARSET=utf8;
  27.  
  28. -- ----------------------------
  29. -- Records of class
  30. -- ----------------------------
  31. INSERT INTO `class` VALUES ('', '三年二班');
  32. INSERT INTO `class` VALUES ('', '一年三班');
  33. INSERT INTO `class` VALUES ('', '三年一班');
  34. INSERT INTO `class` VALUES ('', 'python 二期');
  35.  
  36. -- ----------------------------
  37. -- Table structure for `course`
  38. -- ----------------------------
  39. DROP TABLE IF EXISTS `course`;
  40. CREATE TABLE `course` (
  41. `cid` int(11) NOT NULL AUTO_INCREMENT,
  42. `cname` varchar(20) DEFAULT NULL,
  43. `teache_id` int(11) DEFAULT NULL,
  44. PRIMARY KEY (`cid`),
  45. KEY `fk_c_t` (`teache_id`),
  46. CONSTRAINT `fk_c_t` FOREIGN KEY (`teache_id`) REFERENCES `teacher` (`tid`)
  47. ) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=utf8;
  48.  
  49. -- ----------------------------
  50. -- Records of course
  51. -- ----------------------------
  52. INSERT INTO `course` VALUES ('', '生物', '');
  53. INSERT INTO `course` VALUES ('', '体育', '');
  54. INSERT INTO `course` VALUES ('', '物理', '');
  55.  
  56. -- ----------------------------
  57. -- Table structure for `score`
  58. -- ----------------------------
  59. DROP TABLE IF EXISTS `score`;
  60. CREATE TABLE `score` (
  61. `sid` int(11) NOT NULL AUTO_INCREMENT,
  62. `student_id` int(11) DEFAULT NULL,
  63. `corse_id` int(11) DEFAULT NULL,
  64. `number` int(11) DEFAULT NULL,
  65. PRIMARY KEY (`sid`),
  66. KEY `fk_s_st` (`student_id`),
  67. KEY `fk_s_co` (`corse_id`),
  68. CONSTRAINT `fk_s_co` FOREIGN KEY (`corse_id`) REFERENCES `course` (`cid`),
  69. CONSTRAINT `fk_s_st` FOREIGN KEY (`student_id`) REFERENCES `student` (`sid`)
  70. ) ENGINE=InnoDB AUTO_INCREMENT=33 DEFAULT CHARSET=utf8;
  71.  
  72. -- ----------------------------
  73. -- Records of score
  74. -- ----------------------------
  75. INSERT INTO `score` VALUES ('', '', '', '');
  76. INSERT INTO `score` VALUES ('', '', '', '');
  77. INSERT INTO `score` VALUES ('', '', '', '');
  78. INSERT INTO `score` VALUES ('', '', '', '');
  79. INSERT INTO `score` VALUES ('', '', '', '');
  80. INSERT INTO `score` VALUES ('', '', '', '');
  81. INSERT INTO `score` VALUES ('', '', '', '');
  82. INSERT INTO `score` VALUES ('', '', '', '');
  83. INSERT INTO `score` VALUES ('', '', '', '');
  84. INSERT INTO `score` VALUES ('', '', '', '');
  85. INSERT INTO `score` VALUES ('', '', '', '');
  86. INSERT INTO `score` VALUES ('', '', '', '');
  87. INSERT INTO `score` VALUES ('', '', '', '');
  88. INSERT INTO `score` VALUES ('', '', '', '');
  89. INSERT INTO `score` VALUES ('', '', '', '');
  90. INSERT INTO `score` VALUES ('', '', '', '');
  91. INSERT INTO `score` VALUES ('', '', '', '');
  92. INSERT INTO `score` VALUES ('', '', '', '');
  93. INSERT INTO `score` VALUES ('', '', '', '');
  94. INSERT INTO `score` VALUES ('', '', '', '');
  95. INSERT INTO `score` VALUES ('', '', '', '');
  96. INSERT INTO `score` VALUES ('', '', '', '');
  97. INSERT INTO `score` VALUES ('', '', '', '');
  98. INSERT INTO `score` VALUES ('', '', '', '');
  99. INSERT INTO `score` VALUES ('', '', '', '');
  100. INSERT INTO `score` VALUES ('', '', '', '');
  101. INSERT INTO `score` VALUES ('', '', '', '');
  102.  
  103. -- ----------------------------
  104. -- Table structure for `student`
  105. -- ----------------------------
  106. DROP TABLE IF EXISTS `student`;
  107. CREATE TABLE `student` (
  108. `sid` int(11) NOT NULL AUTO_INCREMENT,
  109. `sname` varchar(20) DEFAULT NULL,
  110. `gender` varchar(12) DEFAULT NULL,
  111. `class_id` int(11) DEFAULT NULL,
  112. PRIMARY KEY (`sid`),
  113. KEY `fk_s_c` (`class_id`),
  114. CONSTRAINT `fk_s_c` FOREIGN KEY (`class_id`) REFERENCES `class` (`cid`)
  115. ) ENGINE=InnoDB AUTO_INCREMENT=10 DEFAULT CHARSET=utf8;
  116.  
  117. -- ----------------------------
  118. -- Records of student
  119. -- ----------------------------
  120. INSERT INTO `student` VALUES ('', '钢蛋', '女', '');
  121. INSERT INTO `student` VALUES ('', '铁锤', '女', '');
  122. INSERT INTO `student` VALUES ('', '山炮', '男', '');
  123. INSERT INTO `student` VALUES ('', '张三', '男', '');
  124. INSERT INTO `student` VALUES ('', '李四', '男', '');
  125. INSERT INTO `student` VALUES ('', '王五', '男', '');
  126. INSERT INTO `student` VALUES ('', '马六', '女', '');
  127. INSERT INTO `student` VALUES ('', '霍七', '男', '');
  128. INSERT INTO `student` VALUES ('', '贺八', '男', '');
  129.  
  130. -- ----------------------------
  131. -- Table structure for `teacher`
  132. -- ----------------------------
  133. DROP TABLE IF EXISTS `teacher`;
  134. CREATE TABLE `teacher` (
  135. `tid` int(11) NOT NULL AUTO_INCREMENT,
  136. `tname` varchar(20) DEFAULT NULL,
  137. PRIMARY KEY (`tid`)
  138. ) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=utf8;
  139.  
  140. -- ----------------------------
  141. -- Records of teacher
  142. -- ----------------------------
  143. INSERT INTO `teacher` VALUES ('', '波多');
  144. INSERT INTO `teacher` VALUES ('', '苍空');
  145. INSERT INTO `teacher` VALUES ('', '饭岛');

创建表(结构)

2、查询“生物”课程比“物理”课程成绩高的所有学生的学号;

思路:
    获取所有有生物课程的人(学号,成绩) - 临时表
    获取所有有物理课程的人(学号,成绩) - 临时表
    根据【学号】连接两个临时表:
        学号 物理成绩 生物成绩       然后再进行筛选
  1. select A.student_id,生物,物理 from
  2.  
  3. (select student_id,number as 生物 from score left join course on score.corse_id = course.cid where course.cname = '生物') as A
  4.  
  5. left join
  6.  
  7. (select student_id,number as 物理 from score left join course on score.corse_id = course.cid where course.cname = '物理') as B
  8.  
  9. on A.student_id = B.student_id where 物理 > 生物 ;
 
3、查询平均成绩大于60分的同学的学号和平均成绩;
    思路:
        根据学生分组,使用avg获取平均值,通过havingavg进行筛选      
  1. select student_id,avg(number) from score GROUP BY student_id having avg(number)>60;
 
4、查询所有同学的学号、姓名、选课数、总成绩;
  1. SELECT
  2. score.student_id,
  3. COUNT(score.corse_id),
  4. SUM(score.number),
  5. student.sname
  6. FROM
  7. score
  8. LEFT JOIN student ON student.sid = score.student_id
  9. GROUP BY
  10. student_id
 
5、查询姓“李”的老师的个数
    

  1. select COUNT(tid) from teacher where tname LIKE"波%";
  2.  
  3. select count(1) from (select tid from teacher where tname like '波%') as B
6、查询没学过“叶平”老师课的同学的学号、姓名;
    思路:
        先查到“叶平老师”老师教的所有课ID
        获取选过课的所有学生ID
        学生表中筛选 
  1. select * from student where sid not in(
  2. select student_id from score WHERE score.corse_id in(
  3. select cid from course
  4. LEFT JOIN teacher on teacher.tid = course.teache_id where teacher.tname = "波多"
  5. )
  6. )
7、查询学过“001”并且也学过编号“002”课程的同学的学号、姓名;
    思路:
        先查到既选择001又选择002课程的所有同学
        根据学生进行分组,如果学生数量等于2表示,两门均已选择
  1. select student_id,sname from
  2.  
  3. (select student_id,corse_id from score where corse_id = 1 or corse_id = 2) as B
  4.  
  5. left join student on B.student_id = student.sid group by student_id HAVING count(student_id) = 2
8、查询学过“叶平”老师所教的所有课的同学的学号、姓名; 
  1. select * from student where sid in(
  2. select student_id from score WHERE score.corse_id in(
  3. select cid from course
  4. LEFT JOIN teacher on teacher.tid = course.teache_id where teacher.tname = "波多"
  5. )
  6. )
9、查询课程编号“002”的成绩比课程编号“001”课程低的所有同学的学号、姓名;
    

  1. select c.student_id,student.sname from
  2. (select A.student_id,a,b from
  3.  
  4. (select student_id,number as a from score left join course on score.corse_id = course.cid where course.cid = 1) as A
  5.  
  6. left join
  7.  
  8. (select student_id,number as b from score left join course on score.corse_id = course.cid where course.cid = 2) as B
  9. on A.student_id = B.student_id where b > a ) as c
  10. LEFT JOIN
  11. student on c.student_id = student.sid;
10、查询有课程成绩小于60分的同学的学号、姓名;  
  1. select sid,sname from student where sid in (
  2. select distinct student_id from score where number < 60
  3. )
  4.  
  5. select sid,sname from student where sid in (
  6. select student_id from score where number < 60 GROUP BY student_id
  7. )
11、查询没有学全所有课的同学的学号、姓名;
    思路:
        在分数表中根据学生进行分组,获取每一个学生选课数量
        如果数量 == 总课程数量,表示已经选择了所有课程      
  1. select student_id,sname from score left join student on score.student_id = student.sid
  2. group by student_id HAVING count(corse_id) = (select count(cid) from course)
12、查询至少有一门课与学号为“001”的同学所学相同的同学的学号和姓名;
    思路:
        获取 001 同学选择的所有课程
        获取课程在其中的所有人以及所有课程
        根据学生筛选,获取所有学生信息
        再与学生表连接,获取姓名
  1. select student_id,sname, count(corse_id)
  2. from score left join student on score.student_id = student.sid
  3. where student_id != 1 and corse_id in (select corse_id from score where student_id = 1) group by student_id
13、查询至少学过学号为“001”同学所有课的其他同学学号和姓名;
        先找到和001的学过的所有人
        然后个数 = 001所有学科     ==》 其他人可能选择的更多

  1. select student_id,sname, count(corse_id)
  2. from score left join student on score.student_id = student.sid
  3. where student_id != 1 and corse_id in (select corse_id from score where student_id = 1)
  4. group by student_id
14、查询和“002”号的同学学习的课程完全相同的其他同学学号和姓名;
         
        个数相同
        002学过的也学过

  1. select student_id,sname from score left join student on score.student_id = student.sid where student_id in (
  2. select student_id from score where student_id != 1 group by student_id HAVING count(corse_id) = (select count(1) from score where student_id = 1)
  3. ) and corse_id in (select corse_id from score where student_id = 1) group by student_id HAVING count(corse_id) = (select count(1) from score where student_id = 1)
15、删除学习“叶平”老师课的score表记录;  
  1. delete from score where corse_id in (
  2. select cid from course left join teacher on course.teache_id = teacher.tid where teacher.tname = '饭岛'
  3. )
16、向SC表中插入一些记录,这些记录要求符合以下条件:①没有上过编号“002”课程的同学学号;②插入“002”号课程的平均成绩;
  

  1. insert into score(student_id, corse_id, number) select sid,2,(select avg(number) from score where corse_id = 2)
  2. from student where sid not in (
  3. select student_id from score where corse_id = 2
  4. )
17、按平均成绩从低到高 显示所有学生的“语文”、“数学”、“英语”三门的课程成绩,按如下形式显示: 学生ID,语文,数学,英语,有效课程数,有效平均分;
   

  1. select sc.student_id,
  2. (select number from score left join course on score.corse_id = course.cid where course.cname = "生物" and score.student_id=sc.student_id) as sy,
  3. (select number from score left join course on score.corse_id = course.cid where course.cname = "物理" and score.student_id=sc.student_id) as wl,
  4. (select number from score left join course on score.corse_id = course.cid where course.cname = "体育" and score.student_id=sc.student_id) as ty,
  5. count(sc.corse_id),
  6. avg(sc.number)
  7. from score as sc
  8. group by student_id desc
  9.  
  10. select student_id,
  11. (select number from score as a WHERE a.student_id=b.student_id and corse_id=1)as sw,
  12. (select number from score as a WHERE a.student_id=b.student_id and corse_id=2) as ty,
  13. (select number from score as a WHERE a.student_id=b.student_id and corse_id=3) as wl,
  14. count(corse_id),avg(number)from score as b group by student_id ORDER BY avg(number) desc
18、查询各科成绩最高和最低的分:以如下形式显示:课程ID,最高分,最低分;   
  1. select corse_id, max(number) as max_num, min(number) as min_num from score group by corse_id;
19、按各科平均成绩从低到高和及格率的百分数从高到低顺序;
    思路:case when .. then   (类似三目(元)运算)   
  1. select corse_id, avg(number) ,sum(case when score.number > 60 then 1 else 0 END)/count(1)*100 as percent
  2. from score group by corse_id order by avg(number) asc,percent desc;
20、课程平均分从高到低显示(现实任课老师); 
  1. select avg(if(isnull(score.number),0,score.number)),teacher.tname from course
  2. left join score on course.cid = score.corse_id
  3. left join teacher on course.teache_id = teacher.tid
  4.  
  5. group by score.corse_id
  6.  
  7. select avg(score.number),teacher.tname from course
  8. left join score on course.cid = score.corse_id
  9. left join teacher on course.teache_id = teacher.tid
  10.  
  11. group by score.corse_id
21、查询各科成绩前三名的记录:(不考虑成绩并列情况)
  1. select score.sid,score.corse_id,score.number,T.first_num,T.second_num from score left join
  2. (
  3. select sid,
  4. (select number from score as s2 where s2.corse_id = s1.corse_id order by number desc limit 0,1) as first_num,
  5. (select number from score as s2 where s2.corse_id = s1.corse_id order by number desc limit 2,1) as second_num
  6. from
  7. score as s1
  8. ) as T
  9. on score.sid =T.sid
  10. where score.number <= T.first_num and score.number >= T.second_num
22、查询每门课程被选修的学生数;  
  1. select corse_id, count(1) from score group by corse_id
23、查询出只选修了一门课程的全部学生的学号和姓名;
    

  1. select student.sid, student.sname, count(1) from score
  2.  
  3. left join student on score.student_id = student.sid
  4.  
  5. group by corse_id having count(1) = 1
24、查询男生、女生的人数;
    

  1. select * from
  2. (select count(1) as man from student where gender='男')as A ,
  3. (select count(1) as feman from student where gender='女') as B
25、查询姓“张”的学生名单;  
  1. select sname from student where sname like '张%';
26、查询同名同姓学生名单,并统计同名人数;  
  1. select sname,count(1) as count from student group by sname;
27、查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序排列;   
  1. select corse_id,avg(if(isnull(number), 0 ,number)) as avg from score group by corse_id order by avg asc,corse_id desc;
  2.  
  3. select corse_id,avg(number)from score group by corse_id order by avg(number) asc,corse_id desc;
28、查询平均成绩大于85的所有学生的学号、姓名和平均成绩;   
  1. select student_id,avg(number),student.sname FROM score LEFT JOIN student on student.sid = score.student_id GROUP BY student_id
  2. HAVING avg(number)>85;
29、查询课程名称为“数学”,且分数低于60的学生姓名和分数; 
  1. SELECT student.sname,score.number FROM score LEFT JOIN student on student.sid = score.student_id left join course on score.corse_id = course.cid
  2. WHERE score.number<60 and course.cname= "物理"
30、查询课程编号为003且课程成绩在80分以上的学生的学号和姓名; 
  1. select student.sname,score.student_id from score LEFT JOIN student
  2. on student.sid = score.student_id WHERE score.number>80 and score.corse_id=3 GROUP BY student_id
31、求选了课程的学生人数 
  1. select count(distinct student_id) from score
  2.  
  3. select count(c) from (
  4. select count(student_id) as c from score group by student_id) as A
32、查询选修“杨艳”老师所授课程的学生中,成绩最高的学生姓名及其成绩;   
  1. select sname,number from score
  2. left join student on score.student_id = student.sid
  3. where score.corse_id in (select course.cid from course left join teacher
  4. on course.teache_id = teacher.tid where tname='波多') order by number desc limit ;
33、查询各个课程及相应的选修人数;
  1. select course.cname,count() from score
  2. left join course on score.corse_id = course.cid
  3. group by corse_id;
34、查询不同课程但成绩相同的学生的学号、课程号、学生成绩;   
  1. select DISTINCT s1.corse_id,s2.corse_id,s1.number,s2.number from score as s1, score as s2 where s1.number = s2.number and s1.corse_id != s2.corse_id;
35、查询每门课程成绩最好的前两名;
  1. select score.sid,score.corse_id,score.number,T.first_num,T.second_num from score left join
  2. (
  3. select
  4. sid,
  5. (select number from score as s2 where s2.corse_id = s1.corse_id order by number desc limit ,) as first_num,
  6. (select number from score as s2 where s2.corse_id = s1.corse_id order by number desc limit ,) as second_num
  7. from
  8. score as s1
  9. ) as T
  10. on score.sid =T.sid
  11. where score.number <= T.first_num and score.number >= T.second_num
36、检索至少选修两门课程的学生学号;
  1. select student_id from score group by student_id having count(student_id) > 1
37、查询全部学生都选修的课程的课程号和课程名;  
  1. select corse_id,course.cname,count(student_id) from score LEFT JOIN course on
  2. score.corse_id = course.cid GROUP BY corse_id HAVING COUNT(student_id)=(select count(sid) FROM student)
38、查询没学过“叶平”老师讲授的任一门课程的学生姓名;   
  1. select student_id,student.sname from score
  2. left join student on score.student_id = student.sid
  3. where score.corse_id not in (
  4. select cid from course left join teacher on course.teache_id = teacher.tid where tname = '波多'
  5. )
  6. group by student_id
  7.  
  8. select student_id,student.sname from score
  9. left join student on score.student_id = student.sid
  10. where score.corse_id not in (
  11. select cid from course left join teacher on course.teache_id = teacher.tid where tname = '波多'
  12. )
  13. group by student_id
39、查询两门以上不及格课程的同学的学号及其平均成绩;
  1. select student_id,avg(number) from score where number<60 GROUP BY student_id having count(corse_id)>=2
40、检索“004”课程分数小于60,按分数降序排列的同学学号;  
  1. SELECT student_id,number from score where corse_id=4 and number<60 ORDER BY number desc
41、删除“002”同学的“001”课程的成绩; 
  1. delete from score where corse_id = 1 and student_id = 2

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