A water problem

Time Limit: 5000/2500 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 342    Accepted Submission(s):
187

Problem Description
Two planets named Haha and Xixi in the universe and
they were created with the universe beginning.

There is 73

days in Xixi a year and 137

days in Haha a year.

Now you know the days N

after Big Bang, you need to answer whether it is the first day in a year about
the two planets.

 
Input
There are several test cases(about 5

huge test cases).

For each test, we have a line with an only integer
N(0≤N)

, the length of N

is up to 10000000

.

 
Output
For the i-th test case, output Case #i: , then output
"YES" or "NO" for the answer.
 
Sample Input
10001
0
333
 
Sample Output
Case #1: YES
Case #2: YES
Case #3: NO
 
Author
UESTC
 
Source
 
Recommend
wange2014   |   We have carefully selected several
similar problems for you:  5842 5841 5840 5839 5838 
 
 
解题思路:判断输入的数能否被10001整除,因为10001是73和137的最小公倍数。
  只要模拟除法,看最后的余数就可以。
  因为判断位数太多,所以也不能用java大数做,不然会内存超限。
  感觉之前做题给做傻了,一见到大数就想用java,一看别人说的题意就理解了,但自己看就是看不懂题意。
代码:
 #include <iostream>
#include <cstdio>
#include <cstring> using namespace std; char s[]; int main()
{
int z=;
int ans=;
int d=;
int len;
while(scanf("%s",s)!=EOF){
ans=;
len=strlen(s);
for(int i=;i<len;i++){
ans=((ans*+(s[i]-''))%d)%d;
}
if(ans==){
printf("Case #%d: YES\n",z++);
}else{
printf("Case #%d: NO\n",z++);
}
}
return ;
}

hdu5832 A water problem的更多相关文章

  1. HDU 5832 A water problem(某水题)

    p.MsoNormal { margin: 0pt; margin-bottom: .0001pt; text-align: justify; font-family: Calibri; font-s ...

  2. hdu 5443 The Water Problem

    题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5443 The Water Problem Description In Land waterless, ...

  3. HDU 5867 Water problem (模拟)

    Water problem 题目链接: http://acm.split.hdu.edu.cn/showproblem.php?pid=5867 Description If the numbers ...

  4. HDU 5832 A water problem

    A water problem Time Limit: 5000/2500 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)T ...

  5. HDU 5832 A water problem (带坑水题)

    A water problem 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5832 Description Two planets named H ...

  6. hdu 5443 The Water Problem 线段树

    The Water Problem Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php? ...

  7. HDU-4974 A simple water problem

    http://acm.hdu.edu.cn/showproblem.php?pid=4974 话说是签到题,我也不懂什么是签到题. A simple water problem Time Limit: ...

  8. The Water Problem(排序)

    The Water Problem Time Limit: 1500/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Othe ...

  9. HDU 4974 A simple water problem(贪心)

    HDU 4974 A simple water problem pid=4974" target="_blank" style="">题目链接 ...

随机推荐

  1. 【HDU 5438】Ponds

    题意 不断删去度数为1的点,最后求有奇数个点的联通块的权值之和. 分析 存边的时候,要头尾都存这个边.用dfs或者队列删点,再用并查集或者dfs确定联通块,然后统计联通块的点数,最后累加. 我自己写的 ...

  2. vbox下安装arch

    http://tieba.baidu.com/p/2663744019 安装介质: archlinux-2013.10.01-dual.iso 准备存储设备: 警告: 磁盘分区有时会毁掉原分区内的数据 ...

  3. Erlang练习题----shopping

    直接就上代码了: -module(shop). -export([cost/1,total/1]). cost(orange) -> 5; cost(newspaper) -> 8; co ...

  4. Codeforces 1C Ancient Berland Circus

    传送门 题意 给出一正多边形三顶点的坐标,求此正多边形的面积最小值. 分析 为了叙述方便,定义正多边形的单位圆心角u为正多边形的某条边对其外接圆的圆心角(即外接圆的某条弦所对的圆心角). (1)多边形 ...

  5. easyUI框架之学习2--添加左侧导航栏

    <head> function addTab(title, url) { if ($('#tableContainer').tabs('exists', title)) { $('#tab ...

  6. HTTP负载测试——Tsung

    参考资料:http://blog.jobbole.com/87509/ 如何生成每秒百万级别的 HTTP 请求? 在进行负责测试时要牢记一件重要的事:你能在 Linux 上建立多少个 socket 连 ...

  7. WinForm TextBox 焦点停留到文本最后

    最近写个 WinForm 项目,TextBox 控件有内容的时候,获取焦点,光标总是在最前面,很不便于输入.那怎么样让光标停留到最后呢?如下代码可以实现:            this.txtBox ...

  8. pom.xml

    使用intelJ idea 导入maven包管理文件是,使用Import的方式导入,会自动导入pom.xml来导入包. pom.xml会指定父子关系. 例如,总模块的pom.xml中有一下内容: &l ...

  9. XSS Filter Evasion Cheat Sheet 中文版

    前言 译者注: 翻译本文的最初原因是当我自己看到这篇文章后,觉得它是非常有价值.但是这么著名的一个备忘录却一直没有人把它翻译成中文版.很多人仅仅是简单的把文中的 各种代码复制下来,然后看起来很刁的发在 ...

  10. CSS创建一个遮罩层

    .layer{ width: 100%; position: absolute; left:; right:; top:; bottom:; -moz-opacity:; filter: alpha( ...