杭电1003 MAX SUN

Problem Description

Given a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max sum of a sub-sequence. For example, given (6,-1,5,4,-7), the max sum in this sequence is 6 + (-1) + 5 + 4 = 14.

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line starts with a number N(1<=N<=100000), then N integers followed(all the integers are between -1000 and 1000).

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line contains three integers, the Max Sum in the sequence, the start position of the sub-sequence, the end position of the sub-sequence. If there are more than one result, output the first one. Output a blank line between two cases.

 

Sample Input

2
5 6 -1 5 4 -7
7 0 6 -1 1 -6 7 -5

 

Sample Output

Case 1:
14 1 4

Case 2:
7 1 6

 

代码如下：

#include <iostream>
using namespace std;
int main()
{
	int t;
	cin>>t;
	if(t>=0&&t<=20)
	{
		for(int i=1;i<=t;i++)
		{
			int first,second,temp=1;
			int sum=0,max=-1001;
			int n,x;
			cin>>n;
			for(int j=1;j<=n;j++)
			{
				cin>>x;
				sum=sum+x;
				if(max<sum)
				{
					max=sum;
					first=temp;
					second=j;
				}
				if(sum<0)
				{
					sum=0;
					temp=j+1;
				}
			}
			cout<<"Case "<<i<<":"<<endl;
			cout<<max<<" "<<first<<" "<<second<<endl;
			if(i<t)
				cout<<endl;
		}
	}
	return 0;
}