求最低分最高分---c#（冒泡排序的运用）

 //  输入10个人的分数，去掉两个最高两个最低，求平均分
             Console.Write("请输入人数：");
             int renshu = int.Parse(Console.ReadLine());
             int[] chengji = new int[renshu];
             if (renshu >= )
             {
                 for (int h = ; h <= renshu; h++)
                 {
                     Console.Write("请输入第" + h + "个人的成绩");
                     chengji[h - ] = int.Parse(Console.ReadLine());
                 }
                 for (int i = ; i < renshu; i++) //冒泡排序，成绩由大到小排好
                 {
                     for (int j = i; j < renshu - ; j++)
                     {
                         if (chengji[i] < chengji[j + ])
                         {
                             int zhong = ;  //中间值
                             zhong = chengji[i];
                             chengji[i] = chengji[j + ];
                             chengji[j + ] = zhong;
                         }
                     }
                 }
                 int he = ;
                 for (int i = ; i <= (renshu - ); i++)     //算出总的成绩
                 {

                     he = he + chengji[i];
                 }
                 double pj = (he - chengji[] - chengji[] - chengji[renshu - ] - chengji[renshu - ]) / (renshu - );
                 Console.WriteLine("去掉两个最高分{0}、{1}，去掉两个最低分{2}、{3},最后平均成绩是：{4}", chengji[], chengji[], chengji[renshu - ], chengji[renshu - ], pj);
             }
             else
             {
                 Console.WriteLine("输入的人数要大于等于5！！！");
             }

             Console.ReadKey();