4：Median of Two Sorted Arrays

here are two sorted arrays nums1 and nums2 of size m and n respectively.

Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)).

Example 1:

nums1 = [1, 3]
nums2 = [2]

The median is 2.0

Example 2:

nums1 = [1, 2]
nums2 = [3, 4]

The median is (2 + 3)/2 = 2.5

答案：

public double findMedianSortedArrays(int[] nums1, int[] nums2) {

int len1 = nums1.length,len2 = nums2.length;

int len = len1 + len2;

int mod = len%2;

int start = 0;

int middle = len/2;

int temp = 0;

int index1 = 0,index2 = 0;

while(index1<len1 || index2 < len2){

if(index2 == len2 || (index1 < len1 && nums1[index1]<=nums2[index2])){

if(mod==1){

if(start == middle){

return nums1[index1];

}

}else{

if(start == middle - 1){

temp = nums1[index1];

}

if(start == middle){

return ((double)temp + (double)nums1[index1])/2;

}

}

index1++;

}else if(index1 == len1 || (index2 < len2 && nums1[index1]>nums2[index2])){

if(mod==1){

if(start == middle){

return nums2[index2];

}

}else{

if(start == middle - 1){

temp = nums2[index2];

}

if(start == middle){

return ((double)temp + (double)nums2[index2])/2;

}

}

index2++;

}

start ++;

}

return 0.0;

}