[LeetCode 题解]: Valid Palindrome
Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.
For example,"A man, a plan, a canal: Panama" is a palindrome."race a car" is not a palindrome.
Note:
Have you consider that the string might be empty? This is a good question to ask during an interview.
For the purpose of this problem, we define empty string as valid palindrome.
主要考察, cctype.h 的使用:
可能用到的函数: tolower, toupper, isalpha, isdigit, isalnum。
class Solution {
public:
bool isPalindrome(string s) {
int left=,right =s.size()-;
while(left<right)
{
if(!isalnum(s[left]))
left++;
else if(!isalnum(s[right]))
right--;
else
{
if(tolower(s[left])==tolower(s[right]))
{
left++;
right--;
}
else
return false;
}
}
return true;
}
};
可能用到的函数: tolower, toupper, isalpha, isdigit, isalnum。
补充知识: cctype 库文件(参考cplusplus:http://www.cplusplus.com/reference/cctype/ )
| 函数名 | function description | 函数说明 |
| isalnum | Check if character is alphanumeric (function ) | 查看参数是否为字符或数字 |
| isalpha | Check if character is alphabetic (function ) | 查看参数是否为字符 |
| isblank | Check if character is blank (function ) | 查看参数是否为空格 |
| iscntrl | Check if character is a control character (function ) | 查看参数是否为控制字符 |
| isdigit | Check if character is decimal digit (function ) | 查看参数是否为十进制数字 |
| isgraph | Check if character has graphical representation (function ) | 查看参数是否为可显示字符 |
| islower | Check if character is lowercase letter (function ) | 查看参数是否为可打印字符 |
| isprint | Check if character is printable (function ) | 查看参数是否为小写字符 |
| ispunct | Check if character is a punctuation character (function ) | 查看参数是否为标点符号 |
| isspace | Check if character is a white-space (function ) | 查看参数是否为空字符 |
| isupper | Check if character is uppercase letter (function ) | 查看参数是否为大写字符 |
| isxdigit | Check if character is hexadecimal digit (function ) | 查看参数是否为十六进制数字 |
具体的ASCII 与 cctype各函数的对应关系如下表:
| ASCII values | characters | iscntrl | isblank | isspace | isupper | islower | isalpha | isdigit | isxdigit | isalnum | ispunct | isgraph | isprint |
| x00 .. 0x08 | NUL, (other control codes) | x | |||||||||||
| 0x09 | tab ('\t') | x | x | x | |||||||||
| 0x0A .. 0x0D | (white-space control codes:'\f','\v','\n','\r') | x | x | ||||||||||
| 0x0E .. 0x1F | (other control codes) | x | |||||||||||
| 0x20 | space (' ') | x | x | x | |||||||||
| 0x21 .. 0x2F | !"#$%&'()*+,-./ | x | x | x | |||||||||
| 0x30 .. 0x39 | 123456789 | x | x | x | x | x | |||||||
| 0x3a .. 0x40 | :;<=>?@ | x | x | x | |||||||||
| 0x41 .. 0x46 | ABCDEF | x | x | x | x | x | x | ||||||
| 0x47 .. 0x5A | GHIJKLMNOPQRSTUVWXYZ | x | x | x | x | x | |||||||
| 0x5B .. 0x60 | [\]^_` | x | x | x | |||||||||
| 0x61 .. 0x66 | abcdef | x | x | x | x | x | x | ||||||
| 0x67 .. 0x7A | ghijklmnopqrstuvwxyz | x | x | x | x | x | |||||||
| 0x7B .. 0x7E | {|}~ | x | x | x | |||||||||
| 0x7F | (DEL) | x |
转载请注明出处: http://www.cnblogs.com/double-win/ 谢谢!
[LeetCode 题解]: Valid Palindrome的更多相关文章
- [LeetCode] 680. Valid Palindrome II 验证回文字符串 II
Given a non-empty string s, you may delete at most one character. Judge whether you can make it a pa ...
- LeetCode(125)题解--Valid Palindrome
https://leetcode.com/problems/valid-palindrome/ 题目: Given a string, determine if it is a palindrome, ...
- 【题解】【字符串】【Leetcode】Valid Palindrome
Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignori ...
- LeetCode 1216. Valid Palindrome III
原题链接在这里:https://leetcode.com/problems/valid-palindrome-iii/ 题目: Given a string s and an integer k, f ...
- [Leetcode][JAVA] Valid Palindrome
Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignori ...
- [LeetCode 题解]:Palindrome Number
前言 [LeetCode 题解]系列传送门: http://www.cnblogs.com/double-win/category/573499.html 1.题目描述 Determine ...
- [leetcode] 1. Valid Palindrome
leetcode的第一题,回文数判断. 原题如下: For example, "A man, a plan, a canal: Panama" is a palindrome. & ...
- [LeetCode] 125. Valid Palindrome 验证回文字符串
Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignori ...
- 【leetcode】Valid Palindrome
题目简述: Given a string, determine if it is a palindrome, considering only alphanumeric characters and ...
随机推荐
- sql developer Oracle 数据库 用户对象下表及表结构的导入导出
Oracle数据库表数据及结构的导入导出 导出的主机与即将导入到的目标主机的tablespace 及用户名需一直!!!!!
- 调试正常,签名打包提示 "x应用未安装。"
今天在工作的时候遇到一个奇葩的问题,开发一个新项目,然后在AS中调试运行都是一切正常.打包签名后,缺无法安装,提示"x应用未安装."如图所示. 网上找了好多方法,比如,签名的时候要 ...
- Javascript 键盘事件
window.document.onkeydown = function (e) { var evt = window.event || e;//兼容性处理 var keycode = evt.key ...
- 开发团队(Team)的主要职责和特征
角色介绍 开发团队是Scrum团队的三个角色之一. 开发团队包括架构师.开发工程师.测试人员.数据库管理员和UI设计师等,这几类人的跨职能组合.具备的技能足以实现产品开发. Team的主要职责 1.S ...
- [iOS]在xcode的iOS虚拟机中对BLE(蓝牙4.0)进行调试
本文档的主要内容可参考苹果官方资料: http://developer.apple.com/library/ios/#technotes/tn2295/_index.html 1. 买一个CSR蓝牙4 ...
- slf4j日志框架
- mysql存储过程(procedure)
#创建带参数的存储过程 delimiter // ),out p int) begin ; end // delimiter call pro_stu_name_pass(@n,@p); select ...
- php static 变量声明
<?phpfunction test($key){ static $array = array(); /* 静态变量是只存在于函数作用域中的变量,注释:执行后这种变量不会丢失(下次调用这个函数 ...
- dedecms开启报错调试
位置:/include/common.inc.php //error_reporting(E_ALL); error_reporting(E_ALL || ~E_NOTICE); 替换成 error_ ...
- Golang 之 Base62 编码
Base62 编码用62个可见字符来编码信息,也就是所谓的62进制,可用于缩短地址之类的.实现起来也很简单.当然,这个实现跟别人家的有可能不一样,反正自己能编能解就行. package main im ...