hdu1028 Ignatius and the Princess III(生成函数整理占坑)upd 已咕

先咕着

---------------2018 5 22----------------------

题解

生成函数处理整数拆分

code

#include<cstdio>
#include<cstring>
#include<algorithm>
inline int raed() {
	int x = 0,f = 1;
	char c = getchar();
	while(c < '0' || c < '9') c = getchar();
	while(c <= '9' && c >= '0')x = x * 10 + c - '0',c = getchar();
	return x * f;
}
const int maxn = 564;
int a[maxn],b[maxn];
int main() {
	int n;
	while(scanf("%d",&n) == 1) {
		for(int i = 0;i <= n;++ i)
			a[i] = 1,b[i] = 0;
		for(int i = 2;i <= n;++ i) {
			for(int j = 0;j <= n;++ j)
				for(int k = 0;k + j <= n;k += i)
					b[j + k] += a[j];
			for(int j = 0;j <= n;++ j)
				a[j] = b[j],b[j] = 0;
		}
		printf("%d\n",a[n]);
	}
	return 0;
}