Problem Description

The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book:
Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais…
Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive 'T's is not unusual. And they never use spaces.
So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A', 'B', 'C', …, 'Z'} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap.

Input

The first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format:
One line with the word W, a string over {'A', 'B', 'C', …, 'Z'}, with 1 ≤ |W| ≤ 10,000 (here |W| denotes the length of the string W).
One line with the text T, a string over {'A', 'B', 'C', …, 'Z'}, with |W| ≤ |T| ≤ 1,000,000.

Output

For every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the word W in the text T.

Sample Input

3
BAPC
BAPC
AZA
AZAZAZA
VERDI
AVERDXIVYERDIAN

Sample Output

1
3
0
解题思路:计算模式串在主串中出现的次数。
AC代码:
 #include<cstdio>
#include<string.h>
const int maxn=1e4+;
const int maxm=1e6+;
char text[maxm],pattern[maxn];
int prefix[maxn],lena,lenb,num,t;
void get_prefix_table(){//处理模式串前缀表
int j=,pos=-;
prefix[]=-;
while(j<lenb){
if(pos==-||pattern[pos]==pattern[j])prefix[++j]=++pos;
else pos=prefix[pos];
}
}
void kmp_search(){
int i=,j=;
while(i<lena){
if(j==-||text[i]==pattern[j])i++,j++;
else j=prefix[j];
if(j==lenb)num++,j=prefix[j];//此时的j应退回到j前面子串的最长公共前后缀长度的位置进行下一次匹配,可以有相交的模式串
}
}
int main(){
while(~scanf("%d",&t)){
while(t--){
scanf("%s%s",pattern,text);
memset(prefix,,sizeof(prefix));
num=,lena=strlen(text),lenb=strlen(pattern);
get_prefix_table();
kmp_search();
printf("%d\n",num);
}
}
return ;
}

题解报告:hdu 1686 Oulipo(裸KMP)的更多相关文章

  1. HDU 1686 Oulipo(KMP)题解

    题意:主串中能找到几个模式串 思路:超详细解释KMP KMP:针对这个代码,解释一下Fail数组的含义:T为主串,P为模式串,Fail代表失配值,即当P[j] != T[i]时,j要指向的位置为Fai ...

  2. HDU 1686 Oulipo(KMP变形求子串出现数目(可重))

    题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1686 题目大意:给两个字符串A,B求出A中出现了几次B(计算重复部分). 解题思路:稍微对kmp()函 ...

  3. hdu 1686 Oulipo (kmp)

    题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1686 题目大意:寻找子链在母链中出现的次数. #include <iostream> #i ...

  4. HDU 1686 Oulipo(kmp)

    Problem Description The French author Georges Perec (1936–1982) once wrote a book, La disparition, w ...

  5. hdu 1686 Oulipo 【KMP】(计算模式串匹配的次数——与已匹配的字串可以有交集)

    题目链接:https://vjudge.net/contest/220679#problem/B 题目大意: 输入一个T,表示有T组测试数据: 每组测试数据包括一个字符串W,T,T长度大于W小于100 ...

  6. HDU 1686 Oulipo(KMP+计算匹配成功次数)

    一开始总是超时,后来发现还是方法没找对,这个跟普通KMP不太一样的就是,KMP匹配成功的时候会完全跳过已经匹配成功的匹配段,至少我掌握的是.那么如何避免这样的问题呢,举个栗子啊 原串为ABABA,模式 ...

  7. HDU 1686 Oulipo【kmp求子串出现的次数】

    The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e ...

  8. HDU 1686 Oulipo / POJ 3461 Oulipo / SCU 2652 Oulipo (字符串匹配,KMP)

    HDU 1686 Oulipo / POJ 3461 Oulipo / SCU 2652 Oulipo (字符串匹配,KMP) Description The French author George ...

  9. HDU - 1686 Oulipo KMP匹配运用

    id=25191" target="_blank" style="color:blue; text-decoration:none">HDU - ...

随机推荐

  1. cogs——2419. [HZOI 2016]公路修建2

    2419. [HZOI 2016]公路修建2 ★☆   输入文件:hzoi_road2.in   输出文件:hzoi_road2.out   简单对比时间限制:1 s   内存限制:128 MB [题 ...

  2. Evaluate Reverse Polish Notation(逆波兰式)

    Evaluate the value of an arithmetic expression in Reverse Polish Notation. Valid operators are +, -, ...

  3. Servlet表单数据处理

    以下内容引用自http://wiki.jikexueyuan.com/project/servlet/form-data.html: 当需要从浏览器到Web服务器传递一些信息并最终传回到后台程序时,一 ...

  4. POJ3977 Subset 折半枚举

    题目大意是给定N个数的集合,从这个集合中找到一个非空子集,使得该子集元素和的绝对值最小.假设有多个答案,输出元素个数最少的那个. N最多为35,假设直接枚举显然是不行的. 可是假设我们将这些数分成两半 ...

  5. css 實現微信聊天類似的氣泡

    要實現這樣的效果 代碼如下: --------------------------------------- <style> .test{width:300px; padding:30px ...

  6. Tomcat启动一半闪退问题解决

    近期刚刚接触Tomcat.对其还不是非常了解. 在这几天,遇到一个Tomcat启动闪退的问题.通过查阅各种资料.算是完美解决.在此分享给朋友们. 首先.确定你的问题在哪里.有两个方法,你能够通过日志去 ...

  7. 通过构建Cocoapods私有库进行组件化开发探索

    专题一 一.创建私有索引库 选Github或者码云都可以,本例以Github为例.创建私有索引库用来作为自己组件库的索引: 二.本地添加私有索引库 添加:pod repo add 索引库名称 索引库地 ...

  8. Lint工具去除Android工程里不再需要的资源

    摘要: 在项目开发过程中常常会不断改UI设计,于是在定稿要发布的前夕,发现有好多不再需要的资源文件存在,发布的包会把这些无用的资源都包含在里面,造成APK的下载包过大.可以通过Android SDK自 ...

  9. css ios H5页面web页面 上下滑动卡顿问题解决方案

    原因1: html,body{ height: 100%; } 删除上述代码即可. 其他原因: *{ -webkit-overflow-scrolling: touch; } 增加上述代码.

  10. luogu1966 火柴排队

    题目大意 涵涵有两盒火柴,每盒装有 n 根火柴,每根火柴都有一个高度.现在将每盒中的火柴各自排成一列,同一列火柴的高度互不相同,两列火柴之间的距离定义为: $\sum_{i=1}^n(a_i-b_i) ...