题意  给一个字符串 判定其是否为回文串和镜像串  回文串非常好推断  镜像串对于每个字符用数组保存它的镜像字符即可了  没有的就是空格

注意若字符串长度为奇数  中间那个字母必须是对称的才是镜像串

#include<cstdio>
#include<cctype>
#include<cstring>
const int N = 35;
int l;
char s[N], mc[] = "A 3 HIL JM O 2TUVWXY5", mn[] = "1SE Z 8 "; bool isRegular()
{
for (int i = 1; i <= l / 2; ++i)
if (s[i] != s[l - i + 1]) return false;
return true;
} bool isMirrored()
{
for (int i = 1; i <= (l + 1) / 2 ; ++i)
{
if (isalpha (s[i]) && s[l - i + 1] != mc[s[i] - 'A']) return false;
else if (isdigit (s[i]) && s[l - i + 1] != mn[s[i] - '1']) return false;
}
return true;
} int main()
{
while (scanf ("%s", s + 1) != EOF)
{
l = strlen (s + 1);
if (isMirrored())
{
if (isRegular()) printf ("%s -- is a mirrored palindrome.\n\n", s + 1);
else printf ("%s -- is a mirrored string.\n\n", s + 1);
}
else if (isRegular()) printf ("%s -- is a regular palindrome.\n\n", s + 1);
else printf ("%s -- is not a palindrome.\n\n", s + 1);
}
return 0;
}

 Palindromes 

A regular palindrome is a string of numbers or letters that is the same forward as backward. For example, the string "ABCDEDCBA" is a palindrome because it is the same when the string is read from left to right as when the string is read
from right to left.

A mirrored string is a string for which when each of the elements of the string is changed to its reverse (if it has a reverse) and the string is read backwards the result is the same as the original string. For example, the string "3AIAE" is a mirrored
string because "A" and "I" are their own reverses, and "3" and "E" are each others' reverses.

A mirrored palindrome is a string that meets the criteria of a regular palindrome and the criteria of a mirrored string. The string "ATOYOTA" is a mirrored palindrome because if the string is read backwards, the string is the same as the original and
because if each of the characters is replaced by its reverse and the result is read backwards, the result is the same as the original string. Of course, "A", "T", "O", and "Y" are all their own reverses.

A list of all valid characters and their reverses is as follows.

Character Reverse Character Reverse Character Reverse
A A M M Y Y
B   N   Z 5
C   O O 1 1
D   P   2 S
E 3 Q   3 E
F   R   4  
G   S 2 5 Z
H H T T 6  
I I U U 7  
J L V V 8 8
K   W W 9  
L J X X    

Note that O (zero) and 0 (the letter) are considered the same character and therefore ONLY the letter "0" is a valid character.

Input

Input consists of strings (one per line) each of which will consist of one to twenty valid characters. There will be no invalid characters in any of the strings. Your program should read to the end of file.

Output

For each input string, you should print the string starting in column 1 immediately followed by exactly one of the following strings.

STRING CRITERIA
" -- is not a palindrome." if the string is not a palindrome and is not a mirrored string
" -- is a regular palindrome." if the string is a palindrome and is not a mirrored string
" -- is a mirrored string." if the string is not a palindrome and is a mirrored string
" -- is a mirrored palindrome." if the string is a palindrome and is a mirrored string

Note that the output line is to include the -'s and spacing exactly as shown in the table above and demonstrated in the Sample Output below.

In addition, after each output line, you must print an empty line.

Sample
Input

NOTAPALINDROME
ISAPALINILAPASI
2A3MEAS
ATOYOTA

Sample
Output

NOTAPALINDROME -- is not a palindrome.

ISAPALINILAPASI -- is a regular palindrome.

2A3MEAS -- is a mirrored string.

ATOYOTA -- is a mirrored palindrome.

UVa 401 Palindromes(镜像回文字符串)的更多相关文章

  1. 401 Palindromes(回文词)

      Palindromes  A regular palindrome is a string of numbers or letters that is the same forward as ba ...

  2. FCC JS基础算法题(2):Check for Palindromes(检查回文字符串)

    题目描述: 如果给定的字符串是回文,返回true,反之,返回false.如果一个字符串忽略标点符号.大小写和空格,正着读和反着读一模一样,那么这个字符串就是palindrome(回文).注意你需要去掉 ...

  3. leetcode 5 Longest Palindromic Substring--最长回文字符串

    问题描述 Given a string S, find the longest palindromic substring in S. You may assume that the maximum ...

  4. 【Aizu2292】Common Palindromes(回文树)

    [Aizu2292]Common Palindromes(回文树) 题面 Vjudge 神TMD日语 翻译: 给定两个字符串\(S,T\),询问\((i,j,k,l)\)这样的四元组个数 满足\(S[ ...

  5. uva 401 Palindromes 解题报告

    题目链接:http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem& ...

  6. [LeetCode] Valid Palindrome 验证回文字符串

    Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignori ...

  7. 回文字符串的判断!关于strlen(char * str)函数

    #include <stdio.h> #include <string.h> int ishuiw(char * p); int main() { ;//true-false接 ...

  8. NYOJ_37.回文字符串 (附滚动数组)

    时间限制:3000 ms  |  内存限制:65535 KB 难度:4 描述 所谓回文字符串,就是一个字符串,从左到右读和从右到左读是完全一样的,比如"aba".当然,我们给你的问 ...

  9. 131. 132. Palindrome Partitioning *HARD* -- 分割回文字符串

    131. Palindrome Partitioning Given a string s, partition s such that every substring of the partitio ...

随机推荐

  1. 函数内部属性之arguments和this

    在函数内部,有两个特殊的对象:arguments和this. 1.arguments arguments是一个类数组对象.包含着传入函数中的所有参数.但这个对象还有一个名叫callee的属性,该属性是 ...

  2. 为公司内部搭建CA

    步骤一 首先我们要知道CA的配置文件 openssl的配置文件:/etc/pki/tls/openssl.cnf 我们打开这个配置文件 这文件中很多跟CA相关的信息如图 解释: 我们可以搭建好几个CA ...

  3. 剑指Offer(书):重建二叉树

    题目:输入某二叉树的前序遍历和中序遍历的结果,请重建出该二叉树.假设输入的前序遍历和中序遍历的结果中都不含重复的数字.例如输入前序遍历序列{1,2,4,7,3,5,6,8}和中序遍历序列{4,7,2, ...

  4. Hibernate入门(1)——环境搭建

    什么是Hibernate?为什么使用Hibernate?Hibernate有什么优缺点?网上很多大神的文章又详细又通俗易懂. 步骤: 1.创建数据库表格. 2.编写JavaBean实体类. 3.下载H ...

  5. MySQL报错The server time zone value 'Öйú±ê׼ʱ¼ä' is unrecognized or represents

    参考资料:https://blog.csdn.net/qq_37630354/article/details/82814330 在property里加上最后这个参数即可

  6. C 题 KMP中next[]问题

    题目大意: 找到能够进行字符串匹配的前缀 这题只要一直求next,直到next为0停止,记得答案是总长减去next的长度 #include <iostream> #include < ...

  7. idea添加虚拟参数

    1. 2.

  8. [转]SQL SERVER数据库还原的方法

    SQL SERVER数据库还原的方法 在SQL SERVER 2005下还原数据库 1.新建数据库A,右键还原数据库,此时目标数据库为A,选择备份 文件B_db_201311040200.BAK,还原 ...

  9. POJ1256 Anagram

    Time Limit: 1000MS   Memory Limit: 10000KB   64bit IO Format: %lld & %llu Submit Status Descript ...

  10. 【POJ1743】Musical Theme(后缀数组,二分)

    题意:求一个字符串的不重叠最长相同变化的子串 n<=20000 思路:这是一道论文题 我们将原串两两之间作差,可以发现所求的相同变化的子串作出的差相同 问题就转化成了不重叠的最长重复子串 显然答 ...