谨慎重载clone方法
public class Car implements Cloneable {
private Object containedObj1 = new Object();
private Object containedObj2 = new Object();
public Object getObj1() {
return containedObj1;
}
public Object getObj2() {
return containedObj2;
}
@Override
protected Object clone() throws CloneNotSupportedException {
return (Car) super.clone();
}
public Car() {
}
public static void main(String[] args) {
try {
Car obj1 = new Car();
Car obj2 = (Car) obj1.clone();
System.out.println("obj1 and obj2 are same:" + (obj1 == obj2));
System.out.println("obj1.containedObj1 and obj2.containedObj1 are same:" + (obj1.getObj1() == obj2.getObj1()));
System.out.println("obj1.containedObj2 and obj2.containedObj2 are same:" + (obj1.getObj2() == obj2.getObj2()));
System.out.println("obj1.str and obj2.str are same:" +(obj2.getString() == obj1.getString()));
System.out.println("obj1.data:" + obj1.getData()+"; obj2.data:" + obj2.getData());
System.out.println("obj1.dataf:" + obj1.getDataf()+"; obj2.dataf:" + obj2.getDataf());
} catch (CloneNotSupportedException e) {
e.printStackTrace();
}
}
}
public class Car2 {
private Object containedObj1 = new Object();
private Object containedObj2 = new Object();
private String str = "oneStr";
private int data = 1024;
private float dataf = 1024.1024f;
public Car2() {
}
public Car2(Car2 car) {
this.str = new String(car.getString().toString());
this.data = car.getData();
this.dataf = car.getDataf();
}
private String getString() {
return str;
}
public int getData() {
return data;
}
public float getDataf() {
return dataf;
}
public Object getObj1() {
return containedObj1;
}
public Object getObj2() {
return containedObj2;
}
public static void main(String[] args) {
Car2 obj1 = new Car2();
Car2 obj2 = new Car2(obj1);
System.out.println("obj1 and obj2 are same:" + (obj1 == obj2));
System.out.println("obj1.containedObj1 and obj2.containedObj1 are same:" + (obj1.getObj1() == obj2.getObj1()));
System.out.println("obj1.containedObj2 and obj2.containedObj2 are same:" + (obj1.getObj2() == obj2.getObj2()));
System.out.println("obj1.str and obj2.str are same:" +(obj2.getString() == obj1.getString()));
System.out.println("obj1.data:" + obj1.getData()+"; obj2.data:" + obj2.getData());
System.out.println("obj1.dataf:" + obj1.getDataf()+"; obj2.dataf:" + obj2.getDataf());
}
}
@Override
protected Object clone() throws CloneNotSupportedException {
Body newBody = (Body) super.clone();
newBody.head = (Head) head.clone();
return newBody;
}
public class Body implements Cloneable {
public Head head;
public Body() {
}
public Body(Head head) {
this.head = head;
}
@Override
protected Object clone() throws CloneNotSupportedException {
Body newBody = (Body) super.clone();
newBody.head = (Head) head.clone();
return newBody;
}
public static void main(String[] args) throws CloneNotSupportedException {
Body body = new Body(new Head());
Body body1 = (Body) body.clone();
System.out.println("body == body1 : " + (body == body1));
System.out.println("body.head == body1.head : " + (body.head == body1.head));
}
}
class Head implements Cloneable/* implements Cloneable */ {
public Face face;
public Head() {
}
public Head(Face face) {
this.face = face;
}
@Override
protected Object clone() throws CloneNotSupportedException {
return super.clone();
}
}
class Face {
}
public class Body2 implements Cloneable {
public Head head;
public Body2() {
}
public Body2(Head head) {
this.head = head;
}
@Override
protected Object clone() throws CloneNotSupportedException {
Body2 newBody = (Body2) super.clone();
newBody.head = (Head) head.clone();
return newBody;
}
public static void main(String[] args) throws CloneNotSupportedException {
Body2 body = new Body2(new Head(new Face()));
Body2 body1 = (Body2) body.clone();
System.out.println("body == body1 : " + (body == body1));
System.out.println("body.head == body1.head : " + (body.head == body1.head));
System.out.println("body.head.face == body1.head.face : " + (body.head.face == body1.head.face));
}
}
class Head implements Cloneable/* implements Cloneable */ {
public Face face;
public Head() {
}
public Head(Face face) {
this.face = face;
}
@Override
protected Object clone() throws CloneNotSupportedException {
return super.clone();
}
}
class Face {
}
public final class Galaxy {
/**
* Regular constructor.
*/
public Galaxy(double aMass, String aName) {
fMass = aMass;
fName = aName;
}
/**
* Copy constructor.
*/
public Galaxy(Galaxy aGalaxy) {
this(aGalaxy.getMass(), aGalaxy.getName());
//no defensive copies are created here, since
//there are no mutable object fields (String is immutable)
}
/**
* Alternative style for a copy constructor, using a static newInstance
* method.
*/
public static Galaxy newInstance(Galaxy aGalaxy) {
return new Galaxy(aGalaxy.getMass(), aGalaxy.getName());
}
public double getMass() {
return fMass;
}
/**
* This is the only method which changes the state of a Galaxy
* object. If this method were removed, then a copy constructor
* would not be provided either, since immutable objects do not
* need a copy constructor.
*/
public void setMass(double aMass){
fMass = aMass;
}
public String getName() {
return fName;
}
// PRIVATE
private double fMass;
private final String fName;
/** Test harness. */
public static void main (String... aArguments){
Galaxy m101 = new Galaxy(15.0, "M101");
Galaxy m101CopyOne = new Galaxy(m101);
m101CopyOne.setMass(25.0);
System.out.println("M101 mass: " + m101.getMass());
System.out.println("M101Copy mass: " + m101CopyOne.getMass());
Galaxy m101CopyTwo = Galaxy.newInstance(m101);
m101CopyTwo.setMass(35.0);
System.out.println("M101 mass: " + m101.getMass());
System.out.println("M101CopyTwo mass: " + m101CopyTwo.getMass());
}
}
输出结果:
M101 mass: 15.0
M101Copy mass: 25.0
M101 mass: 15.0
M101CopyTwo mass: 35.0
谨慎重载clone方法的更多相关文章
- Java中clone方法的使用
什么是clone 在实际编程过程中,我们常常要遇到这种情况:有一个对象object1,在某一时刻object1中已经包含了一些有效值,此时可能会需要一个和object1完全相同新对象object2,并 ...
- Effective Java —— 谨慎覆盖clone
本文参考 本篇文章参考自<Effective Java>第三版第十三条"Always override toString",在<阿里巴巴Java开发手册>中 ...
- Effective Java 第三版——13. 谨慎地重写 clone 方法
Tips <Effective Java, Third Edition>一书英文版已经出版,这本书的第二版想必很多人都读过,号称Java四大名著之一,不过第二版2009年出版,到现在已经将 ...
- Effective Java 之-----谨慎的覆盖clone方法
1.概述 如果clone方法返回一个由构造器创建的对象,它就得到有错误的类.因此,如果覆盖了非final类中的clone方法,则应该返回一个通过调用super.clone得到的对象.如果类的所有超类都 ...
- 第十一条:谨慎的覆盖clone()方法
一个类要想实现克隆,需要实现Cloneable接口,表明这个类的对象具有克隆的功能. Cloneable接口是一个mixin接口,它里面并没有任何的抽象方法,类似的接口有Serializable接口, ...
- Java 深度克隆 clone()方法重写 equals()方法的重写
1.为什么要重写clone()方法? 答案:Java中的浅度复制是不会把要复制的那个对象的引用对象重新开辟一个新的引用空间,当我们需要深度复制的时候,这个时候我们就要重写clone()方法. 2.为什 ...
- .NET 基础 一步步 一幕幕[面向对象之方法、方法的重载、方法的重写、方法的递归]
方法.方法的重载.方法的重写.方法的递归 方法: 将一堆代码进行重用的一种机制. 语法: [访问修饰符] 返回类型 <方法名>(参数列表){ 方法主体: } 返回值类型:如果不需要写返回值 ...
- Object类clone方法的自我理解
网上搜帖: clone()是java.lang.Object类的protected方法,实现clone方法: 1)类自身需要实现Cloneable接口 2)需重写clone()方法,最好设置修饰符mo ...
- PHP面向对象编程——深入理解方法重载与方法覆盖(多态)
什么是多态? 多态(Polymorphism)按字面的意思就是“多种状态”.在面向对象语言中,接口的多种不同的实现方式即为多态.引用Charlie Calverts对多态的描述——多态性是允许你将父对 ...
随机推荐
- swift - tabBar图片设置的一些注意点
图片大小尺寸 刚刚开始接触的话,从美工那边拿来的图标大小一般都是偏大的,就像这样: 在此建议,tabBar的图标大小可以是32*32,个人感觉效果不错 图片的颜色问题 如上图所示,该图标的期望颜色(也 ...
- php addslashes和stripslashes函数
addslashes — 使用反斜线引用字符串 stripslashes — 反引用一个引用字符串 Example #1 一个 addslashes() 例子 <?php$str = &qu ...
- lintcode-129-重哈希
129-重哈希 哈希表容量的大小在一开始是不确定的.如果哈希表存储的元素太多(如超过容量的十分之一),我们应该将哈希表容量扩大一倍,并将所有的哈希值重新安排.假设你有如下一哈希表: size=3, c ...
- WebService(三)
JAX-WS简单使用示例: 1.服务端 package com.rong.service; import javax.jws.WebMethod; import javax.jws.WebParam; ...
- 桥接,NAT,Host Only的区别
桥接,NAT,Host Only的区别 一.Brigde——桥接 :默认使用VMnet0fish批注:只要在虚拟机中将IP设对,即使宿主机的IP是错的,也可以通信.但是如此物理网卡被禁用了,则不能 ...
- elementUI使用本地变量进行验证,监测不到本地变量的变化 的问题
对于饿了么组件自定义验证规则,组件库文档已经非常详细了:http://element-cn.eleme.io/#/zh-CN/component/form 我这里将验证中固定的值提取出来使用变量进行保 ...
- Web前端JQuery基础
JQuery知识汇总 一.关于Jquery简介 jQuery是一个快速.简洁的JavaScript框架,是继Prototype之后又一个优秀的JavaScript代码库(或JavaS ...
- Windows搭建Log4Net+FileBeat+ELK日志分析系统过程
参考博客:http://udn.yyuap.com/thread-54591-1-1.html ; https://www.cnblogs.com/yanbinliu/p/6208626.html ; ...
- 第112天:javascript中函数预解析和执行阶段
关于javascript中的函数: 1.预解析:把所有的函数定义提前,所有的变量声明提前,变量的赋值不提前 2.执行 :从上到下执行,但有例外(setTimeout,setInterval,aja ...
- 【uoj#51】[UR #4]元旦三侠的游戏 博弈论+dp
题目描述 给出 $n$ 和 $m$ ,$m$ 次询问.每次询问给出 $a$ 和 $b$ ,两人轮流选择:将 $a$ 加一或者将 $b$ 加一,但必须保证 $a^b\le n$ ,无法操作者输,问先手是 ...