codeforces 236A . Boy or Girl(串水问题)
1 second
256 megabytes
standard input
standard output
Those days, many boys use beautiful girls' photos as avatars in forums. So it is pretty hard to tell the gender of a user at the first glance. Last year, our hero went to a forum and had a nice chat with a beauty (he thought so). After that they talked very
often and eventually they became a couple in the network.
But yesterday, he came to see "her" in the real world and found out "she" is actually a very strong man! Our hero is very sad and he is too tired to love again now. So he came up with a way to recognize users' genders by their user names.
This is his method: if the number of distinct characters in one's user name is odd, then he is a male, otherwise she is a female. You are given the string that denotes the user name, please help our hero to determine the gender of this user by his method.
The first line contains a non-empty string, that contains only lowercase English letters — the user name. This string contains at most 100 letters.
If it is a female by our hero's method, print "CHAT WITH HER!" (without the quotes), otherwise, print "IGNORE HIM!" (without the quotes).
wjmzbmr
CHAT WITH HER!
xiaodao
IGNORE HIM!
sevenkplus
CHAT WITH HER!
For the first example. There are 6 distinct characters in "wjmzbmr". These characters are: "w", "j", "m",
"z", "b", "r". So wjmzbmr is a female and you should print "CHAT WITH HER!".
#include <iostream>
#include<memory.h>
#include<stdlib.h>
using namespace std;
int cmp(const void *a,const void *b)
{
return *(char *)a-*(char *)b;
}
int main()
{
char c[101];
int k,s,i,j;
while(cin>>c)
{
s=0;
k=strlen(c);
qsort(c,k,sizeof(c[0]),cmp);
for(i=0,j=1; i<k; i++)
{
if(c[i]!=c[j])
{
j++;
s++;
}
else
{
j++;
}
}
if(s%2==0)
{
cout<<"CHAT WITH HER!"<<endl;
}
else
cout<<"IGNORE HIM!"<<endl;
memset(c,'\0',sizeof(c));
}
return 0;
}
版权声明:本文博客原创文章,博客,未经同意,不得转载。
codeforces 236A . Boy or Girl(串水问题)的更多相关文章
- 『NYIST』第八届河南省ACM竞赛训练赛[正式赛一]-CodeForces 236A,虽然很水,但有一个很简单的函数用起来方便
A. Boy or Girl time limit per test 1 second memory limit per test 256 megabytes input standard input ...
- Educational Codeforces Round 7 B. The Time 水题
B. The Time 题目连接: http://www.codeforces.com/contest/622/problem/B Description You are given the curr ...
- Educational Codeforces Round 7 A. Infinite Sequence 水题
A. Infinite Sequence 题目连接: http://www.codeforces.com/contest/622/problem/A Description Consider the ...
- Codeforces Testing Round #12 A. Divisibility 水题
A. Divisibility Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/597/probl ...
- Codeforces Beta Round #37 A. Towers 水题
A. Towers 题目连接: http://www.codeforces.com/contest/37/problem/A Description Little Vasya has received ...
- Codeforces Round #394 (Div. 2)A水 B暴力 C暴力 D二分 E dfs
A. Dasha and Stairs time limit per test 2 seconds memory limit per test 256 megabytes input standard ...
- Codeforces Round #169 (Div. 2) A水 B C区间更新 D 思路
A. Lunch Rush time limit per test 2 seconds memory limit per test 256 megabytes input standard input ...
- codeforces 712B B. Memory and Trident(水题)
题目链接: B. Memory and Trident time limit per test 2 seconds memory limit per test 256 megabytes input ...
- codeforces 712A A. Memory and Crow(水题)
题目链接: A. Memory and Crow time limit per test 2 seconds memory limit per test 256 megabytes input sta ...
随机推荐
- javamail发送邮件(转)
今天学习了一下JavaMail,javamail发送邮件确实是一个比较麻烦的问题.为了以后使用方便,自己写了段代码,打成jar包,以方便以后使用.呵呵 以下三段代码是我的全部代码,朋友们如果想用,直接 ...
- apache2.4.4启用deflate压缩
今天在看<高性能php应用开发>这本书,说道如何启用mod_deflate: 启用如下模块: LoadModule deflate_module modules/mod_deflate.s ...
- 使用psftp.exe
使用psftp.exe 点击打开psftp.exe,出现如下图的命令窗口.
- 黄聪:Microsoft Enterprise Library 5.0 系列教程(七) Exception Handling Application Block
原文:黄聪:Microsoft Enterprise Library 5.0 系列教程(七) Exception Handling Application Block 使用企业库异常处理应用程序模块的 ...
- bellman_ford寻找平均权值最小的回路
给定一个有向图,如果存在平均值最小的回路,输出平均值. 使用二分法求解,对于一个猜测值mid,判断是否存在平均值小于mid的回路 如果存在平均值小于mid的包含k条边的回路,那么有w1+w2+w3+. ...
- session与cookie的差别
session session 的工作机制是:为每一个訪客创建一个唯一的 id (UID),并基于这个 UID 来存储变量.UID 存储在 cookie 中,或者通过 URL 进行传导. ...
- elasticsearch2.2
elasticsearch2.2 集群搭建各种坑 目前生产环境的es版本是1.0版本,需要升级到最新的2.2版本,于是在测试环境进行部署集群测试,在测试过程中遇到的坑相当多,下面详细介绍下. ...
- OPENVPN开启用户password认证
一.服务端配置 1.改动openvpn的主配置文件,加入例如以下内容 [root@ttt openvpn]# cat /etc/openvpn/server.conf |more #########a ...
- C++ map简单运用
#include <iostream> #include <string> #include <map> using namespace std; typedef ...
- linux下安装oracle11g 64位最简客户端(转)
安装环境 Linux服务器:SuSe11 sp1 64位 Oracle客户端:Oracle11gR2 64位(最简客户端) 部署流程 1.准备工作,首先在oracle官网下载最新的 ...