mysql 求分组中位数、环比、同比、中位数的环比
说明
中位数、环比、同比概念请自行百度，本文求 字段A中位数、根据字段B分组后字段A中位数、字段A环比、字段A同比、字段A中位数的环比、字段A中位数的同比。
一、表结构如下图
查询条件为 capital_name in （'金融机构1','金融机构2'），以下查询的中位数、环比等都基于此条件；
二、求【最终金额】的【中位数】
中位数主要是利用临时变量查询，且一个sql只能查询一个字段的中位数，下面的sql对中位数做保留2位小数点处理
1 SELECT
2 @max_row_number := max( row_number ),
3 ROUND( ( CASE MOD ( @max_row_number, 2 )
4 WHEN 0 THEN ( sum( IF ( row_number = FLOOR( @max_row_number / 2 ) OR row_number = FLOOR( @max_row_number / 2 ) + 1, final_app_amount, 0 )) / 2 )
5 WHEN 1 THEN SUM( IF ( row_number = FLOOR( @max_row_number / 2 ) + 1, final_app_amount, 0 )) END
6 ), 2 ) AS final_app_amount_median
7 FROM
8 (
9 SELECT
10 final_app_amount,
11 @rank AS row_number,
12 @rank := @rank + 1
13 FROM repay_customer AS t1,
14 ( SELECT @rank := 1 ) t2
15 WHERE
16 1 = 1 AND capital_name IN ( '金融机构1', '金融机构2' )
17 ORDER BY final_app_amount
18 ) t3,
19 ( SELECT @max_row_number := 0 ) t4
三、求【最终金额】的【分组中位数】
即根据时间，计算每月的最终金额的中位数，对结果做保留2位小数处理
1 SELECT
2 group_index,
3 loan_time_credit,
4 CASE MOD ( count(*), 2 )
5 WHEN 0 THEN ROUND( ( sum( IF ( rank = FLOOR( group_count / 2 ) OR rank = FLOOR( group_count / 2 ) + 1, final_app_amount, 0 )) / 2 ), 2 )
6 WHEN 1 THEN ROUND( ( SUM( IF ( rank = FLOOR( group_count / 2 ) + 1, final_app_amount, 0 ) ) ), 2 )
7 END AS final_app_amount_median
8 FROM
9 (
10 SELECT
11 t3.*,
12 @group_count := CASE WHEN @last_group_index = group_index THEN @group_count ELSE rank END AS group_count,
13 @last_group_index := group_index
14 FROM
15 (
16 SELECT
17 CONCAT( DATE_FORMAT( loan_time_credit, '%Y-%m' ) ) AS group_index,
18 DATE_FORMAT( loan_time_credit, '%Y-%m' ) AS loan_time_credit,
19 final_app_amount AS final_app_amount,
20 @rank := CASE WHEN @last_group = CONCAT( DATE_FORMAT( loan_time_credit, '%Y-%m' ) ) THEN @rank + 1 ELSE 1 END AS rank,
21 @last_group := CONCAT( DATE_FORMAT( loan_time_credit, '%Y-%m' ))
22 FROM
23 repay_customer AS t1,
24 ( SELECT @group_count := 0, @rank := 0 ) t2
25 WHERE
26 1 = 1 AND capital_name IN ( '金融机构1', '金融机构2' )
27 ORDER BY
28 loan_time_credit,
29 final_app_amount
30 ) t3,
31 ( SELECT @group_count := 0, @last_group_index := 0 ) t4
32 ORDER BY
33 group_index,
34 rank DESC
35 ) t5
36 GROUP BY
37 group_index
四、求【最终金额】和【合同金额】的环比
环比一般以月为分组条件，求环比的分组字段必须为时间字段，且只有一个时间字段；
以下sql求每月 “最终金额“ 的“和“ 的环比增长量、增长率， 和 每月 “合同金额“ 的 “平均值” 的环比增长量、增长率；
【注】此sql中计算了sum的环比和avg的环比，同理可换成 min、max，count 等；
注意：此sql思路为根据查询条件计算出目标数据的最小时间和最大时间，罗列此区间内的所有月，再匹配分组后结果，例如， 2021-11 月里没有 金融机构1和金融机构2的数据，但结果中依然后 2021-11 这一行，目的是为了更明显的与上个月做对比；
对结果做保留2位小数点处理；
1 SELECT
2 t3.group_index,
3 t3.group_index AS loan_time_credit,
4 ROUND( ( ( t3.final_app_amount_sum_growth - last_final_app_amount_sum_growth )/ last_final_app_amount_sum_growth ), 2 ) AS final_app_amount_sum_rises,
5 ROUND( ( ( t3.contract_amount_avg_growth - last_contract_amount_avg_growth )/ last_contract_amount_avg_growth ), 2 ) AS contract_amount_avg_rises,
6 ROUND( ( t3.final_app_amount_sum_growth - t3.last_final_app_amount_sum_growth ), 2 ) AS final_app_amount_sum_growth,
7 ROUND( ( t3.contract_amount_avg_growth - t3.last_contract_amount_avg_growth ), 2 ) AS contract_amount_avg_growth
8 FROM
9 (
10 SELECT
11
12 @last_final_app_amount_sum_growth := CASE WHEN @last_group_index != group_index THEN @last_final_app_amount_sum_growth ELSE t1.final_app_amount_sum_growth END AS last_final_app_amount_sum_growth,
13 @last_contract_amount_avg_growth := CASE WHEN @last_group_index != group_index THEN @last_contract_amount_avg_growth ELSE t1.contract_amount_avg_growth END AS last_contract_amount_avg_growth,
14 t1.*,
15 @last_group_index := group_index,
16 @last_final_app_amount_sum_growth := t1.final_app_amount_sum_growth,
17 @last_contract_amount_avg_growth := t1.contract_amount_avg_growth
18 FROM
19 (select @start_date := (select min(loan_time_credit) from repay_customer where 1=1 and capital_name IN ( '金融机构1', '金融机构2' )),
20 @end_date := (select max(loan_time_credit) from repay_customer where 1=1 and capital_name IN ( '金融机构1', '金融机构2' ))) t4 ,
21 (
22 SELECT
23 group_index,
24 final_app_amount_sum_growth,
25 contract_amount_avg_growth
26 FROM
27 (
28 SELECT
29 DATE_FORMAT( date_sub( @start_date, INTERVAL ( @i := @i - 1 ) MONTH ), '%Y-%m' ) AS group_index
30 FROM
31 mysql.help_topic
32 JOIN ( SELECT @i := 1 ) c
33 WHERE
34 help_topic_id <= (
35 TIMESTAMPDIFF( MONTH, @start_date,@end_date))
36 ) dateI
37 LEFT JOIN (
38 SELECT
39 DATE_FORMAT( loan_time_credit, '%Y-%m' ) AS loan_time_credit,
40 sum( final_app_amount ) AS final_app_amount_sum_growth,
41 avg( contract_amount ) AS contract_amount_avg_growth
42 FROM
43 repay_customer
44 WHERE
45 1 = 1
46 AND capital_name IN ( '金融机构1', '金融机构2' )
47 GROUP BY
48 DATE_FORMAT( loan_time_credit, '%Y-%m' )) dataA ON dateI.group_index = dataA.loan_time_credit
49 ) t1,(
50 SELECT
51 @last_group_index := 0,
52 @last_final_app_amount_sum_growth := 0,
53 @last_contract_amount_avg_growth := 0
54 ) t2
55 ) t3
五、求【最终金额】和【合同金额】的同比
同比一般与上一年比较，求同比的分组字段必须为时间字段，且只有一个时间字段；
以下sql求每月 “最终金额“ 的“和“ 的同比增长量、增长率， 和 每月 “合同金额“ 的 “平均值” 的同比增长量、增长率；
【注】此sql中计算了sum的同比和avg的同比，同理可换成 min、max，count 等；
注意：此sql思路为根据查询条件计算出目标数据的最小时间和最大时间，罗列此区间内的所有月，再匹配分组后结果，例如， 2021-11 月里没有 金融机构1和金融机构2的数据，但结果中依然后 2021-11 这一行，目的是为了更明显的与上个月做对比；
对结果做保留2位小数点处理；
1 SELECT
2 t1.group_index,
3 t1.group_index AS loan_time_credit,
4 ROUND( ( ( t2.final_app_amount_sum_growth - t3.final_app_amount_sum_growth )/ t3.final_app_amount_sum_growth ), 2 ) AS final_app_amount_sum_rises,
5 ROUND( ( ( t2.contract_amount_avg_growth - t3.contract_amount_avg_growth )/ t3.contract_amount_avg_growth ), 2 ) AS contract_amount_avg_rises,
6 t2.final_app_amount_sum_growth - t3.final_app_amount_sum_growth AS final_app_amount_sum_growth,
7 t2.contract_amount_avg_growth - t3.contract_amount_avg_growth AS contract_amount_avg_growth
8 FROM
9 (select @start_date := (select min(loan_time_credit) from repay_customer where 1=1 and capital_name IN ( '华夏银行', '蓝海银行', '中金租' )),
10 @end_date := (select max(loan_time_credit) from repay_customer where 1=1 and capital_name IN ( '华夏银行', '蓝海银行', '中金租' ))) t4 ,
11 (
12 SELECT
13 DATE_FORMAT( date_sub( @start_date, INTERVAL ( @i := @i - 1 ) MONTH ), '%Y-%m' ) AS group_index
14 FROM
15 mysql.help_topic
16 JOIN ( SELECT @i := 1 ) c
17 WHERE
18 help_topic_id <= (
19 TIMESTAMPDIFF( MONTH, @start_date, @end_date) )
20 ) t1
21 LEFT JOIN (
22 SELECT
23 DATE_FORMAT( loan_time_credit, '%Y-%m' ) AS group_index,
24 DATE_FORMAT( DATE_ADD( loan_time_credit, INTERVAL - 1 YEAR ), '%Y-%m' ) AS last_group_index,
25 sum( final_app_amount ) AS final_app_amount_sum_growth,
26 avg( contract_amount ) AS contract_amount_avg_growth
27 FROM
28 repay_customer
29 WHERE
30 1 = 1
31 AND capital_name IN ( '华夏银行', '蓝海银行', '中金租' )
32 GROUP BY
33 DATE_FORMAT( loan_time_credit, '%Y-%m' )
34 ) t2 ON t1.group_index = t2.group_index
35 LEFT JOIN (
36 SELECT
37 DATE_FORMAT( loan_time_credit, '%Y-%m' ) AS group_index,
38 sum( final_app_amount ) AS final_app_amount_sum_growth,
39 avg( contract_amount ) AS contract_amount_avg_growth
40 FROM
41 repay_customer
42 WHERE
43 1 = 1
44 AND capital_name IN ( '华夏银行', '蓝海银行', '中金租' )
45 AND loan_time_credit >= DATE_ADD( @start_date, INTERVAL - 1 YEAR )
46 AND loan_time_credit <= DATE_ADD( @end_date, INTERVAL - 1 YEAR )
47 GROUP BY
48 DATE_FORMAT( loan_time_credit, '%Y-%m' )
49 ) t3 ON t2.last_group_index = t3.group_index
六、求【最终金额】中位数的环比
分组字段只能为时间且只有一个；
一个sql只能查一个字段的中位数；
对结果做保留2位小数点处理；
1 SELECT
2 t3.group_index,
3 t3.group_index AS loan_time_credit,
4 ROUND( ( t3.final_app_amount - t3.last_final_app_amount ), 2 ) AS final_app_amount_median_growth,
5 ROUND( ( ( t3.final_app_amount - last_final_app_amount )/ last_final_app_amount ), 2 ) AS final_app_amount_median_rises
6 FROM
7 (
8 SELECT
9 @last_final_app_amount := CASE WHEN @last_group_index != group_index THEN @last_final_app_amount ELSE t1.final_app_amount END AS last_final_app_amount,
10 t1.*,
11 @last_group_index := group_index,
12 @last_final_app_amount := t1.final_app_amount
13 FROM
14 (
15 SELECT
16 dateI.group_index,
17 final_app_amount
18 FROM
19 (select @start_date := (select min(loan_time_credit) from repay_customer where 1=1 and capital_name IN ( '金融机构1', '金融机构2')),
20 @end_date := (select max(loan_time_credit) from repay_customer where 1=1 and capital_name IN ( '金融机构1', '金融机构2' ))) t4 ,
21 (
22 SELECT
23 DATE_FORMAT( date_sub( @start_date, INTERVAL ( @i := @i - 1 ) MONTH ), '%Y-%m' ) AS group_index
24 FROM
25 mysql.help_topic
26 JOIN ( SELECT @i := 1 ) c
27 WHERE
28 help_topic_id <= (
29 TIMESTAMPDIFF( MONTH, @start_date, @end_date ))
30 ) dateI
31 LEFT JOIN (
32 SELECT
33 group_index,
34 CASE
35 MOD ( count(*), 2 )
36 WHEN 0 THEN
37 (
38 sum(
39 IF
40 ( rank = FLOOR( group_count / 2 ) OR rank = FLOOR( group_count / 2 ) + 1, final_app_amount, 0 )) / 2
41 )
42 WHEN 1 THEN
43 SUM(
44 IF
45 ( rank = FLOOR( group_count / 2 ) + 1, final_app_amount, 0 ))
46 END AS final_app_amount
47 FROM
48 (
49 SELECT
50 t3.*,
51 @group_count :=
52 CASE
53
54 WHEN @last_group_index = group_index THEN
55 @group_count ELSE rank
56 END AS group_count,
57 @last_group_index := group_index
58 FROM
59 (
60 SELECT
61 DATE_FORMAT( loan_time_credit, '%Y-%m' ) AS group_index,
62 final_app_amount AS final_app_amount,
63 @rank :=
64 CASE
65
66 WHEN @last_group = DATE_FORMAT( loan_time_credit, '%Y-%m' ) THEN
67 @rank + 1 ELSE 1
68 END AS rank,
69 @last_group := DATE_FORMAT( loan_time_credit, '%Y-%m' )
70 FROM
71 repay_customer AS t1,
72 ( SELECT @group_count := 0, @rank := 0 ) t2
73 WHERE
74 1 = 1 AND capital_name IN ( '金融机构1', '金融机构2' )
75 ORDER BY
76 loan_time_credit,
77 final_app_amount
78 ) t3,
79 ( SELECT @group_count := 0, @last_group_index := 0 ) t4
80 ORDER BY
81 group_index,
82 rank DESC
83 ) t5
84 GROUP BY
85 group_index
86 ) dataA ON dateI.group_index = dataA.group_index
87 ) t1,(
88 SELECT
89 @last_group_index := 0,
90 @last_final_app_amount := 0
91 ) t2
92 ) t3
七、求【最终金额】中位数的同比
分组字段只能为时间且只有一个；
一个sql只能查一个字段的中位数；
对结果做保留2位小数点处理；
1 SELECT
2 t1.group_index,
3 t1.group_index AS loan_time_credit,
4 ROUND( ( t2.final_app_amount - t3.final_app_amount ), 2 ) AS final_app_amount_median_growth,
5 ROUND( ( ( t2.final_app_amount - t3.final_app_amount )/ t3.final_app_amount ), 2 ) AS final_app_amount_median_rises
6 FROM
7 (select @start_date := (select min(loan_time_credit) from repay_customer where 1=1 and capital_name IN ( '金融机构1', '金融机构2' )),
8 @end_date := (select max(loan_time_credit) from repay_customer where 1=1 and capital_name IN ('金融机构1', '金融机构2' ))) t4 ,
9 (
10 SELECT
11 DATE_FORMAT( date_sub( @start_date, INTERVAL ( @i := @i - 1 ) YEAR ), '%Y-%m' ) AS group_index
12 FROM
13 mysql.help_topic
14 JOIN ( SELECT @i := 1 ) c
15 WHERE
16 help_topic_id <= (
17 TIMESTAMPDIFF( MONTH, @start_date, @end_date ))
18 ) t1
19 LEFT JOIN (
20 SELECT
21 group_index,
22 last_year_group_index,
23 CASE MOD ( count(*), 2 ) WHEN 0 THEN sum( IF ( rank = FLOOR( group_count / 2 ) OR rank = FLOOR( group_count / 2 ) + 1, final_app_amount, 0 )) / 2
24 WHEN 1 THEN SUM( IF ( rank = FLOOR( group_count / 2 ) + 1, final_app_amount, 0 )) END AS final_app_amount
25 FROM
26 (
27 SELECT
28 t3.*,
29 @group_count :=
30 CASE
31
32 WHEN @last_group_index = group_index THEN
33 @group_count ELSE rank
34 END AS group_count,
35 @last_group_index := group_index
36 FROM
37 (
38 SELECT
39 DATE_FORMAT( loan_time_credit, '%Y-%m' ) AS group_index,
40 DATE_FORMAT( DATE_ADD( loan_time_credit, INTERVAL - 1 MONTH ), '%Y-%m' ) AS last_year_group_index,
41 final_app_amount,
42 @rank := CASE WHEN @last_group = DATE_FORMAT( loan_time_credit, '%Y-%m' ) THEN @rank + 1 ELSE 1 END AS rank,
43 @last_group := DATE_FORMAT( loan_time_credit, '%Y-%m' )
44 FROM
45 repay_customer AS t1,
46 ( SELECT @group_count := 0, @rank := 0 ) t2
47 WHERE
48 1 = 1 AND capital_name IN ( '金融机构1', '金融机构2' )
49 ORDER BY
50 loan_time_credit,
51 final_app_amount
52 ) t3,
53 ( SELECT @group_count := 0, @last_group_index := 0 ) t4
54 ORDER BY
55 group_index,
56 rank DESC
57 ) t5
58 GROUP BY
59 group_index
60 ) t2 ON t1.group_index = t2.group_index
61 LEFT JOIN (
62 SELECT
63 group_index,
64 CASE MOD ( count(*), 2 )
65 WHEN 0 THEN sum( IF ( rank = FLOOR( group_count / 2 ) OR rank = FLOOR( group_count / 2 ) + 1, final_app_amount, 0 )) / 2
66 WHEN 1 THEN SUM( IF ( rank = FLOOR( group_count / 2 ) + 1, final_app_amount, 0 ))
67 END AS final_app_amount
68 FROM
69 (
70 SELECT
71 t3.*,
72 @group_count := CASE WHEN @last_group_index = group_index THEN @group_count ELSE rank END AS group_count,
73 @last_group_index := group_index
74 FROM
75 (
76 SELECT
77 DATE_FORMAT( loan_time_credit, '%Y-%m' ) AS group_index,
78 final_app_amount,
79 @rank := CASE WHEN @last_group = DATE_FORMAT( loan_time_credit, '%Y-%m' ) THEN @rank + 1 ELSE 1 END AS rank,
80 @last_group := DATE_FORMAT( loan_time_credit, '%Y-%m' )
81 FROM
82 repay_customer AS t1,
83 ( SELECT @group_count := 0, @rank := 0 ) t2
84 WHERE
85 1 = 1 AND capital_name IN ('金融机构1', '金融机构2' )
86 AND loan_time_credit >= DATE_ADD( @start_date, INTERVAL - 1 YEAR )
87 AND loan_time_credit <= DATE_ADD( @end_date, INTERVAL - 1 YEAR )
88 ORDER BY
89 loan_time_credit,
90 final_app_amount
91 ) t3,
92 ( SELECT @group_count := 0, @last_group_index := 0 ) t4
93 ORDER BY
94 group_index,
95 rank DESC
96 ) t5
97 GROUP BY
98 group_index
99 ) t3 ON t2.last_year_group_index = t3.group_index
八 完
太不容易了我！
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