Collective Mindsets (easy)

Time Limit:1000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u

Description

Tonight is brain dinner night and all zombies will gather together to scarf down some delicious brains. The artful Heidi plans to crash the party, incognito, disguised as one of them. Her objective is to get away with at least one brain, so she can analyze the zombies' mindset back home and gain a strategic advantage.They will be N guests tonight: N - 1 real zombies and a fake one, our Heidi. The living-dead love hierarchies as much as they love brains: each one has a unique rank in the range 1 to N - 1, and Heidi, who still appears slightly different from the others, is attributed the highest rank, N. Tonight there will be a chest with brains on display and every attendee sees how many there are. These will then be split among the attendees according to the following procedure:The zombie of the highest rank makes a suggestion on who gets how many brains (every brain is an indivisible entity). A vote follows. If at least half of the attendees accept the offer, the brains are shared in the suggested way and the feast begins. But if majority is not reached, then the highest-ranked zombie is killed, and the next zombie in hierarchy has to make a suggestion. If he is killed too, then the third highest-ranked makes one, etc. (It's enough to have exactly half of the votes – in case of a tie, the vote of the highest-ranked alive zombie counts twice, and he will of course vote in favor of his own suggestion in order to stay alive.)You should know that zombies are very greedy and sly, and they know this too – basically all zombie brains are alike. Consequently, a zombie will never accept an offer which is suboptimal for him. That is, if an offer is not strictly better than a potential later offer, he will vote against it. And make no mistake: while zombies may normally seem rather dull, tonight their intellects are perfect. Each zombie's priorities for tonight are, in descending order:
  1. survive the event (they experienced death already once and know it is no fun),
  2. get as many brains as possible.

Heidi goes first and must make an offer which at least half of the attendees will accept, and which allocates at least one brain for Heidi herself.What is the smallest number of brains that have to be in the chest for this to be possible?

Input

The only line of input contains one integer: N, the number of attendees (1 ≤ N ≤ 109).
Output

Output one integer: the smallest number of brains in the chest which allows Heidi to take one brain home.
Sample Input

Input
1
Output
1
Input
4
Output
2
 
有 n - 1 个僵尸,1 个是主角 hedi ,他们在一起分大脑。。。n 个人都是有个独特的等级的,让等级最高的人来决定分配大脑的方案,如果没有半数以上的僵尸同意,等级最高的就会死,让低一个等级的僵尸去决定分配方案,如此分直到有半数以上僵尸同意,僵尸是非常狡猾的,且非常聪明,他们怕死,但在不死的前提下想获得更多的大脑。现在heidi是等级最高的,他自己想带走一个大脑,问最少需要多少大脑。
//海盗分金问题,看似简单,但是,细思恐极。。。找的是规律,这题还简单,下题才难想
 #include <stdio.h>
int main()
{
int n;
while (scanf("%d",&n)!=EOF)
{
if (n%==)
printf("%d\n",n/);
else
printf("%d\n",n/+);
}
return ;
}

Collective Mindsets (easy)(逻辑题)的更多相关文章

  1. Collective Mindsets (medium) (逻辑题)

    B - Collective Mindsets (medium) Time Limit:1000MS     Memory Limit:262144KB     64bit IO Format:%I6 ...

  2. 2014百度之星资格赛 1001:Energy Conversion(水题,逻辑题)

    Energy Conversion Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others ...

  3. Java面试题精选(三) JSP/Servlet Java面试逻辑题

    --   JSP/Servlet  Java面试逻辑题   --     很显然,Servlet/JSP的WEB前端动态制作的重要性比HTML/CSS/JS的价值高很多,但我们都知道他们都是建立在HT ...

  4. Sql面试题之四(难度:中等 | 含答案 | 有逻辑题)

    Sql面试题之四(难度:中等 | 含答案 | 有逻辑题)

  5. 数据库表设计时一对一关系存在的必要性 数据库一对一、一对多、多对多设计 面试逻辑题3.31 sql server 查询某个表被哪些存储过程调用 DataTable根据字段去重 .Net Core Cors中间件解析 分析MySQL中哪些情况下数据库索引会失效

    数据库表设计时一对一关系存在的必要性 2017年07月24日 10:01:07 阅读数:694 在表设计过程中,我无意中觉得一对一关系觉得好没道理,直接放到一张表中不就可以了吗?真是说,网上信息什么都 ...

  6. php 逻辑题

    越长大约发现,高中学的数学,都还给了数学老师,一点都没有留住. 最近遇到了一个 逻辑题,然后想了半天,后来做出来了,我就发现了,我可能是一个假的理科生.很简单的样子. 废话不说,看看这道题吧. /** ...

  7. PJzhang:一道看线索找答案的逻辑题

    猫宁!!! 这道逻辑题,2年前就有打算解决,但是没上心,今天抽空梳理出来了思路,逻辑上可以跑的通,不至于以后慢慢忘了,这道题和数独题基本类似,但是也许更花时间,做这种题最好看着线索列图标,省的不停翻页 ...

  8. python基础之逻辑题(3)

    Python基础之逻辑题(3) 1.编写一个函数实现将IP地址转换成一个整数 2.求结果:---lambda 3.求a的结果 4.求下面nums的输出 5.求下面片段的输出 6.写出程序的结果:--- ...

  9. python基础之逻辑题(2)

    python基础之逻辑题(2) 1.若k为整数,下列while循环执行的次数为? 2.请输出正确结果-----numbers? 3.求结果-----math?   4.求结果-----sum? 5.输 ...

随机推荐

  1. Java:网络编程之登陆服务器

    1. 客服端:浏览器(telnet) 服务端:自定义 2. 客服端:浏览器 服务端:TomCat服务器 3. 客服端:自定义 服务端:TomCat服务器   //例子如下: import java.n ...

  2. 2017.3.31 spring mvc教程(七)多视图控制器

    学习的博客:http://elf8848.iteye.com/blog/875830/ 我项目中所用的版本:4.2.0.博客的时间比较早,11年的,学习的是Spring3 MVC.不知道版本上有没有变 ...

  3. 2017.3.31 spring mvc教程(二)核心流程及配置详解

    学习的博客:http://elf8848.iteye.com/blog/875830/ 我项目中所用的版本:4.2.0.博客的时间比较早,11年的,学习的是Spring3 MVC.不知道版本上有没有变 ...

  4. D3学习之:D3.js中的12中地图投影方式

    特别感谢:1.[张天旭]的D3API汉化说明.已被引用到官方站点: 2.[馒头华华]提供的ourd3js.com上提供的学习系列教程,让我们这些新人起码有了一个方向. 不得不说,学习国外的新技术真的是 ...

  5. easyui datagrid 批量编辑和提交数据

    easyui datagrid 行编辑和提交方,废话就不多说了,直接上代码 <div style="margin: 5px;"> <table id=" ...

  6. Mac OSX下编译安装PostgreSQL

    原先使用的是官方提供的安装包,可是安装包会创建postgre这个用户.在登陆界面看的有点不爽,搜索了半天居然没有找到怎样在osx下编译安装的教程,并且假设是依照官方文档的编译安装办法一定会让你崩溃,本 ...

  7. SurfaceView实现拍照预览

    一.布局代码 <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:andro ...

  8. NinePatch

    将图片保存为扩展名为.9.png的格式直接放入Android Studio中的drawable文件夹,拖拉选择拉伸区域,如下图,即可制作出可拉伸背景

  9. 怎样彻底清除UniAccess Agent

    怎样彻底清除UniAccess Agent 作者:chszs.转载需注明. 博客主页:http://blog.csdn.net/chszsUniAccess Agent是联软科技公司推出的一款企业网络 ...

  10. android中依据不同分辨率dp和px的相互转算

    public class PxAndDp { /** * 依据手机的分辨率从 dp 的单位 转成为 px(像素) */ public static int dip2px(Context context ...