thinkphp mysql 坐标按距离排序

$cha1 = new Model();
$shops = $cha1->query("select *,(2 * 6378.137* ASIN(SQRT(POW(SIN(3.1415926535898*(".$lat."-lat)/360),2)+COS(3.1415926535898*".$lat."/180)* COS(lat * 3.1415926535898/180)*POW(SIN(3.1415926535898*(".$lng."-lng)/360),2))))*1000 as juli from `wifi_shop`
 where shoplevel like '%".$type."%' and province = '".$_SESSION['shop']['province']."' and city = '".$_SESSION['shop']['city']."' order by juli asc limit ".$Page->firstRow.",".$Page->listRows);
        

代码中$lat和$lng就是已知的那个坐标的经纬度,排序出来的单位是米因为我乘以1000了,where后面的查询条件可以根据需要编辑,limit后面是分页的,可以不要或者自己编辑

然后php代码中计算出两个坐标点距离的方法是,这个方法也是返回的单位米

function GetDistance($lat1, $lng1, $lat2, $lng2){
        define('PI',3.1415926535898);
        define('EARTH_RADIUS',6378.137);
        $radLat1 = $lat1 * (PI / 180);
        $radLat2 = $lat2 * (PI / 180);

        $a = $radLat1 - $radLat2;
        $b = ($lng1 * (PI / 180)) - ($lng2 * (PI / 180)); 

        $s = 2 * asin(sqrt(pow(sin($a/2),2) + cos($radLat1)*cos($radLat2)*pow(sin($b/2),2)));
        $s = $s * EARTH_RADIUS;
        $s = round($s * 10000) / 10000;
        return $s*1000;
    }