/*
** 算法的思路:
** 1.将k个链表的首元素进行建堆
** 2.从堆中取出最小的元素,放到链表中
** 3.如果取出元素的有后续的元素,则放入堆中,若没有则转步骤2,直到堆为空
*/ #include <stdio.h> struct ListNode
{
int val;
struct ListNode *next;
}; #define PARENT(i) (((i)-1)/2)
#define LEFT(i) ((i)*2+1)
#define RIGHT(i) ((i)*2+2) typedef struct ListNode * ListNodePointer; void MinHeapify(ListNodePointer lists[], int nListSize, int nParentIndex );
void BuildMinHeap(ListNodePointer lists[], int nListSize );
ListNodePointer ExtractMin( ListNodePointer lists[], int *pListSize );
void InsertHeap(ListNodePointer lists[], int *pListSize, ListNodePointer pNode );
struct ListNode* mergeKLists(struct ListNode** lists, int listsSize); int main(int argc, char const *argv[])
{ struct ListNode list[] = {{.next=NULL,.val=}, {.next=NULL, .val=-}};
ListNodePointer pListPointerArray[] = {&list[], NULL, &list[]}; ListNodePointer header = mergeKLists(pListPointerArray, ); ListNodePointer pList = header;
while( NULL != pList )
{
printf("%d ", pList->val);
pList = pList->next;
}
printf("\n"); return ;
} void MinHeapify(ListNodePointer lists[], int nListSize, int nParentIndex )
{ int nLeftIndex; //左节点下标
int nRightIndex; //右节点下标
int nMinIndex; //最小节点下标
ListNodePointer pNodePtrTmp; do
{
nLeftIndex = LEFT(nParentIndex);
nRightIndex = RIGHT(nParentIndex);
nMinIndex = nParentIndex; if ( nLeftIndex < nListSize && lists[nLeftIndex]->val < lists[nMinIndex]->val )
{
nMinIndex = nLeftIndex;
} if ( nRightIndex < nListSize && lists[nRightIndex]->val < lists[nMinIndex]->val )
{
nMinIndex = nRightIndex;
} if ( nMinIndex != nParentIndex )
{
pNodePtrTmp = lists[nMinIndex];
lists[nMinIndex] = lists[nParentIndex];
lists[nParentIndex] = pNodePtrTmp; nParentIndex = nMinIndex; }else
{
break;
} }while( );
} //建堆
void BuildMinHeap(ListNodePointer lists[], int nListSize )
{ int i;
for ( i = nListSize/; i >= ; i-- )
{
MinHeapify(lists, nListSize, i);
}
} //从堆中取出最小的元素
ListNodePointer ExtractMin( ListNodePointer lists[], int *pListSize )
{ ListNodePointer pMinNode = lists[]; (*pListSize)--;
lists[] = lists[*pListSize]; MinHeapify(lists, *pListSize, ); return pMinNode;
} //向堆中添加元素
void InsertHeap(ListNodePointer lists[], int *pListSize, ListNodePointer pNode )
{ int nCurNodeIndex = *pListSize;
int nParentIndex = PARENT(nCurNodeIndex);
ListNodePointer pNodePtrTmp; lists[nCurNodeIndex] = pNode;
(*pListSize)++; while ( nCurNodeIndex > && lists[nParentIndex]->val > lists[nCurNodeIndex]->val )
{
pNodePtrTmp = lists[nParentIndex];
lists[nParentIndex] = lists[nCurNodeIndex];
lists[nCurNodeIndex] = pNodePtrTmp; nCurNodeIndex = nParentIndex;
nParentIndex = PARENT(nCurNodeIndex);
}
} struct ListNode* mergeKLists(struct ListNode** lists, int listsSize)
{ ListNodePointer *pListPointerArray = (ListNodePointer *) malloc( sizeof(ListNodePointer)*listsSize );
struct ListNode header = {.next=NULL};
ListNodePointer pTail = NULL; int i;
int nHeapSize = ; for( i=; i<listsSize; i++ )
{
if ( lists[i] != NULL )
{
pListPointerArray[nHeapSize] = lists[i];
nHeapSize++;
}
} if ( nHeapSize == )
{
return NULL;
} BuildMinHeap(pListPointerArray, nHeapSize); //这里为预处理
header.next = ExtractMin(pListPointerArray, &nHeapSize);
pTail = header.next;
if ( NULL != pTail && pTail->next != NULL )
{
InsertHeap(pListPointerArray, &nHeapSize, pTail->next );
} while( nHeapSize != )
{
pTail->next = ExtractMin(pListPointerArray, &nHeapSize); pTail = pTail->next; if ( NULL != pTail && NULL != pTail->next )
{
InsertHeap(pListPointerArray, &nHeapSize, pTail->next );
}
} free(pListPointerArray); return header.next;
}

LeetCode —— Merge k Sorted Lists的更多相关文章

  1. LeetCode: Merge k Sorted Lists 解题报告

    Merge k Sorted Lists Merge k sorted linked lists and return it as one sorted list. Analyze and descr ...

  2. [LeetCode] Merge k Sorted Lists 合并k个有序链表

    Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 这 ...

  3. LeetCode:Merge k Sorted Lists

    题目链接 Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexi ...

  4. LeetCode——Merge k Sorted Lists

    Discription: Merge k sorted linked lists and return it as one sorted list. Analyze and describe its ...

  5. leetcode -- Merge k Sorted Lists add code

    Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. [ ...

  6. LeetCode Merge k Sorted Lists (链表)

    题意 Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity ...

  7. [Leetcode] Merge k sorted lists 合并k个已排序的链表

    Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 思 ...

  8. Leetcode:Merge k Sorted Lists分析和实现

    题目大意是传入一个链表数组lists,每个链表都由若干个链接的链表结点组成,并且每个链表结点记录一个整数.题目保证传入的链表中的整数按从小到大进行排序. 题目要求我们输出一个新的链表,这个链表中应该包 ...

  9. LeetCode Merge k Sorted Lists 解决报告

    https://oj.leetcode.com/problems/merge-k-sorted-lists/ 归并K已经整理阵列,和分析算法的复杂. 解决报告:无论是不考虑优化,最简单的实现是要重新走 ...

随机推荐

  1. 【BZOJ 4547】【HDU 5157】小奇的集合

    http://www.lydsy.com/JudgeOnline/problem.php?id=4547 本蒟蒻并不会矩乘求Fibonacci数列前缀和,所以果断分块打表,常数竟然比矩乘要小! PS: ...

  2. 【POJ 1151】Atlantis

    离散化后扫描线扫一遍. 夏令营时gty学长就讲过扫描线,可惜当时too naive,知道现在才写出模板题. 当时也不会线段树啊233 #include<cstdio> #include&l ...

  3. 网络流 poj 2135

    n个点 m条边 给m条边 求1->n n->1 最小花费,每条边最多走一次 两个最短路显然不行 会影响另外一条 #include<stdio.h> #include<al ...

  4. NHibernate中session.update()及session.merge()的区别

    今天的工作中遇到一个奇怪的问题,如下: "a different object with the same identifier value was already associated w ...

  5. hibernate-取消关联外键引用数据丢失抛异常的设置@NotFound

    hibernate项目里面配了很多many-to-one的关联,后台在查询数据时已经作了健全性判断,但还是经常抛出对象找不到异常: org.hibernate.ObjectNotFoundExcept ...

  6. HTTP协议学习--- (十一)理解HTTP幂等性

    在httpcomponent 文档中看到如下段落: 1.4.1. HTTP transport safety It is important to understand that the HTTP p ...

  7. Get it,你离几何达人不远了!

    对于爱学几何的人,是否存在这样的困扰:没有标准的尺规工具,图形画的不标准,理解上总是出错......整天在纸上画图,浪费大把大把的时间......几何图形画的不美观,在别人面前都拿不出手,公开课上都没 ...

  8. 学习WebSocket(二):使用Spring WebSocket做一个简单聊天室

    聊天室高频率.低延时完全符合websocket的特点,所以聊天室使用websocket再适合不过了. 聊天室的功能并没有比上一节代码多多少,主要在握手阶段对用户的session做处理,对用户的消息进行 ...

  9. [日常训练]常州集训day8

    T1 Description 给定一个长度为$n$的正整数序列$a$.可以将序列分成若干段,定义第$i$段的权值$x_i$为这一段中所有数的最大值,特殊地,$x_0=0$.求$\sum_{i=1}^{ ...

  10. Android成长日记-使用GridView显示多行数据

    本节将实现以下效果 Ps:看起来很不错的样子吧,而且很像九宫格/se ----------------------------------------------------------------- ...