HDU_2057——64位无符号16进制数的运算

Problem Description

There must be many A + B problems in our HDOJ , now a new one is coming. Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too. Easy ? AC it !

 

Input

The input contains several test cases, please process to the end of the file. Each case consists of two hexadecimal integers A and B in a line seperated by a blank. The length of A and B is less than 15.

 

Output

For each test case,print the sum of A and B in hexadecimal in one line.

 

Sample Input

+A -A
+1A 12
1A -9
-1A -12
1A -AA

 

Sample Output

0
2C
11
-2C
-90

 #include <cstdio>
 int main()
 {
    __int64 a,b,c;
    //十六进制数直接可以运算，字母X要大写
    while(~scanf("%I64X%I64X",&a,&b))
       {
          //输入的时候是10...10101010
          //存储的时候是11...01010110补码形式
          //输出的时候是FF...56
          //如果和的符号位是-的话，先-1再取反就变回原码形式
          //然后再另外输出一个'-'
          c=a+b;
          if(c<)
             printf("-%I64X\n",~(c-));
          else
             printf("%I64X\n",c);
       }
    return ;
 }