Given an unsorted array of integers, find the length of longest continuous increasing subsequence (subarray).

Example 1:

Input: [1,3,5,4,7]
Output: 3
Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3.
Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4.

题目地址: Longest Continuous Increasing Subsequence

难度: Easy

题意: 找出呈递增的趋势的子数组,返回最大长度

思路:

遍历数组,并计数,比较简单

class Solution(object):
def findLengthOfLCIS(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
n = len(nums)
if n <= 1:
return len(nums) res = 0
length = 1
for i in range(n-1):
if nums[i] < nums[i+1]:
length += 1
else:
res = max(length, res)
length = 1
res = max(length, res)
return res

时间复杂度: O(n)

空间复杂度: O(1)

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