Codeforces Beta Round #7 D. Palindrome Degree —— 字符串哈希
题目链接:http://codeforces.com/contest/7/problem/D
1 second
256 megabytes
standard input
standard output
String s of length n is
called k-palindrome, if it is a palindrome itself, and its prefix and suffix of length are (k - 1)-palindromes.
By definition, any string (even empty) is 0-palindrome.
Let's call the palindrome degree of string s such a maximum number k,
for which s is k-palindrome.
For example, "abaaba" has degree equals to 3.
You are given a string. Your task is to find the sum of the palindrome degrees of all its prefixes.
The first line of the input data contains a non-empty string, consisting of Latin letters and digits. The length of the string does not exceed 5·106.
The string is case-sensitive.
Output the only number — the sum of the polindrome degrees of all the string's prefixes.
a2A
1
abacaba
6
代码如下:
#include<bits/stdc++.h>
using namespace std;
typedef long long LL;
const double eps = 1e-;
const int INF = 2e9;
const LL LNF = 9e18;
const int mod = 1e9+;
const int maxn = 5e6+; char s[maxn];
int dp[maxn]; int main()
{
scanf("%s",s+);
int l = , r = , m = ;
for(int i = ; s[i]; i++)
{
l = l*+s[i];
r = r+s[i]*m, m *= ;
if(l==r)
dp[i] = dp[i/]+;
} int ans = ;
for(int i = ; s[i]; i++)
ans += dp[i];
printf("%d\n",ans);
}
Codeforces Beta Round #7 D. Palindrome Degree —— 字符串哈希的更多相关文章
- Codeforces Beta Round #7 D. Palindrome Degree manacher算法+dp
题目链接: http://codeforces.com/problemset/problem/7/D D. Palindrome Degree time limit per test1 secondm ...
- Codeforces Beta Round #7 D. Palindrome Degree hash
D. Palindrome Degree 题目连接: http://www.codeforces.com/contest/7/problem/D Description String s of len ...
- Codeforces Beta Round #17 C. Balance (字符串计数 dp)
C. Balance time limit per test 3 seconds memory limit per test 128 megabytes input standard input ou ...
- Codeforces Beta Round #72 (Div. 2 Only)
Codeforces Beta Round #72 (Div. 2 Only) http://codeforces.com/contest/84 A #include<bits/stdc++.h ...
- Codeforces Beta Round #54 (Div. 2)
Codeforces Beta Round #54 (Div. 2) http://codeforces.com/contest/58 A 找子序列 #include<bits/stdc++.h ...
- Codeforces Beta Round #25 (Div. 2 Only)
Codeforces Beta Round #25 (Div. 2 Only) http://codeforces.com/contest/25 A #include<bits/stdc++.h ...
- Codeforces Beta Round #18 (Div. 2 Only)
Codeforces Beta Round #18 (Div. 2 Only) http://codeforces.com/contest/18 A 暴力 #include<bits/stdc+ ...
- Codeforces Beta Round #5 B. Center Alignment 模拟题
B. Center Alignment 题目连接: http://www.codeforces.com/contest/5/problem/B Description Almost every tex ...
- Codeforces Beta Round 84 (Div. 2 Only)
layout: post title: Codeforces Beta Round 84 (Div. 2 Only) author: "luowentaoaa" catalog: ...
随机推荐
- 简单了解HTML5中的Web Notification桌面通知
原文:http://www.zhangxinxu.com/wordpress/2016/07/know-html5-web-notification/ 需要注意的是,消息通知只有通过Web服务访问该页 ...
- DevExpress的GridControl如何实现打印和打印预览 z
第一种方法: System.Drawing.Printing.PageSettings set_print_page = new System.Drawing.Printing ...
- angular http ajax header
myAppModule.config(['$httpProvider', function($httpProvider) { $httpProvider.defaults.headers.common ...
- DICOM医学图像处理:深入剖析Orthanc的SQLite,了解WADO & RESTful API
背景: 上一篇博文简单翻译了Orthanc官网给出的CodeProject上“利用Orthanc Plugin SDK开发WADO插件”的博文,其中提到了Orthanc从0.8.0版本之后支持快速查询 ...
- Hive UDF开发-简介
Hive进行UDF开发十分简单,此处所说UDF为Temporary的function,所以需要hive版本在0.4.0以上才可以. Hive的UDF开发只需要重构UDF类的evaluate函数即可.例 ...
- Leet Code OJ 338. Counting Bits [Difficulty: Medium]
题目: Given a non negative integer number num. For every numbers i in the range 0 ≤ i ≤ num calculate ...
- php实现双色球算法
function DoubleBall(){ $sysBlueball = mt_rand(1,16); $sysRedball = array(1,2,3,4,5,6,7,8,9,10,11,12, ...
- RobotFramework --RIDE介绍
RIDE是robotframework的图形操作前端,我们在RIDE上进行测试用例设计和编写测试脚本,并执行自动化测试.下面来全面的认识下这个操作工具. 在右边编辑页面有三大模块,Edit,TextE ...
- PythonCookBook笔记——数据编码和处理
数据编码和处理 主要涉及用Python处理不同方式编码的数据,如CSV.JSON.XML和二进制包装记录. 读写CSV数据 使用csv库. import csv with open('stocks.c ...
- 初步探讨WPF的ListView控件(涉及模板、查找子控件) - GavinJun
本文结合模板的应用初步介绍ListView的应用 一.Xaml中如何建立数据资源 大部分数据都会来自于后台代码,如何Xaml同样的建立数据源呢?比如建立一个学生List: 首先引入命名空间: xmln ...