HDUOJ----1165Eddy's research II
Eddy's research II
Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 2706 Accepted Submission(s): 985
is known, Ackermann function plays an important role in the sphere of
theoretical computer science. However, in the other hand, the dramatic
fast increasing pace of the function caused the value of Ackermann
function hard to calcuate.
Ackermann function can be defined recursively as follows:
Now
Eddy Gives you two numbers: m and n, your task is to compute the value
of A(m,n) .This is so easy problem,If you slove this problem,you will
receive a prize(Eddy will invite you to hdu restaurant to have supper).
Note that when m<3, n can be any integer less than 1000000, while m=3, the value of n is restricted within 24.
Input is terminated by end of file.
/*@coder龚细军*/
#include<stdio.h>
int Ackermann(int m,int n)
{
if(m==) return n+;
else if(m==) return n+;
else if(m==) return *n+;
else if(m==) return (<<n+)-;
}
int main()
{
int n,m;
while(~scanf("%d%d",&m,&n))
{
printf("%d\n",Ackermann(m,n));
}
return ;
}
HDUOJ----1165Eddy's research II的更多相关文章
- HDU 1165 Eddy's research II(给出递归公式,然后找规律)
- Eddy's research II Time Limit:2000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64 ...
- HDU 1165 Eddy's research II (找规律)
题意:给定一个表达式,然后让你求表达式的值. 析:多写几个就会发现规律. 代码如下: #pragma comment(linker, "/STACK:1024000000,102400000 ...
- HDU 1165 Eddy's research II
题意:已知,求A(m, n). 分析:根据样例模拟一下过程就可以找出递推关系. #include<cstdio> #include<cstring> #include<c ...
- 动态规划入门——Eddy's research II
转载请注明出处:http://blog.csdn.net/a1dark 分析:找规律 #include<stdio.h> int main(){ int m,n; while(scanf( ...
- HDU1165: Eddy's research II(递推)
题目:http://acm.hdu.edu.cn/showproblem.php?pid=1165 果断不擅长找规律啊,做这种题静不下心来. Ackermann function can be def ...
- HDU-1165-Eddy's research II
这个事实上是一个递归题.题目非常easy.m的数非常小.分三种情况.算一下.就能够直接把公式算出来. 当然,也能够用dp做: #include<iostream> #include< ...
- hdu 1165 Eddy's research II(数学题,递推)
// Eddy 继续 Problem Description As is known, Ackermann function plays an important role in the sphere ...
- Eddy's problem partI
Eddy's mistakes[HDU1161] Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java ...
- HDU 1165 公式推导题
题目链接: acm.hdu.edu.cn/showproblem.php?pid=1165 Eddy's research II Time Limit: 4000/2000 MS (Java/Othe ...
随机推荐
- Android图片加载框架最全解析(三),深入探究Glide的缓存机制
在本系列的上一篇文章中,我带着大家一起阅读了一遍Glide的源码,初步了解了这个强大的图片加载框架的基本执行流程. 不过,上一篇文章只能说是比较粗略地阅读了Glide整个执行流程方面的源码,搞明白了G ...
- [11] 楔形体(Wedge)图形的生成算法
顶点数据的生成 bool YfBuildWedgeVertices ( Yreal width, Yreal length, Yreal height, YeOriginPose originPose ...
- Best Time to Buy and Sell Stock leetcode java
题目: Say you have an array for which the ith element is the price of a given stock on day i. If you w ...
- Rotate List leetcode java
题目: Given a list, rotate the list to the right by k places, where k is non-negative. For example: Gi ...
- 任务栈 启动模式 Task Flag launchMode MD
Markdown版本笔记 我的GitHub首页 我的博客 我的微信 我的邮箱 MyAndroidBlogs baiqiantao baiqiantao bqt20094 baiqiantao@sina ...
- javascript制作公式编辑器,函数编辑器和图形绘制
自己是电子信息方向的,因此总是需要处理大量的电路实验.电路数据和电路仿真处理,每次处理数据时候还需要同样的数据很多遍, 又需要关于电路的频率响应和时域响应情况,所以一直有做一个这样公式编辑器的打算了. ...
- Unity异步加载场景loading条
using UnityEngine; using System.Collections; public class LoadingScene : MonoBehaviour { public UISl ...
- 下载RAD
1.登录https://w3-103.ibm.com/software/xl/download/ticket.do 2.输入Intranet ID和pswd,然后选I Agree. 3.然后点Sear ...
- IE11下javascript报堆栈溢出问题的解决
在IE11浏览器下,使用日期函数里面的toLocaleDateString()会报堆栈溢出 不知道是不是跟我的其他相关代码有关,还是就是这个toLocaleDateString()在IE11确实不太一 ...
- fcntl的区域锁定
文件中的某个部分被锁定了,但其他的程序可以访问这个文件的其他部分,称为文件段锁定或文件区域锁定.经常使用文件区域锁定是fcntl函数. #include <sys/types.h> #in ...