CF540B School Marks
思路:
贪心。
实现:
#include <iostream>
#include <cstdio>
#include <vector>
#include <algorithm>
using namespace std; int n, p, k, x, y;
vector<int> a;
int main()
{
cin >> n >> k >> p >> x >> y;
int sum = , tmp = ;
for (int i = ; i < k; i++)
{
cin >> tmp;
a.push_back(tmp);
sum += a[i];
}
if (x - sum < n - k)
{
puts("-1");
}
else
{
bool flag = true;
vector<int> res;
sort(a.begin(), a.begin() + k);
int now = k;
sum = x - sum;
while (now < n)
{
int pos = lower_bound(a.begin(), a.begin() + now, y) - a.begin();
if (pos < now / )
{
a.insert(a.begin(), );
res.push_back();
sum--;
}
else
{
a.insert(a.begin() + pos, y);
res.push_back(y);
sum -= y;
}
if (sum < )
{
puts("-1");
flag = false;
break;
}
now++;
}
if (flag)
{
if (a[n >> ] >= y)
{
for (int i = ; i < n - k; i++)
{
cout << res[i] << " ";
}
puts("");
}
else
{
puts("-1");
}
}
}
return ;
}
CF540B School Marks的更多相关文章
- 【BZOJ-2400】Spoj839Optimal Marks 最小割 + DFS
2400: Spoj 839 Optimal Marks Time Limit: 10 Sec Memory Limit: 128 MBSubmit: 567 Solved: 202[Submit ...
- 贪心 Codeforces Round #301 (Div. 2) B. School Marks
题目传送门 /* 贪心:首先要注意,y是中位数的要求:先把其他的都设置为1,那么最多有(n-1)/2个比y小的,cnt记录比y小的个数 num1是输出的1的个数,numy是除此之外的数都为y,此时的n ...
- 839. Optimal Marks - SPOJ
You are given an undirected graph G(V, E). Each vertex has a mark which is an integer from the range ...
- (CodeForces )540B School Marks 贪心 (中位数)
Little Vova studies programming to p. Vova is very smart and he can write every test for any mark, b ...
- 图论(网络流):SPOJ OPTM - Optimal Marks
OPTM - Optimal Marks You are given an undirected graph G(V, E). Each vertex has a mark which is an i ...
- CodeForces 540B School Marks(思维)
B. School Marks time limit per test 2 seconds memory limit per test 256 megabytes input standard inp ...
- 【SPOJ839】Optimal Marks 网络流
You are given an undirected graph G(V, E). Each vertex has a mark which is an integer from the range ...
- The table name must be enclosed in double quotation marks or sqare bracket while accessing EXCEL by
1 Preface DB Query Analyzer is presented by Master Gen feng, Ma from Chinese Mainland. It has Eng ...
- Codeforces831C Jury Marks
C. Jury Marks time limit per test 2 seconds memory limit per test 256 megabytes input standard input ...
随机推荐
- tomcat会自动解压webapps目录下的war包
如图,把war包放到tomcat的webapps目录,会被自动解压
- VS打包部署图文具体步骤及程序防卸载的制作(password验证卸载)
1. 在vs2010 选择"新建项目->"其它项目类型"->" Visual StudioInstallerà "安装项目": ...
- firebug的应用
firebug再前端调试中起到了非常好的作用能看到DOM的性能,以及检測.比方运用console.log()就是要比alert():好一些这样增强的页面的连续性而且console.warn()和con ...
- storm与hadoop的对照
hadoop 是实现了 mapreduce 的思想,将数据切片计算来处理大量的离线数据. hadoop处理的数据必须是已经存放在 hdfs 上或者类似 hbase 的数据库中.所以 hadoop ...
- salt-stack "No Top file or external nodes data matches found"解决
salt-stack在配置分组时提示如下信息: No Top file or external nodes data matches found 后来在官网上找到如下提示,意思是需要重启master服 ...
- lydsy1013: [JSOI2008]球形空间产生器sphere 高斯消元
题链:http://www.lydsy.com/JudgeOnline/problem.php?id=1013 1013: [JSOI2008]球形空间产生器sphere 时间限制: 1 Sec 内 ...
- HNOI模拟 Day3.23
一.拓扑(top)[ 题目描述]:给你一个有向二分图,求他的拓扑序列的个数.[ 输入]:第一行两个数 N,M,表示点数和边数.接下来 M 行每行两个数 a,b,表示 a 向 b 有一条有向边.[ 输出 ...
- Oracle学习(四):组函数
1.知识点:能够对比以下的录屏进行阅读 SQL> --组函数类型:avg,count,max.min,sum SQL> --工资总额 SQL> select sum(sal) fro ...
- 用js采集网页数据并插入数据库最快的方法
今天教大家一个快速采集网站数据的方法,因为太晚了,直接上例子,这里以采集易车网的产品数据为例. 思路:利用js获取网页数据并生成sql命令,执行sql命令把采集的数据插入数据库. 1.用谷歌浏览器或者 ...
- HDU 4850 Wow! Such String!
链接:http://acm.hdu.edu.cn/showproblem.php?pid=4850 题意:给定一个N(1 ≤ N ≤ 500000),构造一个长度为N的小写字母字符串,要求所有长度大于 ...