LightOJ - 1354 - IP Checking(进制）

链接：

https://vjudge.net/problem/LightOJ-1354

题意：

An IP address is a 32 bit address formatted in the following way

a.b.c.d

where a, b, c, d are integers each ranging from 0 to 255. Now you are given two IP addresses, first one in decimal form and second one in binary form, your task is to find if they are same or not.

思路:

直接进制转换

代码：

#include<iostream>
#include<cstdio>
#include<cstring>
#include<string>
#include<algorithm>
#include<math.h>
#include<vector>
#include<map>

using namespace std;
typedef long long LL;
const int INF = 1e9;

const int MAXN = 5e4+10;
const int MOD = 1e9+7;

bool Ok(int a, char *s)
{
    int sum = 0;
    for (int i = 0;i < 8;i++)
    {
        if (s[i] == '0')
            continue;
        sum += 1<<(7-i);
    }
    return a == sum;
}

int main()
{
    int t, cnt = 0;
    scanf("%d", &t);
    while(t--)
    {
        char s[100];
        int a, b, c, d;
        printf("Case %d:", ++cnt);
        scanf("%d.%d.%d.%d", &a, &b, &c, &d);
        scanf("%s", s);
        bool ok = true;
        if (!Ok(a, s))
            ok = false;
        if (!Ok(b, s+9))
            ok = false;
        if (!Ok(c, s+18))
            ok = false;
        if (!Ok(d, s+27))
            ok = false;
        if (ok)
            puts(" Yes");
        else
            puts(" No");
    }

    return 0;
}