package projecteuler51to60;

import java.awt.peer.SystemTrayPeer;
import java.io.BufferedReader;
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
import java.util.TreeSet; class Card{
//一张一张的读取,一张牌,以及对于的颜色
public final int rank;
public final int suit;
public Card(int rank,int suit){
if(rank<0 || rank>= 13 ||suit< 0||suit>= 4)
throw new IllegalAccessError();
this.rank= rank;
this.suit= suit;
}
public Card(String str){
this("23456789TJQKA".indexOf(str.charAt(0)), "SHCD".indexOf(str.charAt(1)));
} public boolean equals(Object obj) {
if (!(obj instanceof Card))
return false;
Card other = (Card)obj;
return rank == other.rank && suit == other.suit;
} public int hashCode() {
return rank * 4 + suit;
} } class p54{
void solve0(){
String filenameString="src//projecteuler51to60//p054_poker.txt";
readTxtFile(filenameString);
}
int Judge(String[] twoManCard){
Card[] player1 = new Card[5];
Card[] player2 = new Card[5]; for(int i=0;i<5;i++){
player1[i] = new Card(twoManCard[i+0]);
player2[i] = new Card(twoManCard[i+5]);
}
if (getScore(player1) > getScore(player2))
return 1;
return 0;
}
int getScore(Card[] hand){
if(hand.length !=5)
throw new IllegalArgumentException();
int[] rankCounts = new int[13];
int flushSuit = hand[0].suit;
//长度是13的数组,数组值是:各位置数出现的次数
//flushSuit 判断颜色是否一样
for(Card card:hand){
rankCounts[card.rank]++;
if(card.suit!=flushSuit)
flushSuit = -1;
}
//rankCountHist 统计rankCounts中出现了多少次 0 1 2 3 4 5,rankCounts中所有数之和是5,应该就五张牌
int[] rankCountHist = new int[6];
for(int i=0;i<rankCounts.length;i++)
rankCountHist[rankCounts[i]]++;
int bestCards = get5FrequnetHighestCards(rankCounts, rankCountHist);
int straightHishRank = getStraighHighRank(rankCounts);
if(flushSuit!=-1)System.out.println("ok");
// Straight flush
if(straightHishRank!=-1 && flushSuit!=-1) return 8<<20|straightHishRank;
// Four of a kind
else if(rankCountHist[4]==1) return 7<<20|bestCards;
// Full house
else if(rankCountHist[3]==1&&rankCountHist[2]==1)return 6<<20|bestCards;
// Flush
else if(flushSuit!=-1) return 5<<20|bestCards;
// Straight
else if(straightHishRank!=-1) return 4<<20|straightHishRank;
// Three of a kind
else if(rankCountHist[3]==1) return 3<<20|bestCards;
// Two pairs
else if(rankCountHist[2]==2) return 2<<20|bestCards;
// One pair
else if(rankCountHist[2]==1) return 1<<20|bestCards;
// High card
else return 0<<20|bestCards;
}
int get5FrequnetHighestCards(int[] ranks,int[] ranksHist) {
int result = 0;
int count =0;
for(int i=ranksHist.length-1;i>=0;i--){
for(int j=ranks.length-1;j>=0;j--){
if(ranks[j]==i){
for(int k=0;k<i&&count<5;k++,count++)
result=result<<4|j;
}
}
} return result;
}
int getStraighHighRank(int[] ranks){
outer:
for(int i=ranks.length -1;i>=3;i--){
for(int j=0;j<5;j++){
if(ranks[(i-j+13)%13] ==0)
continue outer;
}
return i;
}
return -1;
} void readTxtFile(String filename){
File fl =new File(filename);
int res=0;
FileReader reader=null;
try {
reader = new FileReader(fl);
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} BufferedReader br = new BufferedReader(reader);
String line="";
try {
while((line=br.readLine())!=null){
String[] twoManCard = line.split(" ");
res+=Judge(twoManCard); }
} catch (IOException e) {
// TODO Auto-generated catch block
System.out.println("no file");
}
System.out.println(res);
} }
public class Problem54 { public static void main(String[] args){
long begin= System.currentTimeMillis();
new p54().solve0();
long end = System.currentTimeMillis();
long Time = end - begin;
System.out.println("Time:"+Time/1000+"s"+Time%1000+"ms");
} }

欧拉工程第54题:Poker hands的更多相关文章

  1. 欧拉工程第69题:Totient maximum

    题目链接 欧拉函数φ(n)(有时也叫做phi函数)可以用来计算小于n 的数字中与n互质的数字的个数. 当n小于1,000,000时候,n/φ(n)最大值时候的n. 欧拉函数维基百科链接 这里的是p是n ...

  2. 欧拉工程第70题:Totient permutation

    题目链接 和上面几题差不多的 Euler's Totient function, φ(n) [sometimes called the phi function]:小于等于n的数并且和n是互质的数的个 ...

  3. 欧拉工程第67题:Maximum path sum II

    By starting at the top of the triangle below and moving to adjacent numbers on the row below, the ma ...

  4. 欧拉工程第66题:Diophantine equation

    题目链接 脑补知识:佩尔方差 上面说的貌似很明白,最小的i,对应最小的解 然而我理解成,一个循环的解了,然后就是搞不对,后来,仔细看+手工推导发现了问题.i从0开始变量,知道第一个满足等式的解就是最小 ...

  5. 欧拉工程第65题:Convergents of e

    题目链接 现在做这个题目真是千万只草泥马在心中路过 这个与上面一题差不多 这个题目是求e的第100个分数表达式中分子的各位数之和 What is most surprising is that the ...

  6. 欧拉工程第56题:Powerful digit sum

    题目链接   Java程序 package projecteuler51to60; import java.math.BigInteger; import java.util.Iterator; im ...

  7. 欧拉工程第55题:Lychrel numbers

    package projecteuler51to60; import java.math.BigInteger; import java.util.Iterator; import java.util ...

  8. 欧拉工程第53题:Combinatoric selections

    package projecteuler51to60; class p53{ void solve1(){ int count=0; int Max=1000000; int[][] table=ne ...

  9. 欧拉工程第52题:Permuted multiples

    题目链接 题目: 125874和它的二倍,251748, 包含着同样的数字,只是顺序不同. 找出最小的正整数x,使得 2x, 3x, 4x, 5x, 和6x都包含同样的数字. 这个题目相对比较简单 暴 ...

随机推荐

  1. What is the difference between position: static,relative,absolute,fixed

    What is the difference between static,relative, absolute,fixed we can refer to this link: expand

  2. 如何安装altium designer 10

    http://jingyan.baidu.com/article/4dc4084881e2bdc8d946f1f3.html

  3. Android -- 分享功能和打开指定程序

    打开指定程序                                                                                Intent intent ...

  4. SVG基本图形及clipPath;

    利用SVG可以实现很多复杂的图形,SVG的功能开发者们已经开发许多,今天初识一下SVG的基本图形绘制, <svg viewbox="0,0,400,400" style=&q ...

  5. ios-UIWebView中js和oc代码的互调

    webview是ios中显示远程数据的网页控件,webview能显示的内容很多,MP4.文本.pdf等等: 关于js和oc代码的互相调用 1:oc中调用js代码; >>oc中调用js代码很 ...

  6. Careercup - Google面试题 - 6407924087783424

    2014-05-07 15:17 题目链接 原题: Given an array of n elements (a1,a2,..ai,...,an). You are allow to chose a ...

  7. Java8 Lambda sample (iwantmoon.com出品)

    转载请注明出处:http://iwantmoon.com/Post/83a4497a74674612834965857e7bc044 .Net转到Java来,不知不觉已经有两年了,之前已经用习惯的li ...

  8. 看我是一只IT小小鸟有感

    当我看了<我是一只IT小小鸟>后,有许多的感想.就像许多作者一样,在接触计算机这个专业时都有许多的抱怨,对这个专业的不了解,对这个专业不知道从何学起有深深的无助感,对这个专业在未来的发展有 ...

  9. xml给提示

    1.     FAQ:不给提示: a)     window – preferences – myeclipse – xml – xml catalog b)     User Specified E ...

  10. 获取任意可序列化对象的Xml字符串,方便在日志中查看任一所感兴趣的对象。

    代码: public static string GetLoggingString(this object obj) { using (var stream = new MemoryStream()) ...