这题也是第二次做,本想第一次做时参考的算法会和老师讲的一样,不想老师讲的算法用在这题感觉还不如思雪园友的算法(http://www.cnblogs.com/sixue/archive/2015/04.html)来的简单,不过老师给的思路是一种挺通用的思路,可以用来解决一系列的问题,但我目前看着有点吃力。我坚持认为对全局变量的使用需十分谨慎,能不用就不用,所以为了不出现全局变量,就无辜多了一串参数。实现代码如下,题目在代码下方

 #include <stdio.h>
#include <stdlib.h> int compare(const void * a, const void * b);
void inOrder(int * a, int n, int * in, int N); int main()
{
// freopen("in.txt", "r", stdin); // for test
int i, N, n;
scanf("%d", &N);
int a[N];
for(i = ; i < N; i++)
{
scanf("%d", &n);
a[i] = n;
} qsort(a, N, sizeof(int), compare);
int in[N + ];
inOrder(a, , in, N);
for(i = ; i <= N; i++)
{
printf("%d", in[i]);
if(i < N)
printf(" ");
else
printf("\n");
}
// fclose(stdin); // for test
return ;
} int compare(const void * a, const void * b)
{
return *(int *)a - *(int *)b;
} void inOrder(int * a, int n, int * in, int N)
{
static int i = ; if(n * <= N)
inOrder(a, * n, in, N);
in[n] = a[i++];
if(n * + <= N)
inOrder(a, n * + , in, N);
}

A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties:

  • The left subtree of a node contains only nodes with keys less than the node's key.
  • The right subtree of a node contains only nodes with keys greater than or equal to the node's key.
  • Both the left and right subtrees must also be binary search trees.

A Complete Binary Tree (CBT) is a tree that is completely filled, with the possible exception of the bottom level, which is filled from left to right.

Now given a sequence of distinct non-negative integer keys, a unique BST can be constructed if it is required that the tree must also be a CBT. You are supposed to output the level order traversal sequence of this BST.

Input Specification:

Each input file contains one test case. For each case, the first line contains a positive integer N (<=1000). Then N distinct non-negative integer keys are given in the next line. All the numbers in a line are separated by a space and are no greater than 2000.

Output Specification:

For each test case, print in one line the level order traversal sequence of the corresponding complete binary search tree. All the numbers in a line must be separated by a space, and there must be no extra space at the end of the line.

Sample Input:

10
1 2 3 4 5 6 7 8 9 0

Sample Output:

6 3 8 1 5 7 9 0 2 4

04-树5 Complete Binary Search Tree的更多相关文章

  1. PAT Advanced 1064 Complete Binary Search Tree (30) [⼆叉查找树BST]

    题目 A Binary Search Tree (BST) is recursively defined as a binary tree which has the following proper ...

  2. PAT题库-1064. Complete Binary Search Tree (30)

    1064. Complete Binary Search Tree (30) 时间限制 100 ms 内存限制 32000 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHE ...

  3. A1064. Complete Binary Search Tree

    A Binary Search Tree (BST) is recursively defined as a binary tree which has the following propertie ...

  4. 04-树6 Complete Binary Search Tree(30 分)

    title: 04-树6 Complete Binary Search Tree(30 分) date: 2017-11-12 14:20:46 tags: - 完全二叉树 - 二叉搜索树 categ ...

  5. pat04-树8. Complete Binary Search Tree (30)

    04-树8. Complete Binary Search Tree (30) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 8000 B 判题程序 Standard 作者 CHE ...

  6. PAT 甲级 1064 Complete Binary Search Tree (30 分)(不会做,重点复习,模拟中序遍历)

    1064 Complete Binary Search Tree (30 分)   A Binary Search Tree (BST) is recursively defined as a bin ...

  7. PAT_A1064#Complete Binary Search Tree

    Source: PAT A1064 Complete Binary Search Tree (30 分) Description: A Binary Search Tree (BST) is recu ...

  8. PAT甲级——A1064 Complete Binary Search Tree

    A Binary Search Tree (BST) is recursively defined as a binary tree which has the following propertie ...

  9. 1064 Complete Binary Search Tree (30分)(已知中序输出层序遍历)

    A Binary Search Tree (BST) is recursively defined as a binary tree which has the following propertie ...

随机推荐

  1. java 集合(List)

    List: 特有的方法: 添加: add(int index, E element) addAll(int index, Collection<? extends E> c) 获取: ge ...

  2. jQuery图表开源软件

    jQuery图表插件 jQchart jQchart 是一个jQuery的插件,用来绘制图表的.支持各种形状的图表. 示例代码: == Mini sample == $('#canvasMyID'). ...

  3. C#类和成员的修饰符

    C#中public.private.protected.internal.protected internal & (2010-09-22 13:33:45)转载 标签: 杂谈 分类: C# ...

  4. wait(), notify(),sleep详解

    在JAVA中,是没有类似于PV操作.进程互斥等相关的方法的.JAVA的进程同步是通过synchronized()来实现的,需要说明的是,JAVA的synchronized()方法类似于操作系统概念中的 ...

  5. oracle错误码

    ORA-00001: 违反唯一约束条件 (.) ORA-00017: 请求会话以设置跟踪事件 ORA-00018: 超出最大会话数 ORA-00019: 超出最大会话许可数 ORA-00020: 超出 ...

  6. 在express3.0上使用模板

    express3.0取消了layout设置,为了能使用模版,经过百度后发现有个express-partials模块可以使用 1:安装 npm install express-partials 模块安装 ...

  7. 一份C++线程池的代码,非常实用

    #ifndef _ThreadPool_H_ #define _ThreadPool_H_ #pragma warning(disable: 4530) #pragma warning(disable ...

  8. offsetLeft,Left,clientLeft的区别

    offsetLeft,Left,clientLeft的区别 假设 obj 为某个 HTML 控件. obj.offsetTop 指 obj 相对于版面或由 offsetParent 属性指定的父坐标的 ...

  9. 转载 网页打印时设置A4大小

    最近开发项目时遇到了网页打印的问题,这是问题之二,打印宽度设置 在公制长度单位与屏幕分辨率进行换算时,必须用到一个DPI(Dot Per Inch)指标. 经过我仔细的测试,发现了网页打印中,默认采用 ...

  10. c# xml的增删改查操作 xmlDocument 的用法

    1.将xml转换为DataTable string path = "";//xml的位置StringReader sr = null;XmlTextReader xmlReader ...