redux & connect

import React, {
Component,
// useState,
// useEffect,
} from 'react'; import { bindActionCreators } from 'redux';
import { connect } from 'dva'; import dashboardRegionActions from '../actions/dashboard.region.action'; // import { MapChart } from "../MapChart";
import { SelectOption } from "./SelectOption";
import { SearchInput } from "./SearchInput"; import * as Provinces from "../Region/provinces.json"; import './index.less'; import {
Row,
Col,
// Input,
// Icon,
// Tag,
// Select,
// Tooltip,
// Tabs,
// Radio,
// Checkbox,
// Table,
// Pagination,
} from "antd"; const mapStateToProps = ({ dashboard }) => ({
regionData: dashboard.regionData,
// mapLoading: dashboard?.mapLoading,
}); const mapDispatchToProps = dispatch => ({
actions: bindActionCreators(dashboardRegionActions, dispatch),
}); @connect(mapStateToProps, mapDispatchToProps,)
class SelectableIndexList extends Component {
constructor(props) {
super(props);
this.state = {
placeholder: "请输入省份名或其拼音",
provincesList: this.selectedFilter(Provinces.default),
initProvincesList: this.selectedFilter(Provinces.default),
};
}
selectedFilter = (provinces = []) => {
return provinces.map(obj => {
if (obj.key === "all") {
obj.selected = true;
} else {
obj.selected = false;
}
return obj;
});
};
formatAdcode = (code = "all") => {
let adcode = 100000;
if (code !== "all") {
adcode = Number(`${code}0000`);
}
return adcode;
};
provincesFilter = (provincesList, key) => {
const result = provincesList.map(({name, key: code,}) => {
if (code === key) {
return {
name,
key: code,
selected: true,
};
} else {
return {
name,
key: code,
selected: false,
};
}
}) || [];
return result;
}
clickCheck = (key) => {
const {
// regionData,
actions: {
changeRegion,
},
} = this.props;
const {
provincesList,
initProvincesList,
} = this.state;
const newProvincesList = this.provincesFilter(provincesList, key);
const newInitProvincesList = this.provincesFilter(initProvincesList, key);
this.setState({
provincesList: newProvincesList,
initProvincesList: newInitProvincesList,
}, () => {
// const code = this.formatAdcode(key);
// changeRegion(code);
changeRegion(`${key}`);
});
};
handleCheckableTagChange = (value) => {
const {
// provincesList,
initProvincesList: provincesList,
} = this.state;
let newProvincesList = provincesList.filter(({name, key, selected}) => {
if (name.includes(value)) {
return {
name,
key,
selected,
};
}
}) || [];
this.setState({
provincesList: newProvincesList,
});
};
inputChangeHandle = (e) => {
let value = e.target.value;
this.handleCheckableTagChange(value);
};
render() {
const {
placeholder,
provincesList,
} = this.state;
return (
<>
<Row className="selectable-index-list">
<Col span={24} className="input-box">
{
SearchInput({
placeholder: placeholder,
inputChangeHandle: this.inputChangeHandle,
})
}
</Col>
<Col span={24} className="option-box">
<SelectOption
provincesList={provincesList}
clickCheck={this.clickCheck}
/>
</Col>
</Row>
</>
);
}
} export {
SelectableIndexList,
}; export default SelectableIndexList;

const mapStateToProps = ({ dashboard }) => ({
regionData: dashboard.regionData,
// mapLoading: dashboard?.mapLoading,
}); const mapDispatchToProps = dispatch => ({
actions: bindActionCreators(dashboardRegionActions, dispatch),
}); // export default connect(
// mapStateToProps,
// mapDispatchToProps,
// )(RegionChart);
// @connect(mapStateToProps, mapDispatchToProps,)

redux & connect的更多相关文章

  1. [Redux] Accessing Dispatch and State with Redux -- connect

    If you have props and actions, you want one component to access those props and actions, one solutio ...

  2. redux connect的浅比较说明

    redux的connect方法是一个高阶组件,对包装的组件会在ShouldComponentUpdate中实现一个默认的浅比较. connect形式如下: connect([mapStateToPro ...

  3. 【温故知新】—— React/Redux/React-router4基础知识&独立团Demo

    前言:React专注View层,一切皆组件:全部使用ES6语法,最新版本为React16. Redux是专注于状态管理的库,和react解耦:单一状态,单向数据流.[独立团github地址] 一.Re ...

  4. 手写 redux 和 react-redux

    1.手写 redux redux.js /** * 手写 redux */ export function createStore(reducer) { // 当前状态 let currentStat ...

  5. QQ音乐:React v16 新特性实践

    欢迎大家前往腾讯云+社区,获取更多腾讯海量技术实践干货哦~ 本文由QQ音乐技术团队发表于云+社区专栏 自从去年9月份 React 团队发布了 v16.0 版本开始,到18年3月刚发布的 v16.3 版 ...

  6. 【招聘App】—— React/Nodejs/MongoDB全栈项目:socket.io&聊天实现

    前言:最近在学习Redux+react+Router+Nodejs全栈开发高级课程,这里对实践过程作个记录,方便自己和大家翻阅.最终成果github地址:https://github.com/66We ...

  7. 【招聘App】—— React/Nodejs/MongoDB全栈项目:个人中心&退出登录

    前言:最近在学习Redux+react+Router+Nodejs全栈开发高级课程,这里对实践过程作个记录,方便自己和大家翻阅.最终成果github地址:https://github.com/66We ...

  8. 【招聘App】—— React/Nodejs/MongoDB全栈项目:信息完善&用户列表

    前言:最近在学习Redux+react+Router+Nodejs全栈开发高级课程,这里对实践过程作个记录,方便自己和大家翻阅.最终成果github地址:https://github.com/66We ...

  9. 【招聘App】—— React/Nodejs/MongoDB全栈项目:登录注册

    前言:最近在学习Redux+react+Router+Nodejs全栈开发高级课程,这里对实践过程作个记录,方便自己和大家翻阅.最终成果github地址:https://github.com/66We ...

随机推荐

  1. Covering Indexes in MySQL, PostgreSQL, and MongoDB

    Covering Indexes in MySQL, PostgreSQL, and MongoDB - Orange Matter https://orangematter.solarwinds.c ...

  2. Shiro中Subject对象的创建与绑定流程分析

    我们在平常使用Shrio进行身份认证时,经常通过获取Subject 对象中保存的Session.Principal等信息,来获取认证用户的信息,也就是说Shiro会把认证后的用户信息保存在Subjec ...

  3. poj 2752Seek the Name, Seek the Fame

    Seek the Name, Seek the Fame Time Limit: 2000MS   Memory Limit: 65536KB   64bit IO Format: %I64d &am ...

  4. sql多行合并

    例一 SELECT qqo.questionID '题目id', qqo.quesOption '选项' FROM qz_question_option qqo, qz_question qq WHE ...

  5. scala中List、Array、ListBuffer、ArrayList、Set

    scala中List.Array.ListBuffer.ArrayList.Set 一.List 二.Array 三.LIstBuffer 四.ArrayBuffer 五.Set 一.List Lis ...

  6. SSH入门开发(实现一个简单的登录功能)详解

    开头,首先想记录下一首诗,是今天拇指阅读看到的:很有感触,所以乐于分享: 那么,下面正式开始进入正题,搭建一个 SSH完整的项目: 首先,我们需要在WEB-ROOT下创建一个login.jsp(登录) ...

  7. 2019 沈阳网络赛 D Fish eating fruit ( 树形DP)

    题目传送门 题意:求一颗树中所有点对(a,b)的路径长度,路径长度按照模3之后的值进行分类,最后分别求每一类的和 分析:树形DP \(dp[i][j]\) 表示以 i 为根的子树中,所有子节点到 i ...

  8. Codeforces Round #651 (Div. 2) C. Number Game(数论)

    题目链接:https://codeforces.com/contest/1370/problem/C 题意 给出一个正整数 $n$,Ashishgup 和 FastestFinger 依次选择执行以下 ...

  9. pbds初探

    今年暑假外校集训的时候一道题标算是最短路扩展,然而std用的是pbds,于是就产生了研究的兴趣.结果那个标程我现在死都找不到了233 定义: 在知乎上看到有oier去年向CCF发了邮件,得到的回复是p ...

  10. 【uva 1349】Optimal Bus Route Design(图论--网络流 二分图的最小权完美匹配)

    题意:有一个N个点的有向带权图,要求找若干个有向圈,使得每个点恰好属于一个圈.请输出满足以上条件的最小权和. 解法:有向圈?也就是每个点有唯一的后继.这是一个可逆命题,同样地,只要每个点都有唯一的后继 ...