闲下来后,需要讲最近涉及到的算法全部整理一下,有个indice,方便记忆宫殿的查找

MIT的算法课,地球上最好:https://ocw.mit.edu/courses/electrical-engineering-and-computer-science/6-046j-design-and-analysis-of-algorithms-spring-2015/lecture-notes/

Why Puzzles? Solving puzzles will help you sharpen your analytic skills and make you a better problem solver. More over, most of our puzzles can be solved using methods that are either the same or are related to various techniques that we will be using to design algorithms. Click on titles to get to the puzzles.

  1. Puzzles related to recursion and mathematical induction   We start with a set of puzzles that are all related to recursion and mathematical induction. I have chosen interesting but also a bit tough puzzles to get you intrigued, so do not get discouraged if you find them hard. (递归,数学推导)
  2. Puzzles related to probability   Understanding probability theory is necessary for evaluating the behaviour of an algorithm in average (i.e., in finding the expected run time of an algorithm for given probability distribution of inputs).  Probability can be tricky and it often teases our “naïve” common sense, as you might  experience below.
  3. Analytical thinking puzzles   A mix  of various puzzles for developing creative thinking and your analytical ability.

1. Puzzles related to recursion and mathematical induction

We start with a set of puzzles that are all related to recursion and mathematical induction we study in Topic 1. I have chosen interesting but also a bit tough puzzles to get you intrigued, so do not get discouraged if you find them hard.

1.1. The Party Problem

Tom and his wife Mary went to a party where four more couples were present. Not every one knew every everyone else, so people who did not know each other introduced themselves and shook hands. People that knew each other from before did not shake hands.  Later that evening Tom got bored, so he walked around and asked all other guests (including his wife) how many hands they had shaken that evening, and got nine different answers. How many hands did Mary shake? (Hint: you will end up doing recursion on the number of couples…)

Answer:

1. 总共10个人,每个人不与自己握手,不与配偶握手,不与同一个人握超过一次手,所以每个人最多握8次手,最少0次;

2. Mr.Smith问其它9个人握了几次手,各人回答不一样,所以每个人的握手次数刚好为0-8次,每种不同次数有1个人;

3. 有且只有一个人握了8次手,称之为A,即A与其配偶以外的所有人都握了手;

4. 记A的配偶为a,除了A夫妇以外,所有人都至少握了1次手(和A),所以握手0次的肯定是a;

5. 从10个人中去掉A夫妇,因为A与其余每个人握了1次手,而a没有与别人握手,所以去掉A夫妇后,其它人的握手次数为1-7(不算Mr.Smith),再去掉他 们各自与A握的那次手不算,则各人的握手次数为0-6,还是每种不同次数刚好有1个人;

6. 重复第3-5步4次,直到去掉4对夫妇,最终剩下Mr.&Mrs.Smith,这时Mrs.Smith的握手次数为0,加上4次循环中去掉的4次握手,她总共握 了4次手,与每对夫妇中的某一位各握了一次。

1.2. The Ten Thieves Problem

Here is an “ancient” small puzzle: Two thieves have robbed a warehouse and have to split a large pile of various items,  without prices on them. How do they do this in a way that each thief thinks (believes) that he has got at least one half of the value of the whole pile?

You might want to try to solve this puzzle before reading further …

The solution is that one of the two thieves splits the pile in two parts such that he thinks that both parts are of equal value. The other one then chooses what he thinks is the better part. It is easy to see that both thieves a have reason to believe that they got at least a half (try to explain why).

Now here is the real puzzle for you to solve: Assume that ten thieves have robbed the warehouse. How do they split the pile of items so that each thief  thinks that he has got at least one tenth of the total value of the pile? (Hint: This is quite a tough one. It is an example of a nested recursion (a recursion within a recursion)).

1.3. Finding the False Coins

(a) We are given 27 coins of the same denomination; we know that one of them is counterfeit and that it is lighter than the others. Find the counterfeit coin by weighing coins on a pan balance only three times. 

(b) We are given 12 coins and one of them is a fake but we do not know if it is heavier or lighter. Can you determine which one is a fake and if it is lighter or heavier by weighing coins on a pan balance three times only? ((a) and (b) are perfect examples of  divide-and-conquer technique). 

(c) We have 9 coins and three of them are heavier than the remaining six. Can you find the heavier coins by weighing coins on a pan balance only four times? (Hint: this is an example of the lower bound estimation of complexity of algorithms, i.e., of the minimal number of steps needed to execute an algorithm for a given input).

Answer:

(a) 9 + 9 + 9

(b) 4 + 4 + 4

(c)

1.4. Breaking a chocolate

(a) Assume you are given a block of chocolate consisting of m by n squares. At each move you can break one piece into two (not necessarily equal) pieces (see the picture below). The goal is to get  m × n  separate squares. What is the least number of moves needed to achieve this goal and how should one do it? (b) Assume now that you can put several pieces of chocolate  on top of each other and break them in a single move. What is now the least number of moves needed to get m × n  separate squares? (Hint: this is an example of estimating complexity of algorithms, i.e., the number of steps needed to execute an algorithm for a given input)

 
 
1.5. The Five Pirates

(a) There are five pirates who have to split 100 bars of gold. They all line up and proceed as follows:

i) The first pirate in line gets to propose a way to split up the gold (for example: everyone gets 20 bars)

ii) The pirates, including the one who proposed, vote  on whether to accept the proposal. If the proposal is rejected, the prate who made the proposal is killed.

iii) The next pirate in line then makes his proposal, and the 4 pirates vote again. If the vote is tied (2 vs 2) then the proposing pirate is still killed. Only majority can accept a proposal. The process continues until a proposal is accepted or there is only one pirate left. Assume that every pirate :

  • above all wants to live ;
  • given that he will be alive he wants to get as much gold as possible;
  • given maximal possible amount of gold, he wants to see any other
  • pirate killed, just for fun ;
  • each pirate knows his exact position in line;
  • all of the pirates are excellent puzzle solvers.

Question : What proposal should the first pirate make ?

(b) Assume now there are 10 pirates splitting 1000 pieces of gold. What should the first pirate propose ?

(An interesting puzzle - recursion seems to be the ONLY way to solve it !!!)

1.6. One Way Streets

In Elbonia all cities have a circular one-way highway around the city (in blue on the map below). All streets in the cities are one-way, and they all start and end on the circular highway (see the map).  A block is a part of the city that is not intersected by any street. Design an algorithm that, given a map of a  city, finds a block that can be circumnavigated while respecting all one-way signs. For example, the green block has such property, but the red one does not.  What is the best possible expected (i.e., average) asymptotic run time of such an algorithm?  (Again a recursion, but estimating the expected run time is hard…)

 
 

Answer:

Walk through the path and mark the areas around - clockwise or anticlockwise.

Or,

the problem became "How to find a smallest cycle in the Directed Graph".



避免那个小方块的漏洞的情况下,如何放积木摆满棋盘。

Tricky: 2^n-1 mod 3 = 0

这个必然也必须的小漏洞分布各个子方格的位置,如上图技巧所示。Divide And Conquer的思想。

补充:还需再整理...

 01. 找数组中的 duplicated/missing value。

http://stackoverflow.com/questions/3492302/easy-interview-question-got-harder-given-numbers-1-100-find-the-missing-numbe

     
 02. Party找名人 http://math.stackexchange.com/questions/847371/celebrity-problem-discrete-math       
 03. 博客 - 面试题型总结  http://blog.csdn.net/Hackbuteer1/article/category/899947      
 04. Big-O Cheat Sheet  Big-O Cheat Sheet      
 05. linkcode 面试题  https://www.lintcode.com/zh-cn/problem/#      
 06. 博客 - 常见排序算法总结  http://blog.csdn.net/speedme/article/details/23021467      
 07. 基数排序的逐步优化(与快排比较)  http://blog.csdn.net/yutianzuijin/article/details/22876017      
 08. 大数据算法面试题  http://blog.csdn.net/v_july_v/article/details/6279498      
 09.  linkcode 面试题 (盗版来源)  https://leetcode.com/problemset/algorithms/      
   

[Algorithm] Warm-up puzzles的更多相关文章

  1. What are the 10 algorithms one must know in order to solve most algorithm challenges/puzzles?

    QUESTION : What are the 10 algorithms one must know in order to solve most algorithm challenges/puzz ...

  2. 《algorithm puzzles》——谜题

    这篇文章开始正式<algorithm puzzles>一书中的解谜之旅了! 狼羊菜过河: 谜题:一个人在河边,带着一匹狼.一只羊.一颗卷心菜.他需要用船将这三样东西运至对岸,然而,这艘船空 ...

  3. 《algorithm puzzles》——概述

    这个专题我们开始对<algorithm puzzles>一书的学习,这本书是一本谜题集,包括一些数学与计算机起源性的古典命题和一些比较新颖的谜题,序章的几句话非常好,在这里做简单的摘录. ...

  4. codeforces A. Puzzles 解题报告

    题目链接:http://codeforces.com/problemset/problem/337/A 题意:有n个学生,m块puzzles,选出n块puzzles,但是需要满足这n块puzzles里 ...

  5. HDU 4612 Warm up tarjan缩环+求最长链

    Warm up Problem Description   N planets are connected by M bidirectional channels that allow instant ...

  6. HDU 4612 Warm up(2013多校2 1002 双连通分量)

    Warm up Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Su ...

  7. HDU 4619 Warm up 2(2013多校2 1009 二分匹配)

    Warm up 2 Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)Total S ...

  8. codeforces 377A. Puzzles 水题

    A. Puzzles Time Limit: 20 Sec  Memory Limit: 256 MB 题目连接 http://codeforces.com/problemset/problem/33 ...

  9. hdoj 4612 Warm up【双连通分量求桥&&缩点建新图求树的直径】

    Warm up Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)Total Su ...

随机推荐

  1. Linux学习笔记15—RPM包的安装OR源码包的安装

    RPM安装命令1. 安装一个rpm包rpm –ivh 包名“-i” : 安装的意思“-v” : 可视化“-h” : 显示安装进度另外在安装一个rpm包时常用的附带参数有:--force : 强制安装, ...

  2. 什么是less?

    什么是less? 简单的说,你可以在你的css文件中使用变量.函数等方式来编写你的css. less具有哪些功能? 混入(Mixins)——class中的class: 参数混入——可以传递参数的cla ...

  3. Windows DIB文件操作具体解释-4.使用DIB Section

    前面讲了为了提高DIB的显示性能和效率,我们将DIB转换成DDB.可是这又遇到一个问题.假设我想操作DIB的数据的话,显然是不能使用DDB:一是由于DIB转DDB时发生了颜色转换.再就是DDB无法直接 ...

  4. js实现的map方法

    /** * * 描述:js实现的map方法 * @returns {Map} */ function Map(){ var struct = function(key, value) { this.k ...

  5. windows Server 2008 R2 开关机取消登录时要按Ctrl+Alt+Delete组合键登录的方法

    1.点桌面任务栏的“开始-->运行”在弹出的窗口中输入gpedit.msc . 2.找到如下图所示的位置 右键属性进行设置如下

  6. webservice接口与HTTP接口学习笔记

    一.webservice 的概念 Web 是使应用程序可以与平台和编程语言无关的方式进行相互通信的一项技术.Web 服务是一个软件接口,它描述了一组可以在网络上通过标准化的 XML 消息传递访问的操作 ...

  7. 微信支付WxpayAPI_php_v3 错误修改

    微信sdk:WxpayAPI_php_v3 这是下载压缩包的目录结构. https://pay.weixin.qq.com/wiki/doc/api/jsapi.php?chapter=11_1 ce ...

  8. 深入理解JVM(一)——JVM内存模型

    JVM内存模型 Java虚拟机(Java Virtual Machine=JVM)的内存空间分为五个部分,分别是: 1. 程序计数器 2. Java虚拟机栈 3. 本地方法栈 4. 堆 5. 方法区. ...

  9. MDX Cookbook 04 - 在集合中实现 NOT IN 逻辑 (Minus, Except, Filter 等符号和函数的使用)

    有时需要从一些查询结果里排除掉一些成员,当然平常情况下可以通过 MDX 查询中的 WHERE 条件即 Slicer 切片来完成,同样的这里显示的是如何在切片中排除掉一些成员. 先看这一个查询 - , ...

  10. Spark GraphX实例(3)

    7. 图的聚合操作 图的聚合操作主要的方法有: (1) Graph.mapReduceTriplets():该方法有一个mapFunc和一个reduceFunc,mapFunc对图中的每一个EdgeT ...