Implement Queue by Two Stacks & Implement Stack using Queues
Implement Queue by Two Stacks
Implement the following operations of a queue using stacks.
- push(x) -- Push element x to the back of queue.
- pop() -- Removes the element from in front of queue.
- peek() -- Get the front element.
- empty() -- Return whether the queue is empty.
class MyQueue {
private Stack<Integer> stack1, stack2;
public MyQueue() {
// do initialization if necessary
stack1 = new Stack<Integer>();
stack2 = new Stack<Integer>();
}
// Push element x to the back of queue.
public void push(int x) {
stack1.push(x);
}
// Removes the element from in front of queue.
public void pop() {
if (stack2.isEmpty()) {
while(!stack1.isEmpty()) {
stack2.push(stack1.pop());
}
}
stack2.pop();
}
// Get the front element.
public int peek() {
if (stack2.isEmpty()) {
while(!stack1.isEmpty()) {
stack2.push(stack1.pop());
}
}
return stack2.peek();
}
// Return whether the queue is empty.
public boolean empty() {
return stack1.isEmpty() && stack2.isEmpty();
}
}
Implement Stack using Queues
Implement the following operations of a stack using queues.
- push(x) -- Push element x onto stack.
- pop() -- Removes the element on top of the stack.
- top() -- Get the top element.
- empty() -- Return whether the stack is empty.
Notes:
- You must use only standard operations of a queue -- which means only
push to back,peek/pop from front,size, andis emptyoperations are valid. - Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue.
- You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).
分析:
用两个queues,第二个queue永远为空,它只用于临时保存数字而已。
class MyStack {
// Push element x onto stack.
LinkedList<Integer> q1 = new LinkedList<Integer>();
LinkedList<Integer> q2 = new LinkedList<Integer>();
public void push(int x) {
q1.offer(x);
}
// Removes the element on top of the stack.
public void pop() {
if (!empty()) {
while(q1.size() >= ) {
q2.offer(q1.poll());
}
q1.poll();
while(q2.size() >= ) {
q1.offer(q2.poll());
}
}
}
// Get the top element.
public int top() {
int value = ;
if (!empty()) {
while(q1.size() >= ) {
if (q1.size() == ) {
value = q1.peek();
}
q2.offer(q1.poll());
}
while(q2.size() >= ) {
q1.offer(q2.poll());
}
}
return value;
}
// Return whether the stack is empty.
public boolean empty() {
return q1.size() == ;
}
}
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