Codeforces CF#628 Education 8 A. Tennis Tournament
1 second
256 megabytes
standard input
standard output
A tennis tournament with n participants is running. The participants are playing by an olympic system, so the winners move on and the losers drop out.
The tournament takes place in the following way (below, m is the number of the participants of the current round):
- let k be the maximal power of the number 2 such that k ≤ m,
- k participants compete in the current round and a half of them passes to the next round, the other m - k participants pass to the next round directly,
- when only one participant remains, the tournament finishes.
Each match requires b bottles of water for each participant and one bottle for the judge. Besides p towels are given to each participant for the whole tournament.
Find the number of bottles and towels needed for the tournament.
Note that it's a tennis tournament so in each match two participants compete (one of them will win and the other will lose).
The only line contains three integers n, b, p (1 ≤ n, b, p ≤ 500) — the number of participants and the parameters described in the problem statement.
Print two integers x and y — the number of bottles and towels need for the tournament.
5 2 3
20 15
8 2 4
35 32
In the first example will be three rounds:
- in the first round will be two matches and for each match 5 bottles of water are needed (two for each of the participants and one for the judge),
- in the second round will be only one match, so we need another 5 bottles of water,
- in the third round will also be only one match, so we need another 5 bottles of water.
So in total we need 20 bottles of water.
In the second example no participant will move on to some round directly.
题意:
有n个人两两对决,每场对决有一个裁判。
每个选手每次参加比赛需要b瓶水,并且裁判需要一瓶。并且选手各需要毛巾p条。
(题意没有明说,需要瞎猜)每个人的毛巾可以循环使用,每个人从比赛到结束都只需要p条毛巾。
问总共需要的水和毛巾数量。
题解:
直接模拟每轮比赛即可。
#include <iostream>
#include <algorithm>
#include <cstdio>
using namespace std; int n, b, p; int main() {
scanf("%d%d%d", &n, &b, &p);
int bottles = , towels = n * p;
while(n > ) {
int k = ;
while(k * <= n) k <<= ;
int m = n - k + k / ;
int matches = k / ;
bottles += matches * ( * b + );
n = m;
}
printf("%d %d\n", bottles, towels);
return ;
}
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