原始SQL:

这里想做的事情就是查询一周的一个计算值

可以理解为报表的那种

主表 t_wechat_clue 生产库上200万数据量

然后需要联表一些限制条件

SELECT
IFNULL(SUM((CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -6 DAY) AND HOUR(CLUE.gen_time) = 22 THEN CLUE.follow_total ELSE 0 END)),0) AS y1,
IFNULL(SUM((CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -5 DAY) AND HOUR(CLUE.gen_time) = 22 THEN CLUE.follow_total ELSE 0 END)),0) AS y2,
IFNULL(SUM((CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -4 DAY) AND HOUR(CLUE.gen_time) = 22 THEN CLUE.follow_total ELSE 0 END)),0) AS y3,
IFNULL(SUM((CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -3 DAY) AND HOUR(CLUE.gen_time) = 22 THEN CLUE.follow_total ELSE 0 END)),0) AS y4,
IFNULL(SUM((CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -2 DAY) AND HOUR(CLUE.gen_time) = 22 THEN CLUE.follow_total ELSE 0 END)),0) AS y5,
IFNULL(SUM((CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -1 DAY) AND HOUR(CLUE.gen_time) = 22 THEN CLUE.follow_total ELSE 0 END)),0) AS y6,
IFNULL(SUM((CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL 0 DAY) AND HOUR(CLUE.gen_time) > HOUR(DATE_ADD(NOW(), INTERVAL -2 HOUR)) THEN CLUE.follow_total ELSE 0 END)),0) AS y7, IFNULL(SUM(DISTINCT CASE WHEN CLUE.org_code IS NOT NULL THEN (CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -6 DAY) AND HOUR(CLUE.gen_time) = 22 THEN CLUE.dist_total ELSE 0 END) ELSE 0 END), 0) AS a1,
IFNULL(SUM(DISTINCT CASE WHEN CLUE.org_code IS NOT NULL THEN (CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -5 DAY) AND HOUR(CLUE.gen_time) = 22 THEN CLUE.dist_total ELSE 0 END) ELSE 0 END), 0) AS a2,
IFNULL(SUM(DISTINCT CASE WHEN CLUE.org_code IS NOT NULL THEN (CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -4 DAY) AND HOUR(CLUE.gen_time) = 22 THEN CLUE.dist_total ELSE 0 END) ELSE 0 END), 0) AS a3,
IFNULL(SUM(DISTINCT CASE WHEN CLUE.org_code IS NOT NULL THEN (CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -3 DAY) AND HOUR(CLUE.gen_time) = 22 THEN CLUE.dist_total ELSE 0 END) ELSE 0 END), 0) AS a4,
IFNULL(SUM(DISTINCT CASE WHEN CLUE.org_code IS NOT NULL THEN (CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -2 DAY) AND HOUR(CLUE.gen_time) = 22 THEN CLUE.dist_total ELSE 0 END) ELSE 0 END), 0) AS a5,
IFNULL(SUM(DISTINCT CASE WHEN CLUE.org_code IS NOT NULL THEN (CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -1 DAY) AND HOUR(CLUE.gen_time) = 22 THEN CLUE.dist_total ELSE 0 END) ELSE 0 END), 0) AS a6,
IFNULL(SUM(DISTINCT CASE WHEN CLUE.org_code IS NOT NULL THEN (CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL 0 DAY) AND HOUR(CLUE.gen_time) > HOUR(DATE_ADD(NOW(), INTERVAL -2 HOUR)) THEN CLUE.dist_total ELSE 0 END) ELSE 0 END), 0) AS a7
FROM
t_wechat_clues CLUE
JOIN t_dms_member DMS_MEMBER ON CLUE.emp_id = DMS_MEMBER.employee_id AND LENGTH(CLUE.org_code)=8 AND SUBSTR(CLUE.org_code, 1, 1)='P'
JOIN t_wechat_member WC_MEMBER ON DMS_MEMBER.wechat_emp_id = WC_MEMBER.userid AND WC_MEMBER.STATUS = 1 AND WC_MEMBER.TYPE = 2
JOIN (SELECT TT.id ,TT.NAME FROM (
WITH RECURSIVE cte AS(
SELECT a.id, a.parent_id,a.name FROM tt_wechat_org a WHERE a.id='49'
UNION ALL
SELECT k.id, k.parent_id,k.name FROM tt_wechat_org k INNER JOIN cte c ON c.id = k.parent_id
) SELECT id,NAME,parent_id FROM cte) TT ) TREE_ORG ON TREE_ORG.id = WC_MEMBER.department

反正实际上数据返回到页面渲染Echarts花了10秒的样子

经理说8行,必须要改动

前提情况是,这里联表的字段和日期时间都做了索引处理

慢的原因是查询的字段导致

另外还有就是联表的字段数据类型需要一致

不要让MySQL去推导转换,这会浪费一部分性能

优化之后:

随后同事给我一套UnionALL解法,虽然SQL很多,但是效率提升明显!

SELECT
IFNULL(SUM(CLUE.follow_total),0) AS y1 ,
SUM(DISTINCT (CASE WHEN CLUE.org_code IS NOT NULL THEN CLUE.dist_total ELSE 0 END)) a1
FROM
t_wechat_clues CLUE
JOIN t_dms_member DMS_MEMBER ON CLUE.emp_id = DMS_MEMBER.employee_id AND LENGTH(CLUE.org_code)=8 AND SUBSTR(CLUE.org_code, 1, 1)='P'
JOIN t_wechat_member WC_MEMBER ON DMS_MEMBER.wechat_emp_id = WC_MEMBER.userid AND WC_MEMBER.STATUS = 1 AND WC_MEMBER.TYPE = 2
JOIN (SELECT TT.id ,TT.NAME FROM (
WITH RECURSIVE cte AS(
SELECT a.id, a.parent_id,a.name FROM tt_wechat_org a WHERE a.id='49'
UNION ALL
SELECT k.id, k.parent_id,k.name FROM tt_wechat_org k INNER JOIN cte c ON c.id = k.parent_id
) SELECT id,NAME,parent_id FROM cte) TT ) TREE_ORG ON TREE_ORG.id = WC_MEMBER.department
WHERE CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -6 DAY) AND HOUR(CLUE.gen_time) = 22
UNION ALL SELECT
IFNULL(SUM(CLUE.follow_total),0) AS y1 ,
SUM(DISTINCT (CASE WHEN CLUE.org_code IS NOT NULL THEN CLUE.dist_total ELSE 0 END)) a1
FROM
t_wechat_clues CLUE
JOIN t_dms_member DMS_MEMBER ON CLUE.emp_id = DMS_MEMBER.employee_id AND LENGTH(CLUE.org_code)=8 AND SUBSTR(CLUE.org_code, 1, 1)='P'
JOIN t_wechat_member WC_MEMBER ON DMS_MEMBER.wechat_emp_id = WC_MEMBER.userid AND WC_MEMBER.STATUS = 1 AND WC_MEMBER.TYPE = 2
JOIN (SELECT TT.id ,TT.NAME FROM (
WITH RECURSIVE cte AS(
SELECT a.id, a.parent_id,a.name FROM tt_wechat_org a WHERE a.id='49'
UNION ALL
SELECT k.id, k.parent_id,k.name FROM tt_wechat_org k INNER JOIN cte c ON c.id = k.parent_id
) SELECT id,NAME,parent_id FROM cte) TT ) TREE_ORG ON TREE_ORG.id = WC_MEMBER.department
WHERE CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -5 DAY) AND HOUR(CLUE.gen_time) = 22 UNION ALL SELECT
IFNULL(SUM(CLUE.follow_total),0) AS y1 ,
SUM(DISTINCT (CASE WHEN CLUE.org_code IS NOT NULL THEN CLUE.dist_total ELSE 0 END)) a1
FROM
t_wechat_clues CLUE
JOIN t_dms_member DMS_MEMBER ON CLUE.emp_id = DMS_MEMBER.employee_id AND LENGTH(CLUE.org_code)=8 AND SUBSTR(CLUE.org_code, 1, 1)='P'
JOIN t_wechat_member WC_MEMBER ON DMS_MEMBER.wechat_emp_id = WC_MEMBER.userid AND WC_MEMBER.STATUS = 1 AND WC_MEMBER.TYPE = 2
JOIN (SELECT TT.id ,TT.NAME FROM (
WITH RECURSIVE cte AS(
SELECT a.id, a.parent_id,a.name FROM tt_wechat_org a WHERE a.id='49'
UNION ALL
SELECT k.id, k.parent_id,k.name FROM tt_wechat_org k INNER JOIN cte c ON c.id = k.parent_id
) SELECT id,NAME,parent_id FROM cte) TT ) TREE_ORG ON TREE_ORG.id = WC_MEMBER.department
WHERE CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -4 DAY) AND HOUR(CLUE.gen_time) = 22 UNION ALL SELECT
IFNULL(SUM(CLUE.follow_total),0) AS y1 ,
SUM(DISTINCT (CASE WHEN CLUE.org_code IS NOT NULL THEN CLUE.dist_total ELSE 0 END)) a1
FROM
t_wechat_clues CLUE
JOIN t_dms_member DMS_MEMBER ON CLUE.emp_id = DMS_MEMBER.employee_id AND LENGTH(CLUE.org_code)=8 AND SUBSTR(CLUE.org_code, 1, 1)='P'
JOIN t_wechat_member WC_MEMBER ON DMS_MEMBER.wechat_emp_id = WC_MEMBER.userid AND WC_MEMBER.STATUS = 1 AND WC_MEMBER.TYPE = 2
JOIN (SELECT TT.id ,TT.NAME FROM (
WITH RECURSIVE cte AS(
SELECT a.id, a.parent_id,a.name FROM tt_wechat_org a WHERE a.id='49'
UNION ALL
SELECT k.id, k.parent_id,k.name FROM tt_wechat_org k INNER JOIN cte c ON c.id = k.parent_id
) SELECT id,NAME,parent_id FROM cte) TT ) TREE_ORG ON TREE_ORG.id = WC_MEMBER.department
WHERE CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -3 DAY) AND HOUR(CLUE.gen_time) = 22 UNION ALL SELECT
IFNULL(SUM(CLUE.follow_total),0) AS y1 ,
SUM(DISTINCT (CASE WHEN CLUE.org_code IS NOT NULL THEN CLUE.dist_total ELSE 0 END)) a1
FROM
t_wechat_clues CLUE
JOIN t_dms_member DMS_MEMBER ON CLUE.emp_id = DMS_MEMBER.employee_id AND LENGTH(CLUE.org_code)=8 AND SUBSTR(CLUE.org_code, 1, 1)='P'
JOIN t_wechat_member WC_MEMBER ON DMS_MEMBER.wechat_emp_id = WC_MEMBER.userid AND WC_MEMBER.STATUS = 1 AND WC_MEMBER.TYPE = 2
JOIN (SELECT TT.id ,TT.NAME FROM (
WITH RECURSIVE cte AS(
SELECT a.id, a.parent_id,a.name FROM tt_wechat_org a WHERE a.id='49'
UNION ALL
SELECT k.id, k.parent_id,k.name FROM tt_wechat_org k INNER JOIN cte c ON c.id = k.parent_id
) SELECT id,NAME,parent_id FROM cte) TT ) TREE_ORG ON TREE_ORG.id = WC_MEMBER.department
WHERE CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -2 DAY) AND HOUR(CLUE.gen_time) = 22 UNION ALL SELECT
IFNULL(SUM(CLUE.follow_total),0) AS y1 ,
SUM(DISTINCT (CASE WHEN CLUE.org_code IS NOT NULL THEN CLUE.dist_total ELSE 0 END)) a1
FROM
t_wechat_clues CLUE
JOIN t_dms_member DMS_MEMBER ON CLUE.emp_id = DMS_MEMBER.employee_id AND LENGTH(CLUE.org_code)=8 AND SUBSTR(CLUE.org_code, 1, 1)='P'
JOIN t_wechat_member WC_MEMBER ON DMS_MEMBER.wechat_emp_id = WC_MEMBER.userid AND WC_MEMBER.STATUS = 1 AND WC_MEMBER.TYPE = 2
JOIN (SELECT TT.id ,TT.NAME FROM (
WITH RECURSIVE cte AS(
SELECT a.id, a.parent_id,a.name FROM tt_wechat_org a WHERE a.id='49'
UNION ALL
SELECT k.id, k.parent_id,k.name FROM tt_wechat_org k INNER JOIN cte c ON c.id = k.parent_id
) SELECT id,NAME,parent_id FROM cte) TT ) TREE_ORG ON TREE_ORG.id = WC_MEMBER.department
WHERE CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -1 DAY) AND HOUR(CLUE.gen_time) = 22 UNION ALL SELECT
IFNULL(SUM(CLUE.follow_total),0) AS y1 ,
SUM(DISTINCT (CASE WHEN CLUE.org_code IS NOT NULL THEN CLUE.dist_total ELSE 0 END)) a1
FROM
t_wechat_clues CLUE
JOIN t_dms_member DMS_MEMBER ON CLUE.emp_id = DMS_MEMBER.employee_id AND LENGTH(CLUE.org_code)=8 AND SUBSTR(CLUE.org_code, 1, 1)='P'
JOIN t_wechat_member WC_MEMBER ON DMS_MEMBER.wechat_emp_id = WC_MEMBER.userid AND WC_MEMBER.STATUS = 1 AND WC_MEMBER.TYPE = 2
JOIN (SELECT TT.id ,TT.NAME FROM (
WITH RECURSIVE cte AS(
SELECT a.id, a.parent_id,a.name FROM tt_wechat_org a WHERE a.id='49'
UNION ALL
SELECT k.id, k.parent_id,k.name FROM tt_wechat_org k INNER JOIN cte c ON c.id = k.parent_id
) SELECT id,NAME,parent_id FROM cte) TT ) TREE_ORG ON TREE_ORG.id = WC_MEMBER.department
WHERE CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -0 DAY) AND HOUR(CLUE.gen_time) > HOUR(DATE_ADD(NOW(), INTERVAL -2 HOUR))

生产库执行结果是909ms 1秒差点就查完了

【DataBase】SQL优化案例:其一的更多相关文章

  1. SQL优化案例—— RowNumber分页

    将业务语句翻译成SQL语句不仅是一门技术,还是一门艺术. 下面拿我们程序开发工程师最常用的ROW_NUMBER()分页作为一个典型案例来说明. 先来看看我们最常见的分页的样子: WITH CTE AS ...

  2. mysql的sql优化案例

    前言 mysql的sql优化器比较弱,选择执行计划貌似很随机. 案例 一.表结构说明mysql> show create table table_order\G***************** ...

  3. SQL 优化案例 1

    create or replace procedure SP_GET_NEWEST_CAPTCHA( v_ACCOUNT_ID in VARCHAR2, --接收短信的手机号 v_Tail_num i ...

  4. SQL 优化案例

    create or replace procedure SP_GET_NEWEST_CAPTCHA( v_ACCOUNT_ID in VARCHAR2, --接收短信的手机号 v_Tail_num i ...

  5. SQL夯实基础(四):子查询及sql优化案例

    首先我们先明确一下sql语句的执行顺序,如下有前至后执行: (1)from  (2) on   (3) join  (4) where  (5)group by  (6) avg,sum...  (7 ...

  6. 百倍性能的PL/SQL优化案例(r11笔记第13天)

    我相信你是被百倍性能的字样吸引了,不过我所想侧重的是优化的思路,这个比优化技巧更重要,而结果嘛,其实我不希望说成是百倍提升,“”自黑“”一下. 有一个真实想法和大家讨论一下,就是一个SQL语句如果原本 ...

  7. 数栈SQL优化案例:隐式转换

    MySQL是当下最流行的关系型数据库之一,互联网高速发展的今天,MySQL数据库在电商.金融等诸多行业的生产系统中被广泛使用. 在实际的开发运维过程中,想必大家也常常会碰到慢SQL的困扰.一条性能不好 ...

  8. sqlserver sql优化案例及思路

    始sql: SELECT TOP 100 PERCENT ZZ.CREW_NAME AS 机组, ZZ.CREW_ID, AA.年度时间, CC.当月时间, DD.连续七天时间 AS 最近七天 FRO ...

  9. SQL 优化案例之变更表结构

    从慢日志报表中看到一条很长的SQL select id from myinfo and (( SUBSTRING_INDEX(location_axis, ) ) ) ), '$%') ) or ( ...

  10. 一则SQL优化案例

    原始sql: select CASE ) counts ,) else deadline end as deadline from t_product_credit) c group by sort ...

随机推荐

  1. LeetCode 146. LRU CacheLRU缓存机制 (C++/Java)

    题目: Design and implement a data structure for Least Recently Used (LRU) cache. It should support the ...

  2. C# .NET MVC 表单提交前校验数据等

    页面上写2个button,一个普通button,另一个是submit,submit的这个隐藏.校验函数写在普通button里,普通button click函数中去提交表单. 页面: <input ...

  3. 日志切面接口和方法demo,切面内重新抛出异常

    1. 定义切面 @Target(ElementType.METHOD) @Retention(RetentionPolicy.RUNTIME) public @interface Log { Stri ...

  4. http请求方式-HttpClient 微信退款的接口,需要证书请求 https请求

    http请求方式-HttpClient import com.alibaba.fastjson.JSON; import com.alibaba.fastjson.JSONObject; import ...

  5. Go1.13的坑:无法结束Goroutine

    背景 本人作为一名SRE,想用Go模拟Cpu占用100% 1秒钟,但是在Go1.13上遇到了问题,1s后Goroutine不会停止. 只要用了for{},Goroutine就无法结束,即使主Gorou ...

  6. DPO: Direct Preference Optimization 直接偏好优化(学习笔记)

    学习参考:链接1   一.为什么要提出DPO 在之前,我们已经了解到基于人类反馈的强化学习RLHF分为三个阶段:全监督微调(SFT).奖励模型(RM).强化学习(PPO).但是RLHF面临缺陷:RLH ...

  7. 理解shell

    理解shell shell不单单是CLI,而是一种复杂的交互式程序. 1. shell的类型 当你登录系统时,系统启动什么样的shell程序取决于你的个人用户配置.在/etc/passwd文件中,用户 ...

  8. Rougamo、Fody 实现静态Aop

    最近在看项目,看到别人使用Rougamo框架,好奇花了点时间仔细研究了,在这里记录一下. 0. 静态编织 Aop 首先,我们先了解什么是Aop? Aop 是指面向切面编程 (Aspect Orient ...

  9. 福利来了!MoneyPrinterPlus可以自动配置环境和自动运行了

    之前开源了MoneyPrinterPlus,可以实现批量混剪视频,一键生成视频和自动发布视频的功能. 但是经常会看到小伙伴在安装过程中遇到很多问题.所以这篇文章的目的就是告诉大家怎么使用MoneyPr ...

  10. hive、hbase、clickhouse

    hive相当于贝利,是计算处理数据的鼻祖,hbase相当于梅西,继承了hive(贝利)的意志,但是因为现代足球的发展,梅西整体水平要强于贝利的远古踢法(mapreduce),然后clickhouse相 ...