【DataBase】SQL优化案例:其一
原始SQL:
这里想做的事情就是查询一周的一个计算值
可以理解为报表的那种
主表 t_wechat_clue 生产库上200万数据量
然后需要联表一些限制条件
SELECT
IFNULL(SUM((CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -6 DAY) AND HOUR(CLUE.gen_time) = 22 THEN CLUE.follow_total ELSE 0 END)),0) AS y1,
IFNULL(SUM((CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -5 DAY) AND HOUR(CLUE.gen_time) = 22 THEN CLUE.follow_total ELSE 0 END)),0) AS y2,
IFNULL(SUM((CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -4 DAY) AND HOUR(CLUE.gen_time) = 22 THEN CLUE.follow_total ELSE 0 END)),0) AS y3,
IFNULL(SUM((CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -3 DAY) AND HOUR(CLUE.gen_time) = 22 THEN CLUE.follow_total ELSE 0 END)),0) AS y4,
IFNULL(SUM((CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -2 DAY) AND HOUR(CLUE.gen_time) = 22 THEN CLUE.follow_total ELSE 0 END)),0) AS y5,
IFNULL(SUM((CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -1 DAY) AND HOUR(CLUE.gen_time) = 22 THEN CLUE.follow_total ELSE 0 END)),0) AS y6,
IFNULL(SUM((CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL 0 DAY) AND HOUR(CLUE.gen_time) > HOUR(DATE_ADD(NOW(), INTERVAL -2 HOUR)) THEN CLUE.follow_total ELSE 0 END)),0) AS y7, IFNULL(SUM(DISTINCT CASE WHEN CLUE.org_code IS NOT NULL THEN (CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -6 DAY) AND HOUR(CLUE.gen_time) = 22 THEN CLUE.dist_total ELSE 0 END) ELSE 0 END), 0) AS a1,
IFNULL(SUM(DISTINCT CASE WHEN CLUE.org_code IS NOT NULL THEN (CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -5 DAY) AND HOUR(CLUE.gen_time) = 22 THEN CLUE.dist_total ELSE 0 END) ELSE 0 END), 0) AS a2,
IFNULL(SUM(DISTINCT CASE WHEN CLUE.org_code IS NOT NULL THEN (CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -4 DAY) AND HOUR(CLUE.gen_time) = 22 THEN CLUE.dist_total ELSE 0 END) ELSE 0 END), 0) AS a3,
IFNULL(SUM(DISTINCT CASE WHEN CLUE.org_code IS NOT NULL THEN (CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -3 DAY) AND HOUR(CLUE.gen_time) = 22 THEN CLUE.dist_total ELSE 0 END) ELSE 0 END), 0) AS a4,
IFNULL(SUM(DISTINCT CASE WHEN CLUE.org_code IS NOT NULL THEN (CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -2 DAY) AND HOUR(CLUE.gen_time) = 22 THEN CLUE.dist_total ELSE 0 END) ELSE 0 END), 0) AS a5,
IFNULL(SUM(DISTINCT CASE WHEN CLUE.org_code IS NOT NULL THEN (CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -1 DAY) AND HOUR(CLUE.gen_time) = 22 THEN CLUE.dist_total ELSE 0 END) ELSE 0 END), 0) AS a6,
IFNULL(SUM(DISTINCT CASE WHEN CLUE.org_code IS NOT NULL THEN (CASE WHEN CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL 0 DAY) AND HOUR(CLUE.gen_time) > HOUR(DATE_ADD(NOW(), INTERVAL -2 HOUR)) THEN CLUE.dist_total ELSE 0 END) ELSE 0 END), 0) AS a7
FROM
t_wechat_clues CLUE
JOIN t_dms_member DMS_MEMBER ON CLUE.emp_id = DMS_MEMBER.employee_id AND LENGTH(CLUE.org_code)=8 AND SUBSTR(CLUE.org_code, 1, 1)='P'
JOIN t_wechat_member WC_MEMBER ON DMS_MEMBER.wechat_emp_id = WC_MEMBER.userid AND WC_MEMBER.STATUS = 1 AND WC_MEMBER.TYPE = 2
JOIN (SELECT TT.id ,TT.NAME FROM (
WITH RECURSIVE cte AS(
SELECT a.id, a.parent_id,a.name FROM tt_wechat_org a WHERE a.id='49'
UNION ALL
SELECT k.id, k.parent_id,k.name FROM tt_wechat_org k INNER JOIN cte c ON c.id = k.parent_id
) SELECT id,NAME,parent_id FROM cte) TT ) TREE_ORG ON TREE_ORG.id = WC_MEMBER.department
反正实际上数据返回到页面渲染Echarts花了10秒的样子
经理说8行,必须要改动
前提情况是,这里联表的字段和日期时间都做了索引处理
慢的原因是查询的字段导致
另外还有就是联表的字段数据类型需要一致
不要让MySQL去推导转换,这会浪费一部分性能
优化之后:
随后同事给我一套UnionALL解法,虽然SQL很多,但是效率提升明显!
SELECT
IFNULL(SUM(CLUE.follow_total),0) AS y1 ,
SUM(DISTINCT (CASE WHEN CLUE.org_code IS NOT NULL THEN CLUE.dist_total ELSE 0 END)) a1
FROM
t_wechat_clues CLUE
JOIN t_dms_member DMS_MEMBER ON CLUE.emp_id = DMS_MEMBER.employee_id AND LENGTH(CLUE.org_code)=8 AND SUBSTR(CLUE.org_code, 1, 1)='P'
JOIN t_wechat_member WC_MEMBER ON DMS_MEMBER.wechat_emp_id = WC_MEMBER.userid AND WC_MEMBER.STATUS = 1 AND WC_MEMBER.TYPE = 2
JOIN (SELECT TT.id ,TT.NAME FROM (
WITH RECURSIVE cte AS(
SELECT a.id, a.parent_id,a.name FROM tt_wechat_org a WHERE a.id='49'
UNION ALL
SELECT k.id, k.parent_id,k.name FROM tt_wechat_org k INNER JOIN cte c ON c.id = k.parent_id
) SELECT id,NAME,parent_id FROM cte) TT ) TREE_ORG ON TREE_ORG.id = WC_MEMBER.department
WHERE CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -6 DAY) AND HOUR(CLUE.gen_time) = 22
UNION ALL SELECT
IFNULL(SUM(CLUE.follow_total),0) AS y1 ,
SUM(DISTINCT (CASE WHEN CLUE.org_code IS NOT NULL THEN CLUE.dist_total ELSE 0 END)) a1
FROM
t_wechat_clues CLUE
JOIN t_dms_member DMS_MEMBER ON CLUE.emp_id = DMS_MEMBER.employee_id AND LENGTH(CLUE.org_code)=8 AND SUBSTR(CLUE.org_code, 1, 1)='P'
JOIN t_wechat_member WC_MEMBER ON DMS_MEMBER.wechat_emp_id = WC_MEMBER.userid AND WC_MEMBER.STATUS = 1 AND WC_MEMBER.TYPE = 2
JOIN (SELECT TT.id ,TT.NAME FROM (
WITH RECURSIVE cte AS(
SELECT a.id, a.parent_id,a.name FROM tt_wechat_org a WHERE a.id='49'
UNION ALL
SELECT k.id, k.parent_id,k.name FROM tt_wechat_org k INNER JOIN cte c ON c.id = k.parent_id
) SELECT id,NAME,parent_id FROM cte) TT ) TREE_ORG ON TREE_ORG.id = WC_MEMBER.department
WHERE CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -5 DAY) AND HOUR(CLUE.gen_time) = 22 UNION ALL SELECT
IFNULL(SUM(CLUE.follow_total),0) AS y1 ,
SUM(DISTINCT (CASE WHEN CLUE.org_code IS NOT NULL THEN CLUE.dist_total ELSE 0 END)) a1
FROM
t_wechat_clues CLUE
JOIN t_dms_member DMS_MEMBER ON CLUE.emp_id = DMS_MEMBER.employee_id AND LENGTH(CLUE.org_code)=8 AND SUBSTR(CLUE.org_code, 1, 1)='P'
JOIN t_wechat_member WC_MEMBER ON DMS_MEMBER.wechat_emp_id = WC_MEMBER.userid AND WC_MEMBER.STATUS = 1 AND WC_MEMBER.TYPE = 2
JOIN (SELECT TT.id ,TT.NAME FROM (
WITH RECURSIVE cte AS(
SELECT a.id, a.parent_id,a.name FROM tt_wechat_org a WHERE a.id='49'
UNION ALL
SELECT k.id, k.parent_id,k.name FROM tt_wechat_org k INNER JOIN cte c ON c.id = k.parent_id
) SELECT id,NAME,parent_id FROM cte) TT ) TREE_ORG ON TREE_ORG.id = WC_MEMBER.department
WHERE CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -4 DAY) AND HOUR(CLUE.gen_time) = 22 UNION ALL SELECT
IFNULL(SUM(CLUE.follow_total),0) AS y1 ,
SUM(DISTINCT (CASE WHEN CLUE.org_code IS NOT NULL THEN CLUE.dist_total ELSE 0 END)) a1
FROM
t_wechat_clues CLUE
JOIN t_dms_member DMS_MEMBER ON CLUE.emp_id = DMS_MEMBER.employee_id AND LENGTH(CLUE.org_code)=8 AND SUBSTR(CLUE.org_code, 1, 1)='P'
JOIN t_wechat_member WC_MEMBER ON DMS_MEMBER.wechat_emp_id = WC_MEMBER.userid AND WC_MEMBER.STATUS = 1 AND WC_MEMBER.TYPE = 2
JOIN (SELECT TT.id ,TT.NAME FROM (
WITH RECURSIVE cte AS(
SELECT a.id, a.parent_id,a.name FROM tt_wechat_org a WHERE a.id='49'
UNION ALL
SELECT k.id, k.parent_id,k.name FROM tt_wechat_org k INNER JOIN cte c ON c.id = k.parent_id
) SELECT id,NAME,parent_id FROM cte) TT ) TREE_ORG ON TREE_ORG.id = WC_MEMBER.department
WHERE CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -3 DAY) AND HOUR(CLUE.gen_time) = 22 UNION ALL SELECT
IFNULL(SUM(CLUE.follow_total),0) AS y1 ,
SUM(DISTINCT (CASE WHEN CLUE.org_code IS NOT NULL THEN CLUE.dist_total ELSE 0 END)) a1
FROM
t_wechat_clues CLUE
JOIN t_dms_member DMS_MEMBER ON CLUE.emp_id = DMS_MEMBER.employee_id AND LENGTH(CLUE.org_code)=8 AND SUBSTR(CLUE.org_code, 1, 1)='P'
JOIN t_wechat_member WC_MEMBER ON DMS_MEMBER.wechat_emp_id = WC_MEMBER.userid AND WC_MEMBER.STATUS = 1 AND WC_MEMBER.TYPE = 2
JOIN (SELECT TT.id ,TT.NAME FROM (
WITH RECURSIVE cte AS(
SELECT a.id, a.parent_id,a.name FROM tt_wechat_org a WHERE a.id='49'
UNION ALL
SELECT k.id, k.parent_id,k.name FROM tt_wechat_org k INNER JOIN cte c ON c.id = k.parent_id
) SELECT id,NAME,parent_id FROM cte) TT ) TREE_ORG ON TREE_ORG.id = WC_MEMBER.department
WHERE CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -2 DAY) AND HOUR(CLUE.gen_time) = 22 UNION ALL SELECT
IFNULL(SUM(CLUE.follow_total),0) AS y1 ,
SUM(DISTINCT (CASE WHEN CLUE.org_code IS NOT NULL THEN CLUE.dist_total ELSE 0 END)) a1
FROM
t_wechat_clues CLUE
JOIN t_dms_member DMS_MEMBER ON CLUE.emp_id = DMS_MEMBER.employee_id AND LENGTH(CLUE.org_code)=8 AND SUBSTR(CLUE.org_code, 1, 1)='P'
JOIN t_wechat_member WC_MEMBER ON DMS_MEMBER.wechat_emp_id = WC_MEMBER.userid AND WC_MEMBER.STATUS = 1 AND WC_MEMBER.TYPE = 2
JOIN (SELECT TT.id ,TT.NAME FROM (
WITH RECURSIVE cte AS(
SELECT a.id, a.parent_id,a.name FROM tt_wechat_org a WHERE a.id='49'
UNION ALL
SELECT k.id, k.parent_id,k.name FROM tt_wechat_org k INNER JOIN cte c ON c.id = k.parent_id
) SELECT id,NAME,parent_id FROM cte) TT ) TREE_ORG ON TREE_ORG.id = WC_MEMBER.department
WHERE CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -1 DAY) AND HOUR(CLUE.gen_time) = 22 UNION ALL SELECT
IFNULL(SUM(CLUE.follow_total),0) AS y1 ,
SUM(DISTINCT (CASE WHEN CLUE.org_code IS NOT NULL THEN CLUE.dist_total ELSE 0 END)) a1
FROM
t_wechat_clues CLUE
JOIN t_dms_member DMS_MEMBER ON CLUE.emp_id = DMS_MEMBER.employee_id AND LENGTH(CLUE.org_code)=8 AND SUBSTR(CLUE.org_code, 1, 1)='P'
JOIN t_wechat_member WC_MEMBER ON DMS_MEMBER.wechat_emp_id = WC_MEMBER.userid AND WC_MEMBER.STATUS = 1 AND WC_MEMBER.TYPE = 2
JOIN (SELECT TT.id ,TT.NAME FROM (
WITH RECURSIVE cte AS(
SELECT a.id, a.parent_id,a.name FROM tt_wechat_org a WHERE a.id='49'
UNION ALL
SELECT k.id, k.parent_id,k.name FROM tt_wechat_org k INNER JOIN cte c ON c.id = k.parent_id
) SELECT id,NAME,parent_id FROM cte) TT ) TREE_ORG ON TREE_ORG.id = WC_MEMBER.department
WHERE CLUE.gen_date = DATE_ADD(CURRENT_DATE,INTERVAL -0 DAY) AND HOUR(CLUE.gen_time) > HOUR(DATE_ADD(NOW(), INTERVAL -2 HOUR))
生产库执行结果是909ms 1秒差点就查完了
【DataBase】SQL优化案例:其一的更多相关文章
- SQL优化案例—— RowNumber分页
将业务语句翻译成SQL语句不仅是一门技术,还是一门艺术. 下面拿我们程序开发工程师最常用的ROW_NUMBER()分页作为一个典型案例来说明. 先来看看我们最常见的分页的样子: WITH CTE AS ...
- mysql的sql优化案例
前言 mysql的sql优化器比较弱,选择执行计划貌似很随机. 案例 一.表结构说明mysql> show create table table_order\G***************** ...
- SQL 优化案例 1
create or replace procedure SP_GET_NEWEST_CAPTCHA( v_ACCOUNT_ID in VARCHAR2, --接收短信的手机号 v_Tail_num i ...
- SQL 优化案例
create or replace procedure SP_GET_NEWEST_CAPTCHA( v_ACCOUNT_ID in VARCHAR2, --接收短信的手机号 v_Tail_num i ...
- SQL夯实基础(四):子查询及sql优化案例
首先我们先明确一下sql语句的执行顺序,如下有前至后执行: (1)from (2) on (3) join (4) where (5)group by (6) avg,sum... (7 ...
- 百倍性能的PL/SQL优化案例(r11笔记第13天)
我相信你是被百倍性能的字样吸引了,不过我所想侧重的是优化的思路,这个比优化技巧更重要,而结果嘛,其实我不希望说成是百倍提升,“”自黑“”一下. 有一个真实想法和大家讨论一下,就是一个SQL语句如果原本 ...
- 数栈SQL优化案例:隐式转换
MySQL是当下最流行的关系型数据库之一,互联网高速发展的今天,MySQL数据库在电商.金融等诸多行业的生产系统中被广泛使用. 在实际的开发运维过程中,想必大家也常常会碰到慢SQL的困扰.一条性能不好 ...
- sqlserver sql优化案例及思路
始sql: SELECT TOP 100 PERCENT ZZ.CREW_NAME AS 机组, ZZ.CREW_ID, AA.年度时间, CC.当月时间, DD.连续七天时间 AS 最近七天 FRO ...
- SQL 优化案例之变更表结构
从慢日志报表中看到一条很长的SQL select id from myinfo and (( SUBSTRING_INDEX(location_axis, ) ) ) ), '$%') ) or ( ...
- 一则SQL优化案例
原始sql: select CASE ) counts ,) else deadline end as deadline from t_product_credit) c group by sort ...
随机推荐
- VmWare虚拟机和主机配置为同一网段IP
参考博客:将虚拟机IP与主机IP设置在同一网段的方法 - 天懿 - 博客园 (cnblogs.com) 主机地址 主机通过WiFi连接,地址信息为: 虚拟机配置 选择编辑-->虚拟网络编辑器-- ...
- Linux Topicons Plus桌面工具安装
Topicons Plus是Linux系统GNOME桌面环境的工具,方便于在工具栏显示应用小图标. 1.进入GNOME商店搜搜下载TopIcons Plus工具.下载路径:https://extens ...
- Spring扩展——BeanPostProcessor(BPP)
BeanPostProcess简介 在Spring中 BeanPostProcessor 是一个非常重要的接口,它用于在每个bean对象初始化前后修改Bean的属性信息,比如我们最常用的@Autowi ...
- html 适配iphone X 底部导航
html 适配iphone X 底部导航 适配手机底部有横线的手机,以免被横线遮挡 padding-bottom: constant(safe-area-inset-bottom); /* 兼容 iO ...
- Java动态获取实现类 Class.forName(clazz).newInstance()和applicationContext.getBean, bean Map寻找方式,Java Map定义和初始化方法
Java动态获取实现类 Class.forName(clazz).newInstance()和applicationContext.getBean, bean Map寻找方式,Java Map定义和初 ...
- maven和gradle环境变量配置及idea相关的设置
1.maven 环境变量添加之后,重新打开cmd窗口,验证是否配置成功. idea File >> Settings idea配置之后的验证: 2.gradle 环境变量添加之后,重新 ...
- httpx的使用
urllib和requests库已经可以爬取大多数网站的数据,但对于一些强制使用HTTP/2.0协议访问,这时urllib和requests是无法爬取数据的,因为只支持HTTP/1.1,不支持HTTP ...
- Windows无法访问vsftpd
在搭建vsftpd的时候注意放行相应的服务,注意,是服务,不是端口!! 如果你简单的--add-port放行20和21端口,那么恭喜你,就是访问不了. 正确的方法是--add-service=ftp, ...
- HTTP协议 学习:1-报文分析
HTTP协议 学习:1-报文分析 背景 上一讲我们介绍了HTTP协议的一些 概念 ,对HTTP协议有了一个基础的认识. 正如之前学习MQTT协议一样,我们需要对HTTP的报文进行分析. HTTP 报文 ...
- 【资料分享】Xilinx XCZU7EV工业核心板规格书(四核ARM Cortex-A53 + 双核ARM Cortex-R5 + FPGA,主频1.5GHz)
1 核心板简介 创龙科技SOM-TLZU是一款基于Xilinx UltraScale+ MPSoC系列XCZU7EV高性能处理器设计的高端异构多核SoC工业核心板,处理器集成PS端(四核ARM Cor ...