Java实现 N的阶乘

import java.util.Scanner;
public class n的阶乘 {
public static void main(String[] args) {
	Scanner sc =new Scanner(System.in);
	int n = sc.nextInt();
	  int num[] = new int[10000000];
      int i, j;
      if (n == 1 || n == 0) {
          System.out.println(1);
      } else {
          int p, h;// p 存放当前结果的位数，h为进位；
          p = 1;
          h = 0;
          num[1] = 1;
          for (i = 2; i <= n; i++) {
              // 使得a[]的每位与i相乘
              for (j = 1; j <= p; j++) {
                  num[j] = num[j] * i + h;
                  h = num[j] / 10;
                  num[j] = num[j] % 10;
              }
              // 表示向新的位置进位
              while (h > 0) {
                  num[j] = h % 10;
                  h = h / 10;
                  j++;
              }
              p = j - 1;
          }
          for (i = p; i >= 1; i--) {
              System.out.print(num[i]);
          }
      }
}

}