SRM 396(1-250pt)

DIV1 250pt

题意：对于一个字符串s，若对于每一个i = 0 to s.size()-p-1都有s[i] = s[i+p]则称字符串s是p循环的。"CATCATC", "CATCAT", "ACTAC" , "ACT"都是3循环。给定字符串s和一个数字ma，问至少修改多少个s中字符才能使得s变为k循环的，且k <= ma。

解法：水题，暴力枚举k = 1 to ma即可。

tag:think

 // BEGIN CUT HERE
 /*
  * Author:  plum rain
  * score :
  */
 /*

  */
 // END CUT HERE
 #line 11 "DNAString.cpp"
 #include <sstream>
 #include <stdexcept>
 #include <functional>
 #include <iomanip>
 #include <numeric>
 #include <fstream>
 #include <cctype>
 #include <iostream>
 #include <cstdio>
 #include <vector>
 #include <cstring>
 #include <cmath>
 #include <algorithm>
 #include <cstdlib>
 #include <set>
 #include <queue>
 #include <bitset>
 #include <list>
 #include <string>
 #include <utility>
 #include <map>
 #include <ctime>
 #include <stack>

 using namespace std;

 #define clr0(x) memset(x, 0, sizeof(x))
 #define clr1(x) memset(x, -1, sizeof(x))
 #define pb push_back
 #define sz(v) ((int)(v).size())
 #define all(t) t.begin(),t.end()
 #define zero(x) (((x)>0?(x):-(x))<eps)
 #define out(x) cout<<#x<<":"<<(x)<<endl
 #define tst(a) cout<<a<<" "
 #define tst1(a) cout<<#a<<endl
 #define CINBEQUICKER std::ios::sync_with_stdio(false)

 typedef vector<int> VI;
 typedef vector<string> VS;
 typedef vector<double> VD;
 typedef pair<int, int> pii;
 typedef long long int64;

 const double eps = 1e-;
 const double PI = atan(1.0)*;
 const int inf =  / ;

 string s;
 int d[];
 string temp = "ACTG";

 int gao(int x)
 {
     int ret = ;
     for (int i = ; i < x; ++ i){
         clr0 (d);
         int j = i;
         while (j < sz(s)){
             for (int t = ; t < ; ++ t)
                 if (temp[t] == s[j]) ++ d[t];
             j += x;
         }
         int ma = , sum = ;
         for (int k = ; k < ; ++ k)
             ma = max(ma, d[k]), sum += d[k];
         ret += sum - ma;
     }
     return ret;
 }

 class DNAString
 {
     public:
         int minChanges(int m, vector<string> dna){
             s = accumulate(dna.begin(), dna.end(), string(""));
             int ans = inf;
             for (int i = ; i <= m; ++ i) ans = min(ans, gao(i));
             return ans;
         }

 // BEGIN CUT HERE
     public:
     void run_test(int Case) { if ((Case == -) || (Case == )) test_case_0(); if ((Case == -) || (Case == )) test_case_1(); if ((Case == -) || (Case == )) test_case_2(); if ((Case == -) || (Case == )) test_case_3(); if ((Case == -) || (Case == )) test_case_4(); }
     private:
     template <typename T> string print_array(const vector<T> &V) { ostringstream os; os << "{ "; for (typename vector<T>::const_iterator iter = V.begin(); iter != V.end(); ++iter) os << '\"' << *iter << "\","; os << " }"; return os.str(); }
     void verify_case(int Case, const int &Expected, const int &Received) { cerr << "Test Case #" << Case << "..."; if (Expected == Received) cerr << "PASSED" << endl; else { cerr << "FAILED" << endl; cerr << "\tExpected: \"" << Expected << '\"' << endl; cerr << "\tReceived: \"" << Received << '\"' << endl; } }
     void test_case_0() { int Arg0 = ; string Arr1[] = {"ATAGATA"}; vector <string> Arg1(Arr1, Arr1 + (sizeof(Arr1) / sizeof(Arr1[]))); int Arg2 = ; verify_case(, Arg2, minChanges(Arg0, Arg1)); }
     void test_case_1() { int Arg0 = ; string Arr1[] = {"ACGTGCA"}; vector <string> Arg1(Arr1, Arr1 + (sizeof(Arr1) / sizeof(Arr1[]))); int Arg2 = ; verify_case(, Arg2, minChanges(Arg0, Arg1)); }
     void test_case_2() { int Arg0 = ; string Arr1[] = {"ACGCTGACAGATA"}; vector <string> Arg1(Arr1, Arr1 + (sizeof(Arr1) / sizeof(Arr1[]))); int Arg2 = ; verify_case(, Arg2, minChanges(Arg0, Arg1)); }
     void test_case_3() { int Arg0 = ; string Arr1[] = {"AAAATTTCCG"}; vector <string> Arg1(Arr1, Arr1 + (sizeof(Arr1) / sizeof(Arr1[]))); int Arg2 = ; verify_case(, Arg2, minChanges(Arg0, Arg1)); }
     void test_case_4() { int Arg0 = ; string Arr1[] = {"ACGTATAGCATGACA","ACAGATATTATG","ACAGATGTAGCAGTA","ACCA","GAC"}; vector <string> Arg1(Arr1, Arr1 + (sizeof(Arr1) / sizeof(Arr1[]))); int Arg2 = ; verify_case(, Arg2, minChanges(Arg0, Arg1)); }

 // END CUT HERE

 };

 // BEGIN CUT HERE
 int main()
 {
 //    freopen( "a.out" , "w" , stdout );
     DNAString ___test;
     ___test.run_test(-);
        return ;
 }
 // END CUT HERE