Stacks of Flapjacks
| Stacks of Flapjacks |
Background
Stacks and Queues are often considered the bread and butter of data structures and find use in architecture, parsing, operating systems, and discrete event simulation. Stacks are also important in the theory of formal languages.
This problem involves both butter and sustenance in the form of pancakes rather than bread in addition to a finicky server who flips pancakes according to a unique, but complete set of rules.
The Problem
Given a stack of pancakes, you are to write a program that indicates how the stack can be sorted so that the largest pancake is on the bottom and the smallest pancake is on the top. The size of a pancake is given by the pancake's
diameter. All pancakes in a stack have different diameters.
Sorting a stack is done by a sequence of pancake ``flips''. A flip consists of inserting a spatula between two pancakes in a stack and flipping (reversing) the pancakes on the spatula (reversing the sub-stack). A flip is specified
by giving the position of the pancake on the bottom of the sub-stack to be flipped (relative to the whole stack). The pancake on the bottom of the whole stack has position 1 and the pancake on the top of a stack of
n pancakes has position n.
A stack is specified by giving the diameter of each pancake in the stack in the order in which the pancakes appear.
For example, consider the three stacks of pancakes below (in which pancake 8 is the top-most pancake of the left stack):
8 7 2
4 6 5
6 4 8
7 8 4
5 5 6
2 2 7
The stack on the left can be transformed to the stack in the middle via
flip(3). The middle stack can be transformed into the right stack via the command
flip(1).
The Input
The input consists of a sequence of stacks of pancakes. Each stack will consist of between 1 and 30 pancakes and each pancake will have an integer diameter between 1 and 100. The input is terminated by end-of-file. Each stack
is given as a single line of input with the top pancake on a stack appearing first on a line, the bottom pancake appearing last, and all pancakes separated by a space.
The Output
For each stack of pancakes, the output should echo the original stack on one line, followed by some sequence of flips that results in the stack of pancakes being sorted so that the largest diameter pancake is on the bottom and
the smallest on top. For each stack the sequence of flips should be terminated by a 0 (indicating no more flips necessary). Once a stack is sorted, no more flips should be made.
Sample Input
1 2 3 4 5
5 4 3 2 1
5 1 2 3 4
Sample Output
1 2 3 4 5
0
5 4 3 2 1
1 0
5 1 2 3 4
1 2 0
#include<cstdio>
#include<iostream>
#include<sstream>
#include<algorithm>
using namespace std; const int maxn = 30 + 5;
int n, a[maxn]; void flip(int p)
{
for(int i = 0; i < p-i; i++)
swap(a[i], a[p-i]);
printf("%d ", n-p);
} int main()
{
string s;
while(getline(cin, s))
{
cout << s << "\n";
stringstream ss(s);
n = 0;
while(ss >> a[n]) n++;
cout<<n<<endl;
for(int i = n-1; i > 0; i--)
{
//找到当前最大值所在的位置;
int p = max_element(a, a+i+1) - a;
cout<<p<<endl;
//假设最大值与它所在的位置同样,继续下一个;
if(p == i) continue;
//转换;将最大值放到第一个位置;
if(p > 0) flip(p);
flip(i);
}
printf("0\n");
}
return 0;
}
Stacks of Flapjacks的更多相关文章
- uva 120 stacks of flapjacks ——yhx
Stacks of Flapjacks Background Stacks and Queues are often considered the bread and butter of data ...
- UVaOJ 120 - Stacks of Flapjacks
120 - Stacks of Flapjacks 题目看了半天......英语啊!!! 好久没做题...循环输入数字都搞了半天...罪过啊!!! 还是C方便一点...其实C++应该更方便的...C+ ...
- Uva 120 - Stacks of Flapjacks(构造法)
UVA - 120 Stacks of Flapjacks Time Limit: 3000MS Memory Limit: Unknown 64bit IO Format: %lld &a ...
- uva Stacks of Flapjacks
Stacks of Flapjacks 题目链接:Click Here~ 题目描写叙述: ...
- 【思维】Stacks of Flapjacks
[UVa120] Stacks of Flapjacks 算法入门经典第8章8-1 (P236) 题目大意:有一个序列,可以翻转[1,k],构造一种方案使得序列升序排列. 试题分析:从插入排序即可找到 ...
- Stacks of Flapjacks(栈)
Stacks of Flapjacks Background Stacks and Queues are often considered the bread and butter of data ...
- UVa120 - Stacks of Flapjacks
Time limit: 3.000 seconds限时:3.000秒 Background背景 Stacks and Queues are often considered the bread and ...
- B - Stacks of Flapjacks UVA - 120
BackgroundStacks and Queues are often considered the bread and butter of data structures and find us ...
- UVa 120 Stacks of Flapjacks【构造法】
题意:给出n张煎饼,从上到下输入,每张煎饼上面都有一个数字,厨师每次可以选择第k张煎饼,进行翻转操作,设计一种方法使得所有煎饼按照从小到大排序(最上面的煎饼最小) 首先是这个翻转的操作,如下图 如图所 ...
随机推荐
- Python 标准库 csv —— csv 文件的读写
csv 文件,逗号分割文件. 0. 读取 csv 到 list from csv import reader def load_csv(csvfile): dataset = [] with open ...
- 3.SOAP和WSDL的一些必要知识
转自:https://www.cnblogs.com/JeffreySun/archive/2009/12/14/1623766.html SOAP和WSDL对Web Service.WCF进行深入了 ...
- Python基础教程之第1章 基础知识
#1.1 安装Python #1.1.1 Windows #1.1.2 Linux和UNIX #1.1.3 Macintosh #1.1.4 其它公布版 #1.1.5 时常关注.保持更新 #1.2 交 ...
- 玩转Bootstrap(基础) -- (6.导航条基础)
1.导航条样例 <!DOCTYPE HTML> <html> <head> <meta http-equiv="Content-Type" ...
- elasticsearch节点间通信的基础transport
在前一篇中我们分析了cluster的一些元素.接下来的章节会对cluster的运作机制做详细分析.本节先分析一些transport,它是cluster间通信的基础.它有两种实现,一种是基于netty实 ...
- POJ 1466 Girls and Boys (ZOJ 1137 )最大独立点集
http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=137 http://poj.org/problem?id=1466 题目大意: ...
- MySQL 概述和基础
# MySQL 概述 什么是数据库 存储数据的仓库 都有哪些公司在用数据库 金融机构.游戏网站.购物网站.论坛网站-- 提供数据库服务的软件 MySQL.Oracle.SQL Server.DB2.M ...
- 每天自动备份MySQL数据库的shell脚本
经常备份数据库是一个好习惯,虽然数据库损坏或数据丢失的概率很低,但一旦发生这种事情,后悔是没用的.一般网站或应用的后台都有备份数据库的功能按钮,但需要去手工执行.我们需要一种安全的,每天自动备份的方法 ...
- 卫星网络中使用TCP协议的劣势(所以才有TCP优化版用来卫星通信啊,比如TCP-Peach和ADolar)
卫星网络中使用TCP协议的劣势 为了避免产生网络拥塞,原TCP协议综合采用了慢启动.拥塞避免.快速重传以及快速恢复等算法.但这些算法应用的前提是网络发生拥塞造成丢包,然而在误码率相对较高的卫星通信系统 ...
- Oracle分页查询的一个存储过程:
create or replace procedure AspNetOraclePager( tableName in varchar2, --表名 fields in var ...