D - The Child and Sequence

思路:

  因为有区间取模操作所以没法用标记下传;

  我们发现,当一个数小于要取模的值时就可以放弃;

  凭借这个来减少更新线段树的次数;

来,上代码:

#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm> using namespace std; #define maxn 100005
#define ll long long struct TreeNodeType {
ll l, r, mid, dis, max;
};
struct TreeNodeType tree[maxn << ]; ll n,m; inline void in(ll &now)
{
char Cget = getchar(); now = ;
while (Cget > '' || Cget < '') Cget = getchar();
while (Cget >= ''&&Cget <= '')
{
now = now * + Cget - '';
Cget = getchar();
}
} void tree_build(ll now, ll l, ll r)
{
tree[now].l = l, tree[now].r = r;
if (l == r)
{
in(tree[now].dis);
tree[now].max = tree[now].dis;
return;
}
tree[now].mid = l + r >> ;
tree_build(now << , l, tree[now].mid);
tree_build(now << | , tree[now].mid + , r);
tree[now].dis = tree[now << ].dis + tree[now << | ].dis;
tree[now].max = max(tree[now << ].max, tree[now << | ].max);
} void tree_to(ll now, ll to,ll x)
{
if (tree[now].l == tree[now].r)
{
tree[now].dis = x;
tree[now].max = x;
return;
}
if (to <= tree[now].mid) tree_to(now << , to, x);
else tree_to(now << | , to, x);
tree[now].dis = tree[now << ].dis + tree[now << | ].dis;
tree[now].max = max(tree[now << ].max, tree[now << | ].max);
} void tree_mod(ll now, ll l, ll r, ll x)
{
if (tree[now].max < x) return;
if (tree[now].l >= l&&tree[now].r <= r) tree[now].dis %= x, tree[now].max %= x;
if (tree[now].l == tree[now].r) return;
if (l <= tree[now].mid) tree_mod(now << , l, r, x);
if (r > tree[now].mid) tree_mod(now << |, l, r, x);
tree[now].dis = tree[now << ].dis + tree[now << | ].dis;
tree[now].max = max(tree[now << ].max, tree[now << | ].max);
//cout <<"^ "<< l << ' ' << r << ' ' << tree[now].dis << ' ' << tree[now].max << endl;
} ll tree_query(ll now, ll l, ll r)
{
if (tree[now].l == l&&tree[now].r == r) return tree[now].dis;
if (l > tree[now].mid) return tree_query(now << | , l, r);
else if (r <= tree[now].mid) return tree_query(now << , l, r);
else return tree_query(now << , l, tree[now].mid) + tree_query(now << | , tree[now].mid + , r);
} int main()
{
in(n), in(m);
tree_build(, , n);
ll op, u, v, x;
for (; m--;)
{
in(op),in(u),in(v);
if (op == ) printf("%lld\n", tree_query(, u, v));
if (op == ) in(x), tree_mod(, u, v, x);
if (op == ) tree_to(, u, v);
}
return ;
}

AC日记——The Child and Sequence codeforces 250D的更多相关文章

  1. AC日记——Sagheer and Nubian Market codeforces 812c

    C - Sagheer and Nubian Market 思路: 二分: 代码: #include <bits/stdc++.h> using namespace std; #defin ...

  2. AC日记——Red and Blue Balls codeforces 399b

    399B - Red and Blue Balls 思路: 惊讶的发现,所有的蓝球的消除都是独立的: 对于在栈中深度为i的蓝球消除需要2^i次操作: 代码: #include <cstdio&g ...

  3. AC日记——Andryusha and Colored Balloons codeforces 780c

    C - Andryusha and Colored Balloons 思路: 水题: 代码: #include <cstdio> #include <cstring> #inc ...

  4. AC日记——Little Elephant and Shifts codeforces 221e

    E - Little Elephant and Shifts 思路: 一次函数线段树(疯狂debug): b不断循环左移,判断每次最小的|i-j|,a[i]=b[j]: 仔细观察发现,每个bi移动时, ...

  5. AC日记——Little Elephant and Problem codeforces 221c

    221C 思路: 水题: 代码: #include <cstdio> #include <cstring> #include <iostream> #include ...

  6. AC日记——Little Elephant and Array codeforces 221d

    221D - Little Elephant and Array 思路: 莫队: 代码: #include <cmath> #include <cstdio> #include ...

  7. AC日记——Little Elephant and Numbers codeforces 221b

    221B - Little Elephant and Numbers 思路: 水题: 代码: #include <cmath> #include <cstdio> #inclu ...

  8. AC日记——Little Elephant and Function codeforces 221a

    A - Little Elephant and Function 思路: 水题: 代码: #include <cstdio> #include <iostream> using ...

  9. Codeforces Round #250 (Div. 1) D. The Child and Sequence 线段树 区间取摸

    D. The Child and Sequence Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest ...

随机推荐

  1. Block那些事儿

    1.Block底层原理实现 首先我们来看四个函数 void test1() { int a = 10; void (^block)() = ^{ NSLog(@"a is %d", ...

  2. groupNoAdj

    public boolean groupNoAdj(int start, int[] nums, int target) { if( start >= nums.length){ return ...

  3. php中utf-8转unicode

    public function utf8_unicode($str) { $unicode = array(); $values = array(); $lookingFor = 1; for ($i ...

  4. php jsonp单引号转义

    php中jsonp输出时一般用下面的格式: callbackname('json string'); 如果中间的json string中含有单引号,这个输出就是有问题的,调用方一般是无法处理的,所以我 ...

  5. Bat 修改 xml 文件标签值

    xml 文件如下: <ConfigurationData> <ReportsFolder>\Reports</ReportsFolder> <Helpfold ...

  6. hnust 罚时计算器

    问题 F: 罚时计算器 时间限制: 1 Sec  内存限制: 128 MB提交: 229  解决: 63[提交][状态][讨论版] 题目描述 一般 ACM程序设计比赛都是五个小时.但是比赛结束时,DB ...

  7. Linux大小端模式转换函数

    转自 http://www.cnblogs.com/kungfupanda/archive/2013/04/24/3040785.html 不同机器内部对变量的字节存储顺序不同,有的采用大端模式(bi ...

  8. JavaScript各种数据类型

    (一)JavaScript跟Java.Python等语言一样,也是一门编程语言,配合着html,css等可以让画面动起来, 在页面中导入方式主要有两种,如图 可以自己写在文件里面,一般写在body标签 ...

  9. 洛谷 P1503 鬼子进村 解题报告

    P1503 鬼子进村 题目背景 小卡正在新家的客厅中看电视.电视里正在播放放了千八百次依旧重播的<亮剑>,剧中李云龙带领的独立团在一个县城遇到了一个鬼子小队,于是独立团与鬼子展开游击战. ...

  10. Web实现数据库链接的登录注册修改密码功能

    /** * Copyright (C), 2017-2017 * FileName: User * Author: ichimoku * Date: 2017/12/5 14:31 * version ...