Registration system

A new e-mail service "Berlandesk" is going to be opened in Berland in the near future. The site administration wants to launch their project as soon as possible, that's why they ask you to help. You're suggested to implement the prototype of site registration system. The system should work on the following principle.

Each time a new user wants to register, he sends to the system a request with his name. If such a name does not exist in the system database, it is inserted into the database, and the user gets the response OK, confirming the successful registration. If the name already exists in the system database, the system makes up a new user name, sends it to the user as a prompt and also inserts the prompt into the database. The new name is formed by the following rule. Numbers, starting with 1, are appended one after another to name (name1, name2, ...), among these numbers the least i is found so that namei does not yet exist in the database.

Input

The first line contains number n (1 ≤ n ≤ 105). The following n lines contain the requests to the system. Each request is a non-empty line, and consists of not more than 32 characters, which are all lowercase Latin letters.

Output

Print n lines, which are system responses to the requests: OK in case of successful registration, or a prompt with a new name, if the requested name is already taken.

Examples
input

Copy
4
abacaba
acaba
abacaba
acab
output

Copy
OK
OK
abacaba1
OK
input

Copy
6
first
first
second
second
third
third
output

Copy
OK
first1
OK
second1
OK
third1 用的map做的。
#include <bits/stdc++.h>
using namespace std;
map<string, int> c;
int main()
{
//ios::sync_with_stdio(false);
//cin.tie(0);
c.clear();
int t,i;
char s[];
scanf("%d ",&t);
for(i=;i<=t;i++)
{
cin>>s;
c[s]++;
auto p=c.find(s);
if(p->second>) cout<<p->first<<p->second-<<endl;
else cout<<"OK"<<endl;
}
return ;
}

codeforces Registration system的更多相关文章

  1. Codeforces Beta Round #4 (Div. 2 Only) C. Registration system hash

    C. Registration system Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/problemset ...

  2. Codeforces Beta Round #4 (Div. 2 Only) C. Registration system【裸hash/map】

    C. Registration system time limit per test 5 seconds memory limit per test 64 megabytes input standa ...

  3. (用了map) Registration system

    http://acm.hust.edu.cn/vjudge/contest/view.action?cid=93241#problem/C (654123) http://codeforces.com ...

  4. ACM Registration system

    Registration system 时间限制:1000 ms  |  内存限制:65535 KB 难度:2   描述 A new e-mail service "Berlandesk&q ...

  5. c题 Registration system

    Description A new e-mail service "Berlandesk" is going to be opened in Berland in the near ...

  6. CodeForces-4C Registration system

    // Registration system.cpp : 此文件包含 "main" 函数.程序执行将在此处开始并结束. // #include <iostream> # ...

  7. nyoj Registration system

    Registration system 时间限制:1000 ms  |  内存限制:65535 KB 难度:2   描述 A new e-mail service "Berlandesk&q ...

  8. Registration system

    Registration system 时间限制:1000 ms  |  内存限制:65535 KB 难度:2 描写叙述 A new e-mail service "Berlandesk&q ...

  9. nyoj 911 Registration system(map)

    Registration system 时间限制:1000 ms  |  内存限制:65535 KB 难度:2   描述 A new e-mail service "Berlandesk&q ...

随机推荐

  1. 离线安装vscode vsix插件

    VS代码扩展市场 通过扩展增强Visual Studio代码的强大功能 https://marketplace.visualstudio.com/vscode Visual Studio Code包含 ...

  2. python_3_coding

    # -*- coding:utf-8 -*- 也可以换成下划线 用于声明文件编码,python3本身就是utf-8类型,不用声明 name="你好,世界"#utf-8格式能显示汉字 ...

  3. AngularJS 外部文件中的控制器

    在大型的应用程序中,通常是把控制器存储在外部的文件中. <!DOCTYPE html><html><head><meta http-equiv="C ...

  4. 1、React-Native的基础入门

    React Native (简称RN)是Facebook于2015年4月开源的跨平台移动应用开发框架,是Facebook早先开源的JS框架 React 在原生移动应用平台的衍生产物,目前支持iOS和安 ...

  5. lintcode_397_最长上升连续子序列

    最长上升连续子序列   描述 笔记 数据 评测 给定一个整数数组(下标从 0 到 n-1, n 表示整个数组的规模),请找出该数组中的最长上升连续子序列.(最长上升连续子序列可以定义为从右到左或从左到 ...

  6. 远程桌面连接失败,提示CredSSP加密Oracel修正问题解决

    今天远程桌面的时候失败了,出现以下提示 于是上网找解决办法,经过测试,该方法是可行的. 首先,在控制台中输入regedit,打开注册表

  7. Oracle客户端安装配置

    Oracle客户端安装配置.绿色版Oracle客户端配置使用PLSQL 安装Oracle客户端 准备工作,首先下载对应Oracle版本的客户端,这个可以去Oracle官网下载,加压完目录如下: 点击s ...

  8. 面向对象特性 - php

    1.类的字段调用格式 公用字段   类内调用 $this->字段名  类外调用 $对象名->字段名 静态  类内调用 self::$字段名   类外调用 类名::$字段名 常量 类内调用 ...

  9. emplace_back

    c++11 的 list deque 和 vector 增加了emplace_back函数,相对于push_back函数,它减少了一次类的构造,因此效率更高,推荐使用. #include <li ...

  10. 使用python制作神经网络——搭建框架

    一.神经网络的大体结构可分为三个函数,分别如下: 1.初始化函数 设定输入层节点,隐藏层节点和输出层节点的数量. 2.训练 学习给定训练集样本后,优化权重. 3.查询 给定输入,从输出节点给出答案 所 ...