24、编写一个函数void replace（char *str1,char *str2,int i,int j),将字符串中str1中的第i个字符开始到j个字符结束的位置替换为str2.

/*
编写一个函数void replace（char *str1,char *str2,int i,int j),将字符串中str1中的第i个字符开始到j个字符结束的位置替换为str2.
 */

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int strLen(char *str)
{
    char *p = NULL;
    p = str;
    int strLen = 0;
    while(*p != '\0')
    {
        strLen++;
        p++;
    }
    return strLen;
}

int replace(char *str1,char *str2,int i,int j)
{
    int distance = j - i + 1;//要替代的字符数
    int str2Len = strLen(str2);
    if(distance != str2Len)
        return 0;
    int currentIndex = i - 1;
    int endIndex = j - 1;
    char *p = str2;
    while(*p != '\0' && currentIndex <= endIndex)
    {
        *(str1 + currentIndex) = *p;
        ++currentIndex;
        ++p;
    }

    return 1;
}

int main()
{
    char str1[10] = "abcdefghi";
    char str2[10] = "123";
    int start,end;
    scanf("%d%d", &start, &end);
    replace(str1,str2,start,end);
    printf("%s", str1);
    return 0;
}