基于xml配置springmvc

controller关键代码

public class MenuController extends MultiActionController

方法：

public ModelAndView list(HttpServletRequest request,
          HttpServletResponse response)
	{
	  CoreMenuQuery query = new CoreMenuQuery();
	  List<CoreMenu> list = coreMenuService.find(query);
		return new ModelAndView("index");
	}

一定要

HttpServletRequest request,
          HttpServletResponse response

xml配置

<bean id="paraMethodResolver"
        class="org.springframework.web.servlet.mvc.multiaction.ParameterMethodNameResolver">
        <property name="paramName" value="action"/>
        <property name="defaultMethodName" value="list"/>
    </bean>
   	<!-- 页面View层基本信息设定 -->
    <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/>
		<property name="prefix" value="/WEB-INF/content/"/>
		<property name="suffix" value=".jsp"/>
    </bean>
	<!-- servlet映射列表,所有控制层Controller的servlet在这里定义 -->
    <bean id="urlMapping"
          class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
        <property name="mappings">
            <props>
                <prop key="/admin/index.htm">adminController</prop>
                <prop key="/menu/index.htm">adminController</prop>
            </props>
        </property>
    </bean>

	<bean id="adminController" class="com.core.action.AdminController">
	</bean>  

访问方式类似

http://localhost:8080/BaseS2I/menu/index.htm?action=list

action来自

<property name="paramName" value="action"/>