queryURLParams

let url = 'http://www.douqu.com/index.html?name1=val1&name2=val2';
//1.提取问号后的字符

let asktext = url.substring(url.indexOf('?')+1,url.length);

//2.后面值的处理

let askary = asktext.split('&');
askary.forEach((item)=>{
       let n = item.split('=');
       let key = n[0];
       let value = n[1];
       result[key] = value;
});
console.log(result);

优化方案，进行函数封装，考虑多种情况

//考虑有无哈希值与问号的存在
/*
  @params:url[string]
  @return:[object]包含参数和哈希信息的对象
*/
function queryURLParams(url){
    let askIn = url.indexOf('?');
    let wellIn = url.indexOf('#');
    let welltext = '';
    let asktext = '';
//#不存在,?存在时所做的事,并获取将要处理的字符片段
    wellIn === -1?wellIn=url.length : wellIn;
    askIn >= 0?asktext = url.substring(askIn+1,wellIn) : null;
    welltext = url.substring(wellIn+1);

//处理信息
   let result = {};
   welltext!=='''?result['hash'] = well : null;
   if(asktext!==""){
   let ary = asktext.split('&');
   ary.forEach((item=>{
       let n = item.split('=');
       let key = n[0];
       let value = n[1];
       result[key] = value;
    }));
   }
   return result;
}

正则方式实现

function queryURLParams(){
  let result = {};
  reg1 = /([^?=&#]+)=([^?=&#]+)/g
  reg2 = /#([^?=&#]+)/g
  url.replace(reg1,(n,x,y)=>result[x]=y);
  url.replace(reg2,(n,x)=>result['hash']=x);
  return result;
}
//正则的强大由此可见